Equipotential surfaces (& why they are perpendicular to field) | Electric potential | Khan Academy
Вставка
- Опубліковано 7 жов 2024
- Equipotential surfaces have equal potentials everywhere on them. For stronger fields, equipotential surfaces are closer to each other! These equipotential surfaces are always perpendicular to the electric field direction, at every point.
Khan Academy is a nonprofit organization with the mission of providing a free, world-class education for anyone, anywhere. We offer quizzes, questions, instructional videos, and articles on a range of academic subjects, including math, biology, chemistry, physics, history, economics, finance, grammar, preschool learning, and more. We provide teachers with tools and data so they can help their students develop the skills, habits, and mindsets for success in school and beyond. Khan Academy has been translated into dozens of languages, and 15 million people around the globe learn on Khan Academy every month. As a 501(c)(3) nonprofit organization, we would love your help!
Donate here: www.khanacadem...
Created by Mahesh Shenoy
Getting knowledge from a trusted source makes studies very easy
You got into my mind... That's exactly what I was gonna say.. ❤
Dear mahesh sir
I wanna share something, i am from Nepal
I am preparing for medical entrance
I read all topics from institute there but while solving the problems i was being dumb, just using formulas, searched someone who could really give feel, found you, thank you so much for the videos and the gauss law lectures were just lit and the interactive section in the website, loved it, hehe i have aced it
I know it's difficult to make videos but if possible, please sir, make videos 😁 covering the topics faster
Much love
Wow, thanks for sharing! Made my day :). Yes, will continue to make more videos this year :)
@@KhanAcademyIndiaEnglish please sir make videos on magnetism as soon as possible
@@KhanAcademyIndiaEnglish hello sir i hope you read this message is you read . I just wanted to tell you make a learning a lot easier and thanks for teaching us for free. I request that you make mega shots of class 12 chapters pls
Good show 😄👍
Oh my god! I was almost on the verge of crying because i have to finish a lot of my portion in a very short time because i couldnt study during covid. All the other videos on youtube are so long and they barely manage to explain things that i was looking for. Your videos are so precise and they absolutely make me understand every single concept so vividly. This video really gave me some hope that i can maybe figure this out. Thank you so much.
This sir is AMAZING ! ig India has so much knowledged that right now where theve reached is amazing and appreciateable !
I know that you'll probably never read this, but I wanted to thank you nevertheless because I searched for a good explanation for a long time and this is by far the best explanaition that I got. Thank you very much!
He really knows how to teach students 🤟
I might as well say I love you! The whole universe is making physics easy for me this year, Thanks a lot God and thanks to you!
Mahesh sir! you are amazing. I'm Ransira from Sri Lanka. I am getting ready for my advanced-level examination. I found it quite difficult to comprehend this concept. Your contribution to my understanding of this phenomenon is graceful. Thank you a lot. Best regards, ❤❤
Everytime when I study Physics I have the assurance that Mahesh Sir is there to lift me up when I am down.
Besides the lesson, I'm mesmerised by his beautiful handwriting
Bestest explanation ever
Thank you... It's really helpful 🙏🙏
Thank you sir, I had this question for a long time. Finally I got the answer…😊😊😊
1 ) becouse of redius the equipotential surface is perpandicular
2 ) becouse of strength of electric field the line of force is further and father away from each other
3 ) supporting at every point is same or equal is the definition of equipotential surface
Am i right ????????????????????????
You made this concept super easy.
Thank you sir!!!!
Beautiful visualization. Thank you, sir.
Ohh my god.... ❤️
Man where I can personally connect with you the way you teach no one does...
I literally in love with the way of your teaching 💕🙏🏼
Nice explained sir which helped me to solve my doubts
I have a theory y we equipotential surface are perpendicular to field. Imagine a point charge . So, if equipotential surface is not sphere and some other shape , the angle at most point with respect to electric field varies . So,if field varies then the potential also varies place to place ( bcoz , force by field varies . So, velocity of charge varies. So, kinetic energy varies .so, potential also varies) . Just my theory not sure its crct or not
Yeah it's true infact you said the same thing
Thank you sir 😊
POV: u have a physics exam tomorrow and Khan Academy help you to understand the complex concept that teacher couldn't explain it well
We want more videos about equipotential surface.
I appreciate such wonderfull content 💜
Mahesh you are rocking man... I'm standing like a good one as a teacher for physics because of you...more thankfull...to you..rop your mail
God Bless Sir 🌺
Very nice explanation. Take love from Bangladesh.
Damn this is the exact answer I was searching for
Explanation of concept justsuperb👌
Broo I love u 😮💨💗 crystal clear concepts
Thank you for this video 👍🏼
Thank youuuuu sirrrrrrrrr,radhe radheshyam seh miladeee,jai shreeeeeekrishnnnnnnn❤
Clear explanation
Superb sir.......
Superb
In the last 3 qns you asked, can someone or you... explain the answer please?
We want more physics conceptual videos
sir your voice is very very very sweet
thank you sir
Thank youuuuuuuuuu!🙏🏼
Superb❤
8:58
The equipotency is broken there
Some where more somewhere less
That's why there are not perpendiculat
Also would it be safe to say that if field lines weren't perpendicular to equipotential lines then there would be a basis vecto parallel or tangent to the potential surface that would produce work therefore change the potential energy of the surface hence making it not equipotential which by definition to remain equipotential requires perpendicular field lines...
Nice
Love from Pakistan ❤
You helped me better than my Physics teacher, thank you!!
What I thought is ..say those parallel plates wont be parallel but at some angle inclined from horizontal... simply tilted than all the point at that surface wont be at the same distance from the source due to which E.dr ..will change that is potential will change but as it is a equipotential surface it should not change ...😊..the equipotential surface has to be perpendicular to the field
Thanks dad
Daddy 😳
Which application are you using in making this video ...Plzzz plzzzz answer
Summary Of The Video
*Equipotential Surface*
* *Definition* - Surface at which potential at every point is equal.
*Equipotential Surface By A Single Point Charge*
* A Single point charge creates a spherical equipotential surfaces.
* We can draw as many equipotential surfaces as we want.
* Where Electric Field is Strong equipotential surface are close to each other.
* As we go far away equipotential surface go farther.
*Equipotential Surface Created By A Infinite Plane Sheet*
* In this case we get a plane equipotential surface.
* Also In this case equipotential surfaces are equidistant from each other because here Electric field created by plane sheet is uniform.
*Properties Of Equipotential Surface*
* Electric field is always normal to the equipotential surface.
* When we move a test charge in equipotential surfaces from one point to another we do zero work.
* Two equipotential surface never intersect.
Thank you!! 💅🏼
Why field lines are perpendicular to equipotential surface
Why the equipotential lines are parallel to each other and to the plates?
3226 O'Connell Cape
Why in that equipotential surface that electric potential decrease in opposite direction of feild lines
9:24 what about the work we would do to move that charge?
That is not along the equi-potential surface... The qns we come across are either telling us to move the charge away or towards the source charge which ends up not being zero... If it is along the equi-potential surface, it'll be zero
although, technically they are parallel no?
Sir i am really surprised about your answer after telling reason is perpendicular work done really shocking 🧐🧐
9:02
Sir what about the force we applied to move the test charge in the equipotential surface.
Hi! The answer to your question is that only the work done BY THE FIELD is zero. If we were to calculate the work that WE do on the charge, it wouldn't be zero.
👍
👍👍..
Sir please make hindi lecture videos of 12th class physics
I love how this guy is trying his best to fake his accent