How do you find the midpoint between 2 numbers on the number line, let's say between 4 and 8? You know it is "6", but how do you find it? ((4 + 8) / 2) = 6 (not ((8 - 4) / 2) = 2 )
Hi ! Congratulations for your videos !!!! They are awesome !!! Please, could you show me or make a video of how would be the center of gravity in respect of "x" axis of a parabole F(x) = a(x-h)^2+k with "a" a negative number, and the left root (0,0) ? And calculate the center of gravity of the part from x=(0,0) to (α,0) with α
The equation given in the question tells you. In fact, it's not even about the parabola. It's finding the integral of the upper function ('h' in this case) minus the lower function (which is the parabola in this case).
That is one way to express the equation. You can also express it in terms of y = a x^2 + b x + c where k in the example equals the a here and b and c are zero.
+Karan Kasula Good question. This is often confusing.Try to find the half way point between 6 and 8 on the number line. It is (6 + 8) / 2 = 7 (not (8 - 6) / 2 = 1)Thus y~ = (y + h) / 2
I was have the same question her ... but noticed that you must calculate the y coordinate of the average length of the little slice element which equal to y=(h+y)/2 not the average length which equal y=(h-y)/2 ...... Thanks +Michel van Biezen
Can we say that y~ = (y/2 + kx^2)? Because the centroid of the small rectangle is obviously y/2 and then for the coordinate we add the small piece that is just under the parabola (this is kx^2)
your lectures have helped me get ahead.
thanks a lot for the videos, good sir.
Why is the centroid of the small element dA taken as (h+y)/2 and not (h-kx^2)/2
How do you find the midpoint of 2 numbers on the number line such as 8 and 12? (8 + 12) / 2 = 10 That is how that works in this example as well.
@@MichelvanBiezen Thanks sir 😃 !!
why is that the (~y) is (~y=(h+Kx)/2) ? why not (~y=(h-Kx^2)/2) ? as to find dA is dA=(h-Kx^2)dx > 3:45
How do you find the midpoint between 2 numbers on the number line, let's say between 4 and 8? You know it is "6", but how do you find it? ((4 + 8) / 2) = 6 (not ((8 - 4) / 2) = 2 )
Thanks a lot Sir Michel.
Pls sir i dont get why the midpoint of the strip is (h+y)/2 …wasn’t it supposed to be (h-y)/2??🙏
Take the number line for example. What is the midpoint between 8 and 12? midpoint = (8 + 12) / 2 = 10
Hi ! Congratulations for your videos !!!! They are awesome !!! Please, could you show me or make a video of how would be the center of gravity in respect of "x" axis of a parabole F(x) = a(x-h)^2+k with "a" a negative number, and the left root (0,0) ? And calculate the center of gravity of the part from x=(0,0) to (α,0) with α
Is there a tutorial that you can refer me to,regarding the symmetry staff?
In calculating problems, how can I tell if I am dealing with a parabolic spandrel or semi-parabolic area ?
The equation given in the question tells you. In fact, it's not even about the parabola. It's finding the integral of the upper function ('h' in this case) minus the lower function (which is the parabola in this case).
Can one use the vertical stripes to get the ''x'' coordinates of the center of gravity/centroid??
samuel chuonyo yes , but the distance from the 'y' coordinate to the horizontal stripe is x/2 as the CG of the stripe in the middle
Thank you sir you are a life saver 😄😄
simply a life saver
Sir equation of parabola with vertical axis is equal to x^2=4ky
That is one way to express the equation. You can also express it in terms of y = a x^2 + b x + c where k in the example equals the a here and b and c are zero.
Sua aula é excelente! Amei! Parabéns.
Thank you.
Sir centre of gravity of strip should y+h/2
No, the video is correct. Thanks for checking.
Fabulous! Thank you.
You are welcome. Glad you found it helpful. 🙂
is the value of y~=(h-y)/2 or (h+y)/2
+Karan Kasula Good question. This is often confusing.Try to find the half way point between 6 and 8 on the number line. It is (6 + 8) / 2 = 7 (not (8 - 6) / 2 = 1)Thus y~ = (y + h) / 2
I was have the same question her ... but noticed that you must calculate
the y coordinate of the average length of the little
slice element which equal to y=(h+y)/2
not the average length which equal y=(h-y)/2 ......
Thanks +Michel van Biezen
Can we say that y~ = (y/2 + kx^2)? Because the centroid of the small rectangle is obviously y/2 and then for the coordinate we add the small piece that is just under the parabola (this is kx^2)
I ve tried the integration in my way,why i am getting 7/5 h
I don't know how you integrated it, but the answer in the video is correct.
what about the x coordinate is it equal to zero?if so then how?
+Hitjevi Mujende Yes, because of the symmetry. The object looks exactly the same on both sides of the y-axis. (mirror image)
thanks please do more questions
Great Job!
Your h and k are confusing me. I don't know which is h and which is k.
Tnank you for letting us know. We ill pay closer attention to that.
thnk you so much
learning in 2021! (5/1/2021)
but sir , how bout X. whats the value of X¬
Because of the symmetry, the x coordinate of the CM will be zero.
Your cursive h's look like capital R's.
Muito bom!
Thank you. Glad you liked it. 🙂
كلش،معقد