Multiplicity (omega) is not a statement about a particular microstate, but one concerning the number of microstates belonging to a particular macrostate. For example, if you flip a coin three times, the outcome 'HHT' is a microstate corresponding to the macrostate '2 Heads'. The multiplicity of the '2 heads' macrostate is 3 as we can get 2 heads by {HHT, HTH, THH}.
+Sachin Natesh - I agree - He keeps saying "microstate" when he means "macrostate". A macrostate is what you actually can see - variations in temperature, density, pressure, etc. but not what each particle is doing. When you think about what each particle is doing, that's a microstate, and there can be many microstates which give you the same macrostate. There is no "most probable microstate". All microstates are equally likely. There is a "most probable macrostate" - the equilibrium macrostate. It turns out that almost all the microstates give you the equilibrium macrostate. The system is jumping around from microstate to microstate, but practically every jump it makes is to another equilibrium microstate and when you actually make a macro-measurement, it always looks the same.
Dr. Haridoss, thank you very much for your teaching. I spent hours in Max Born's version re Maxwell Boltzmann distribution, but your explanation is way clearer and easy to understand. Absolutely brilliant.
I think what he wanted to say was that Omega is the number of ways (number of micro-states) of obtaining a given macro-state. And that macrostate that encompasses the greatest number of microstates is the maximizer of Omega.
What an outstanding professor/teacher!!!! I'm always looking for how and why they come at these famous equations and this video is wonderfuly explained. Only one note, at 48:50 how did they find that beta = 1/kBT?
Beta is part of exp(-beta.epsilon) with epsilon being some level of energy; like is shown here: 48:36. Because the term in parentheses must be dimensionless beta must have a unit of energy. The product kB . T (from the ideal gas law) gives you that unit.
can you tell me why boltzman used n!/n1!n2!..... whose particles are partially indistinguishable in group by group, while n^k perfectly treats the particles distinguishable.
@ 11:36 The Boltzmann-distribution is based on classical physics, in which energy is continuous (= no discrete energylevels). Here a fixed number of energylevels is only convenient from a mathemical perspective. @ 50:06 This is NOT the Maxwell-Boltzmann distribution. It is the Boltzmann-distribution!
κοιτα θα ειμαι ειλικρινης , πολυ βοηθητικα ολα τα βιντεο σας και μπραβο σας αλλαααααα δυστηχως η προφορα των αγγλικων σας ειναι ανυποφορα κουραστικη ποποοοοοοο
delta(ni) is like the dx part of the differentiation, f'(x) = (something) so dy/dx = (something) dy = dx(something) here dy = delta(Omega) dx = delta(ni) it's not delta actually, its del
beautifully explained! Some of the professors at IIT are simply outstanding teachers.
except that he is explaining the Omega absolutely wrong
@@alis5893 So where is your explanation???
@@alis5893 how? Here Omega is the no. Of ways of particles in a microstate and not not accessible state.
@@ishwartanwar8983 ok . I think I got confused over the symbols
Multiplicity (omega) is not a statement about a particular microstate, but one concerning the number of microstates belonging to a particular macrostate. For example, if you flip a coin three times, the outcome 'HHT' is a microstate corresponding to the macrostate '2 Heads'. The multiplicity of the '2 heads' macrostate is 3 as we can get 2 heads by {HHT, HTH, THH}.
+Sachin Natesh - I agree - He keeps saying "microstate" when he means "macrostate". A macrostate is what you actually can see - variations in temperature, density, pressure, etc. but not what each particle is doing. When you think about what each particle is doing, that's a microstate, and there can be many microstates which give you the same macrostate. There is no "most probable microstate". All microstates are equally likely. There is a "most probable macrostate" - the equilibrium macrostate. It turns out that almost all the microstates give you the equilibrium macrostate. The system is jumping around from microstate to microstate, but practically every jump it makes is to another equilibrium microstate and when you actually make a macro-measurement, it always looks the same.
thanks for clarifying
@@paulreiser816 awesome explanation man
@@anonymous-hz1mf thanks for further explanation
@@anonymous-hz1mf Thanks brother:)
Beautifully explained. Cleared all the doubts I had ! Always a fan of NPTEL.
