How to Balance S + HNO3 = H2SO4 + NO2 + H2O (Sulfur + Nitric acid)

In this video we'll balance the equation S + HNO3 = H2SO4 + NO2 + H2O . Visit www.Breslyn.org for video guides on balancing equations and more!
To balance S + HNO3 = H2SO4 + NO2 + H2O you'll need to be sure to count all of atoms on each side of the chemical equation.
Once you know how many of each type of atom you can only change the coefficients (the numbers in front of atoms or compounds) to balance the equation for Sulfur + Nitric acid.
Important tips for balancing chemical equations:
Only change the numbers in front of compounds (the coefficients).
Never change the numbers after atoms (the subscripts).
The number of each atom on both sides of the equation must be the same for the equation to be balanced.
For a complete tutorial on balancing all types of chemical equations, watch my video:
Balancing Equations in 5 Easy Steps: • How to Balance Chemica...
More Practice Balancing: • Balancing Chemical Equ...
Drawing/writing done in InkScape. Screen capture done with Camtasia Studio 4.0. Done on a Dell Dimension laptop computer with a Wacom digital tablet (Bamboo).

[@pari2421]

I was trying this for 2 hrs..and you just explained it in no tym..thnx😄

[@sampasutradhar8177]

Lol.. me too

[@ravilohia4865]

Yes

[@Entertainment__-ub5dm]

Same

[@seethalmarygeorge428]

Sir how can we balance this equation by abcd method

[@anushka7181]

Ty Dr.B it was really hard to understand but you made it easier by explaining it step by step ...😇👨‍⚕️📖👍🏻

[@resiliencechemistrypramods7795]

It's better to assume coefficients of reactants & products as a, b,c,d,e. Balancing means all atoms must be equal in both sides.
Now solve a,b,c,d,e by writing equations.
For S: a=c
For N: b=d
For H: b=2c + 2e
For O: 3b=4c+2d+e
Now assume any one as 1 & solve remaing by using these equations. For simplicity assume a or b =1.
If a=1 then c =1. Now solve b,d & e.
U will get b=d= 6, e= 2

[@qamarsultana9718]

Thnk u soo much Mr. Bresley u are really very talented in chemistry your videos are very easy to understand nd simple I was unable to understand in balancing these equations but seeing your videos I understood very easily 😊

[@MouKarmakar-i3b]

Thanks for the well explained video of the impossible equation ❤❤❤

[@minikb9217]

Thank you so much sir...
(From India)
This helped me a lot in solving so many other equation of the same types.....

[@dianessagomez4545]

Muchas Gracias Profesor, me sirvió mucho.

[@wbreslyn]

De nada!

[@agelnisarupsi3833]

You have made it crystal clear sir....:-),,💎

[@VINODSHARMA-zj3ns]

Thanks a lot.
It was eating my head since 2 days

[@wbreslyn]

Most welcome 😊

[@nasreenbegum3117]

now I can Understand Properly Thank you so much sir ..😊😊And please make a One video one Chemical balance of all elements 😅😅

[@lazarescuandrei747]

Really nice video

[@wbreslyn]

Thanks! --- Dr. B

[@joeipiales9360]

Thank you very much!
I've been trying to solve it all morning and I couldn't find a solution.

[@parminderkaur7856]

Muchas Gracias Professor,me sirvio mucho

[@jobinsebastian5325]

Thanku so much 🎁🎁😄😄it was really very difficult for me until you explained.....

[@titanblazer9112]

Can we do this by partial method

[@sampasutradhar8177]

Thank you so much ... It helped a lot

[@Aarush_K_1]

Why we directly wrote their 6 in hno3 at reactant side?please explain 😊😊

[@danialozano2947]

thanks for this, do you know what kind of reaction is it?

[@amazingtheapple153]

Partial method se v upload karo bhai

[@berlinstelma952]

Thank u sir u helped me understand everything before the day of exam

[@wbreslyn]

All the best on the exam!

[@anudesh13]

Nice video . It helped me to solve my holiday homework

[@wbreslyn]

Glad I could help!

