If there is an outlier what are the next steps to determine the outliers and do we have to arrange the data points from lower to highest?. thank you so much!
+Minhua Zhu that was asked as a questoon is the test statistic greater than critical value (is 0.333 greater than 0.466) ..no. in that case "fail to reject" if we got a Test Stat of say 5 - then we would reject
Literally doing my finals watching this video right now, helped a lot ty so much!
Perfect for Irish chemometric student that haven't a notion what they're at! Thank you!
If there is an outlier what are the next steps to determine the outliers
and do we have to arrange the data points from lower to highest?. thank you so much!
Yes!! Thank you so much, this helped me a lot!
Thanks man for the info!
Hi! Thanks for the video. Could u explain why did u compare the 0.3333 with the alfa 0.05 and not the other columns? Thank u
because the question stated there that 'use 5% significant level' which also means that the alpha is 0.05 (conversion of percent to decimal places)
I have seen several Q tables, how do I know which one to use to set the critical value?
what if the outlier is the highest value in the set of numbers?
It doesn't matter
Love from italy,you saved me
this was very helpful . thanks
What about the p-value for the analysis? Could you have a non-significant results even though QTS > QCV?
Beste explanation ever, thanks a lot 🌹🌹🌹
wonderful
what about my data like this 10.3;10.3 10.5;10.5;10.5;10.5;10.5
I am sorry...0.333 larger than 0.466? Than keep the null hypothesis??
+Minhua Zhu that was asked as a questoon is the test statistic greater than critical value (is 0.333 greater than 0.466) ..no.
in that case "fail to reject"
if we got a Test Stat of say 5 - then we would reject
But if you have 10 values the formula should not be (value2-value1)/(last value-1-value1)?
Great thanks!
Hello,if we have data and the potential outlier is larger value not smallest value .How we can calculate the Gab? and can we use Dixon test if N=30
What's important is the gap. When the outlier is bigger than all of the value, you may subtract the suspected outlier from the nearest value.
Hi i want this table 4:01 please