Dr. Haridoss, thank you very much for your teaching. I spent hours in Max Born's version re Maxwell Boltzmann distribution, but your explanation is way clearer and easy to understand. Absolutely brilliant.
This is the best lecture I've come accross so far!
Haven't seen any of his other videos, but after this one, I think I should. VERY helpful. Thank you!
I think what he wanted to say was that Omega is the number of ways (number of micro-states) of obtaining a given macro-state. And that macrostate that encompasses the greatest number of microstates is the maximizer of Omega.
a best source for better explanation of this theory...
What an outstanding professor/teacher!!!! I'm always looking for how and why they come at these famous equations and this video is wonderfuly explained. Only one note, at 48:50 how did they find that beta = 1/kBT?
Beta is part of exp(-beta.epsilon) with epsilon being some level of energy; like is shown here: 48:36. Because the term in parentheses must be dimensionless beta must have a unit of energy. The product kB . T (from the ideal gas law) gives you that unit.
Understood much better and easily sir. Thankyou alot.
Thank you Sir ,can you providea video about Nernst heat theorem & third law of thermodynamic ..? It will may help me a lot .
This is very good. I just wished you had showed some examples.
if the quality of video will be increased it should be more great. very nice video lecture sir. thank you so much
can you tell me why boltzman used n!/n1!n2!..... whose particles are partially indistinguishable in group by group, while n^k perfectly treats the particles distinguishable.
Watching from Nigeria, very interested lecture, thank you sir
Very good explanation of Maxwell boltzmann statistics
@ 11:36 The Boltzmann-distribution is based on classical physics, in which energy is continuous (= no discrete energylevels). Here a fixed number of energylevels is only convenient from a mathemical perspective. @ 50:06 This is NOT the Maxwell-Boltzmann distribution. It is the Boltzmann-distribution!
Start loving science again
Amazing amazing....thanks a lot Sir 🙏🙏🙏
Bravo, sir!
But, how did you take "beta" as 1/KbT
Its a formula
Sir plz tell me where can I find the video lectures of optics for b.sc
Optoelectronics nptel by IIT Delhi prof.Dr. shony
Thanks for the explanation
Helped Me Lot To Clear My Concept Thanx Great Work :)
Thank's for your explanation :))
The best professor!
plz explain interpretation of partition function: translation,rotational,vibrational and electronic partition functions.
BSc physics course.. Ri8??.. I want the same things... Lol... Have u found all these??
YOU NEED TO CORRECT YOUR EXPLANATION OF OMEGA... Students will get confused. CORRECT THIS
can you explain?
Best thing in internet!
Sir what is mean by alpha nd beta ??
Shotly
κοιτα θα ειμαι ειλικρινης , πολυ βοηθητικα ολα τα βιντεο σας και μπραβο σας
αλλαααααα δυστηχως η προφορα των αγγλικων σας ειναι ανυποφορα κουραστικη ποποοοοοοο
outstanding sir
Thank You Sir
Link for the complete lecture series plzzz
what an amazing lecture ... really well explained
how can we take delta(ni) common from 1st expression ?
delta(ni) is like the dx part of the differentiation,
f'(x) = (something)
so
dy/dx = (something)
dy = dx(something)
here dy = delta(Omega)
dx = delta(ni)
it's not delta actually, its del
Is it for the expression for velocities for ideal gas ????
Noo.....we can derive "Maxwell velocity distribution" using this "Maxwell boltzmann statistics "
Wonderful ❣️
Very good teacher
U give us more videos sir
Thanks.
Too good excellent
Absolutely brilliant👍🏻👍🏻
What about degeneracy
When the state of a system has more than one energy-value, this state is called degenerate.
Nice.
Thanks sir
are you wearing slippers ? do you have a lost brother ?
Are you wearing nothing? Do you have a lost family?
Sir please Hindi me lectures dijiye..
not bad mmm
sound quality is very poor
sound quality is very poor.. cudnt understand anything
sound quality is very poor.. cudnt understand anything
So, you better watch other lecture series!