Capacitor filter working in tamil

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  • Опубліковано 12 вер 2024
  • AC to DC Rectifier filter circuits
    Capacitor Filter Working Principle
    A half-wave rectifier with a capacitor-input filter is shown in Below Figure. The filter is simply a capacitor connected from the rectifier output to ground. RL represents the equivalent resistance of a load. We will use the half-wave rectifier to illustrate the basic principle and then expand the concept to full-wave rectification.
    During the positive first quarter-cycle of the input, the diode is forward-biased, allowing the capacitor to charge to within 0.7 V of the input peak, as illustrated in Figure (a). When the input begins to decrease below its peak, as shown in part (b), the capacitor retains its charge and the diode becomes reverse-biased because the cathode is more positive than the anode. During the remaining part of the cycle, the capacitor can discharge only through the load resistance at a rate determined by the RLC time constant, which is normally long compared to the period of the input. The larger the time constant, the less the capacitor will discharge. During the first quarter of the next cycle, as illustrated in part (c), the diode will again become forward-biased when the input voltage exceeds the capacitor voltage by approximately 0.7 V.
    (a) Initial charging of the capacitor (diode is forward-biased) happens only once when power is turned on.
    (b) The capacitor discharges through RL after peak of positive alternation when the diode is reverse-biased. This discharging occurs during the portion of the input voltage indicated by the solid dark blue curve.
    Thank You for watching

КОМЕНТАРІ • 19

  • @nandhitharajesh1442
    @nandhitharajesh1442 2 роки тому +3

    This topic is in my competitive exam syllabus. Thanks for the explanation

  • @VenkatesanS
    @VenkatesanS 3 роки тому

    என்னை மாதிரி கட்டிடவியல் படி த்த ஒருவருக்கு புரிகிற படி சொல்லி இருப்பது மிக மிக அருமை.

  • @Userofindian
    @Userofindian 3 роки тому +1

    மிக அருமையான விளக்கம் ‌ஐயா.

  • @shyamsundarraghu4667
    @shyamsundarraghu4667 2 роки тому +1

    Sir normally, AC would have voltage V0sin(wt) but pulsating DC would have voltage input as |V0sinwt|, since direction alone not changed, then why would the frequency becomes 0, instead of T(time period) it will become T/2(new time period for the pulsating DC ), right?
    Please Answer this Sir.

  • @varadharajan3218
    @varadharajan3218 3 роки тому

    Very useful and super explanation sir. Thanks.

  • @robotics8024
    @robotics8024 3 роки тому

    Best teaching........
    kerala

  • @msiva767
    @msiva767 3 місяці тому

    Sir I want to know about Inductor coil or Inductor load.please share me any link

  • @naguvp6921
    @naguvp6921 3 роки тому

    அருமையானா பதிவு அய்யா 🤝

  • @aswathnarayananr.r.bna20b05
    @aswathnarayananr.r.bna20b05 2 роки тому

    romba nandri sir

  • @maheshvedhaiyan245
    @maheshvedhaiyan245 3 роки тому

    Excellent service

  • @senthilkumar-fj5mx
    @senthilkumar-fj5mx 3 роки тому

    நன்றி ஐயா

  • @dineshbalajim5882
    @dineshbalajim5882 3 роки тому

    sir, how did capacitor works in DC in capacitor filter circuit , plz explain sir..

  • @vishnu3161
    @vishnu3161 3 роки тому

    Sir naan circuit design learn panna start paniruka.. aana epdi athu own ah learn pandrathunu therila.. please give some idea sir..

  • @GokulGokul-iz2to
    @GokulGokul-iz2to 3 роки тому

    Thank u sir

  • @muthupaul8609
    @muthupaul8609 3 роки тому

    நன்றி

  • @rajjeraj7759
    @rajjeraj7759 3 роки тому

    sir Bsc.Electronics and communication padikalama sir eomba naala kekuran please sollunga i am your subscriber sir

    • @EEEVIDS
      @EEEVIDS  3 роки тому +3

      படிக்கலாம்
      எந்த துறையை நீங்கள் எடுத்தாலும் அதில் முழு ஆர்வத்துடன் படித்தால் வெற்றி பெறலாம்.
      நன்றி

  • @rabinmr7316
    @rabinmr7316 3 роки тому

    அய்யா இதன் time constant என்ன?