[@bilalansari8614]

Thanks sit for this amazing video

[@wbreslyn]

Most welcome!

[@ciberhivemind5239]

Thank you! :D

[@adwijgupta9619]

Thank you So Much SIR.😇

[@8bnilavpanja277]

Thank you so much 👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍

[@lappaswamy2742]

Thank you so much sir

[@sowmyas9158]

Thank you sir

[@wbreslyn]

Welcome!

[@MrVpsvps]

Thank you so much :)

[@wbreslyn]

No problem 😊!

[@balan4774]

hi sir is there a video on how you balance chemical formulae I was on leave when she thought it I can't understand but thankyou for the help

[@wbreslyn]

This might help:
How to Balance Chemical Equations: ua-cam.com/video/zmdxMlb88Fs/v-deo.html
Coefficients & Subscripts: ua-cam.com/video/wGNgY2XoYPs/v-deo.html
Practice Balancing: ua-cam.com/video/Qci7hiBy7EQ/v-deo.html

[@basavarajtarkar6346]

it was very help full for me sir so thankful to you sir :)

[@DalveerSingh-mi3dk]

Thank u so much sir...

[@thanatchaboonkwan4591]

Thank you very much.😁😁

[@wbreslyn]

No problem! --- Dr. B

[@parminderkaur7856]

Thankyou sir you are really brilliant

[@Tg_td89]

Thanks. It really helped.😊

[@wbreslyn]

Glad it helped!

[@IIT24Aspirant]

Thank you so much Dr.B. But can you make a video on solving this same equation with redox or algebraic method please?? And explain that what this redox method is?

[@wbreslyn]

I've not done much on redox but have found this site to do a very good job:
ua-cam.com/video/NjlkXzUmhwA/v-deo.html
They have step by step for the different methods.

[@user-xz5ef1zl9m]

Thank u so much Mr
u helped me a lot in my (H.m) 🥺💗
(from Egypt)

[@wbreslyn]

Happy to help!

[@satwikroy7769]

Thanks a lot Dr.B

[@wbreslyn]

Always welcome!

[@sujataasalkar9893]

Thanks helped me a lot

[@wbreslyn]

Excellent!

[@salehsadeghi7897]

T
hanks a lot DR.B

[@Hwraa.369]

Thx ! Really you are great🤍

[@-12.153]

this just saved me from having a mental breakdown over this equation

[@sudiptahazra6041]

Help full

[@wbreslyn]

Thanks!

[@chunchingtse7618]

I needed to balance S8+HNO3 = H2SO4 + NO2 + H2O in my midterm test. That is also quite difficult to solve.

[@divyaprabha8901]

Thank you

[@wbreslyn]

You are welcome!

[@zainabbharmal5162]

Amazing explanation 👍

[@wbreslyn]

Thank you 🙂

[@zainabbharmal5162]

@@wbreslyn wlcm👍😇

[@user-gg8cp3mo2s]

Thank you so much . Your videos always clear my doubts and make all questions easy

[@wbreslyn]

Glad to hear that

[@shabanarizvi6088]

Please make video on this
P4+HNO3=H3PO4+H2O+NO2

[@wbreslyn]

This is a tough equation to balance! If I have time Ill make a video. For not, take a look at:
www.webqc.org/balance.php?reaction=P4%2BHNO3%3DH3PO4%2BNO2%2BH20

[@sanjaysinghagriculture]

I don't understand in oxygen molecule becauz in the product side O symbols are more se what to do

[@anilchavan8921]

Thanks 🙂

[@wbreslyn]

Welcome 😊

[@rithikasuresh3392]

Thank you soo much you saved me...

[@wbreslyn]

No problem!

[@mithudas5677]

Thank you so much sir by seeing this I have solved my so many problems like this (I'm from India)

[@wbreslyn]

Awesome, happy to help!

[@pravanjanbehera3230]

Very nice sir. impressed 👍 namaskar.

[@wbreslyn]

Awesome!

