37-Subquery Using ALL,ANY & EXISTS Operators in SQL | Example | Advance SQL | EXISTS vs IN vs JOINS

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  • Опубліковано 22 лип 2023
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КОМЕНТАРІ • 16

  • @Tech.S7
    @Tech.S7 2 місяці тому +2

    Simple very short ways.... Explained like a pro... Layman can also understand..... Good teaching 🙏

  • @AnandMishra-ou3tv
    @AnandMishra-ou3tv 16 днів тому

    Very helpful videos thnx ❤

  • @attacker21
    @attacker21 6 місяців тому +1

    Really helpful thanks a lot

  • @jamesopoku8049
    @jamesopoku8049 Рік тому +2

    Nice tutorial, keep it up, I really like your videos 👋👋👋

  • @nasimahmed6832
    @nasimahmed6832 3 місяці тому

    great work

  • @aryabhatt5833
    @aryabhatt5833 4 місяці тому

    Thank you ma'am.

  • @sivadurga9204
    @sivadurga9204 3 місяці тому

    Very Precise explanation 👏

  • @jaymahajan3871
    @jaymahajan3871 Рік тому +2

    Good 👌😊👍😊

  • @maheshmenta6078
    @maheshmenta6078 4 місяці тому +1

    simple explanation mam tq

  • @user-qe7pr6rx7k
    @user-qe7pr6rx7k 8 місяців тому +2

    Nice explanation madam

  • @prajuyaragorla8161
    @prajuyaragorla8161 9 місяців тому +1

    how to find deptname =it second highest sal ..like out put empno dname sal deptno

  • @nandhunavrath
    @nandhunavrath 5 місяців тому

    The last query in this video: using 'IN' operator, shouldn't the subquery be - select customers.name
    ie.,: (select customers.name from orders where orders.customer_id = customers.id)
    as orders table doesn't have name column?

  • @SiamData
    @SiamData 3 місяці тому

    for the first example couldn't we just use in operator?

  • @sabari752
    @sabari752 7 місяців тому +1

    100th like is mine