Hello Ms. Havrot! Your videos have been very helpful to me. My math mark has increased by 11% after watching your videos. So, can you please do question 15 on page 263? Thanks you, once again!
Sure! I can help you with that. First thing you need to do is figure out how much time has passed from 1990 to 2005 (15 years) Now make your equation using initial population x (1 +growth rate) to the power of 15 = 12,500 so we would write: 8400 ( 1 + n) ^15 = 12,500 now simplify by divide both sides by 8400 and take the 15th root of the both sides (which simply removes the brackets on the lhs (1+n)^15 = 12,500/8,400 (1+n)^15 = 125/84 1+n = 15th root of 125/84 1 + n = 1.0267 n= 0.0267 or approx 2.7% AND ... you're welcome!!
My pleasure! Could you tell me if you are getting my replies? I think maybe you might have your settings on "no reply"? It's okay with me, just wondering in case you ask a question and you don't think I am answering you.
When you are doing a question like half life or a doubling period you need to find how many times a substance has halved or doubled. So if I said something doubles every 2 hours and a day has passed and I asked how much you have after one day you would need to find out how many times it has doubled. So the exponent becomes 24/2 so I can tell how many times it doubled.
Hi ms, im kinda confused. how would you write the mapping rule when theres a change in your b value? for example, in the second question u did, (y=1/2^x), what would the mapping rule be? thanks!
When you change the b value you are changing the function. That means that you are graphing a unique function that in fact has not undergone any transformations. The parent function is y = (1/2 )^x. From there you could apply a transformation to that parent function. For example y = 2(1/2)^x + 3. Now you have a transformation of the parent function and you would use the points that we have graphed and apply the mapping rule which would be (x,y) -> (x, 2y + 3). Does that help?
@@mshavrotscanadianuniversit6234 yea sure. so for example, at 6:56, you show use how to do a question where the number of cells X2, however, you did not do plus on and just kept the base as 2. however, at 14:57, you do i +1. my question is how do u know when to add by one?
@MD_2k23 The first question is doubling … so if something doubles you are multiplying by 2 ^n where n is the number of times it will double. The second question you are referring to has to do with compound interest. If I asked you how much you paid for a pair of jeans that cost, say $100 plus tax, you know that the answer is not $15 (given that the tax is 15%). In order to find the final price I have to multiply by 1.15 … $100( 1+ .15) = $115.00. So you multiply times 1 + the interest rate as a decimal.
For 8b). Set the left side to 24, which is double 12, then divide by 12 so you get 2 = 1.025^n Then you can use trial and error on your calculator plugging in values for n 8c) works in a similar way except now you set the left side to 8 then divide by 12 You will have to use a negative n this time as it was in the past. I get 28 for b and -16.4 for c
If Earth was filled with people like you, we would be at Mars by now. What a lovely lady ☺
Awww what a sweet comment ❤️
Hello Ms. Havrot! Your videos have been very helpful to me. My math mark has increased by 11% after watching your videos. So, can you please do question 15 on page 263? Thanks you, once again!
Sure! I can help you with that.
First thing you need to do is figure out how much time has passed from 1990 to 2005 (15 years)
Now make your equation using
initial population x (1 +growth rate) to the power of 15 = 12,500
so we would write:
8400 ( 1 + n) ^15 = 12,500
now simplify by divide both sides by 8400 and take the 15th root of the both sides (which simply removes the brackets on the lhs
(1+n)^15 = 12,500/8,400
(1+n)^15 = 125/84
1+n = 15th root of 125/84
1 + n = 1.0267
n= 0.0267 or approx 2.7%
AND ... you're welcome!!
Thank you for this!
My pleasure! Could you tell me if you are getting my replies? I think maybe you might have your settings on "no reply"? It's okay with me, just wondering in case you ask a question and you don't think I am answering you.
Why for some questions is the exponent a fraction but for others it's just t?
When you are doing a question like half life or a doubling period you need to find how many times a substance has halved or doubled. So if I said something doubles every 2 hours and a day has passed and I asked how much you have after one day you would need to find out how many times it has doubled. So the exponent becomes 24/2 so I can tell how many times it doubled.
Hi ms, im kinda confused.
how would you write the mapping rule when theres a change in your b value?
for example, in the second question u did, (y=1/2^x), what would the mapping rule be?
thanks!
When you change the b value you are changing the function. That means that you are graphing a unique function that in fact has not undergone any transformations. The parent function is y = (1/2 )^x. From there you could apply a transformation to that parent function.
For example y = 2(1/2)^x + 3. Now you have a transformation of the parent function and you would use the points that we have graphed and apply the mapping rule which would be (x,y) -> (x, 2y + 3). Does that help?
@@mshavrotscanadianuniversit6234I think i understand.
so would 1/2^x become the new “parent function”?
That’s correct 😊
@@mshavrotscanadianuniversit6234 Thank you so much!
Do you mind doing pg 210 #4? Thank you!
I went onto the online textbook and couldn't find the question that you are asking about. Could you please check the section and page number again?
Hi Ms Havrot, your videos have been really helping me lately. For this lesson would you mind doing page 261 question 3?
Here you go. Let me know if you need any further explanation.
mshavrot.pbworks.com/f/p%20261%20%233.pdf
why do we add or subtract one from all other questions except the cell one? a bit confused.
I’m not sure what you mean. Could you give me some time cues on the video?
@@mshavrotscanadianuniversit6234 yea sure. so for example, at 6:56, you show use how to do a question where the number of cells X2, however, you did not do plus on and just kept the base as 2. however, at 14:57, you do i +1. my question is how do u know when to add by one?
@MD_2k23 The first question is doubling … so if something doubles you are multiplying by 2 ^n where n is the number of times it will double. The second question you are referring to has to do with compound interest. If I asked you how much you paid for a pair of jeans that cost, say $100 plus tax, you know that the answer is not $15 (given that the tax is 15%). In order to find the final price I have to multiply by 1.15 … $100( 1+ .15) = $115.00. So you multiply times 1 + the interest rate as a decimal.
Can you please explain question 8 part b and c Pg- 262 ? I don't know how to solve for n ?
For 8b). Set the left side to 24, which is double 12, then divide by 12 so you get 2 = 1.025^n
Then you can use trial and error on your calculator plugging in values for n
8c) works in a similar way except now you set the left side to 8 then divide by 12 You will have to use a negative n this time as it was in the past.
I get 28 for b and -16.4 for c
@@mshavrotscanadianuniversit6234 Thanks for this explanation
Ms Havrot can you please do page 263 question 14?
Here you go. Remember that with each wipe you have 1% left so you are multiplying by 0.01 n times. mshavrot.pbworks.com/f/4.7%20%23%2014.pdf