[@yojanaraut2022]

Thank you so much. This was difficult yet you explained it very properly.

[@wbreslyn]

No problem! --- Dr. B

[@pokemation55]

@@wbreslyn ya sir thanks

[@kemtsdaughter124]

Thanks 🙏

[@wbreslyn]

No problem! --- Dr. B

[@mithubirdcocktaillover5232]

Thanks sirr
From India

[@wbreslyn]

You're welcome!

[@baharmasoudian3116]

At 1:30, how did you come up with the coefficient of 2 for H2O? Just random? Instinct?

[@neetubawa4233]

Bcoz number of O2 on reactant side is even and if it would be multiplied to any of the numbers the result will also be an even number,
But on product side we r having sum = odd number and which need to be converted into an even one so as to ensure a balanced equation, only 1 O atom in H2O need to be converted into even O's (bcoz other are already even but this one is not and hence causing a prblm)
Therefore we will just multiply it by smallest even no. 2 to proceed further for balancing.

[@minikb9217]

@@neetubawa4233 thank you
I had the same question....
And thanks for the ans

[@neetubawa4233]

@@minikb9217 😊❣️

[@jagjit_singh396]

Thanks

[@wbreslyn]

No problem! --- Dr. B

[@plakshabhardwaj7215]

Sir my equation is sulphur+ nitric acid - sulphur dioxide+ nitrogen dioxide+water, please balance it .

[@aakarshita1032]

I always look up to your videos for an easy yet helpful guide... I am definatly going to suggest this channel to my friends! Thank you for this big help 😃

[@wbreslyn]

Awesome, I appreciate it! --- Dr. B

[@sangitashreebhuyan4839]

Can you please do this in partial equation method?

[@wbreslyn]

I'll add it to my list!

[@tuktukkhadgare8623]

Thankyou🥺

[@wbreslyn]

You’re welcome 😊

[@wbreslyn]

You’re welcome 😊

[@unknowngamer1953]

The confusion comes here that why this equation is not balancing if I first try to balance the oxygen by a Fractional coefficient ?

[@ronakgamer1986]

Bhut Sahi

[@moklemakhatun1304]

Ha ha it was amaizing🤩🤩

[@bhawnamehta2261]

Can you please do a video on how to balance redox reactions? I'm struggling doing it a bit. Sorry for the trouble.

[@wbreslyn]

I keep wanting to do a set of videos on redox but haven't had the chance. This is one of the more difficult topics for students in chemistry. In the mean time, this might help:
www.khanacademy.org/science/chemistry/oxidation-reduction/redox-oxidation-reduction/v/oxidation-reduction-or-redox-reactions
--- Dr.B

[@bhawnamehta2261]

Thanks a lot Dr. B

[@scilencesays6210]

Can u make me understand the part that how 0=13??

[@MonuKumar-xq9qm]

On the other product look at carefully h2so4+4no2+2ho now you count how many oxygen reamains in right side equation

[@endothermicexothermic4051]

Is it a reaction really occur?or SO2 will come out rather than H2SO4?

[@meraryescobarhernandez6995]

Thx

[@wbreslyn]

Yw!

[@afreenaktar1234]

Thank you so much but you explained it very nicely

[@wbreslyn]

You are most welcome!
- Dr. B

[@neetachaliha9520]

What reaction is this?

[@wbreslyn]

I'd probably just call it a redox reaction since some of the elements change their oxidation state.
- Dr. B

[@jibanghartimagar4349]

Same but s8 in what is sir

[@bindusingh467]

But how their is in H2O we multiply by 2

[@Code_Builders]

Sir , plz give a short cut tricks,,,,, this is little bit hard

[@wbreslyn]

This is difficult equation to balance! You could use an algebraic method but that takes a while to learn.

[@Code_Builders]

Sir could you guide me through whatsapp ,,, I am in class 10,,,plz sir ....

[@Code_Builders]

Sir could you guide me through whatsapp ,,, I am in class 10,,,plz sir ....

[@Code_Builders]

@@wbreslyn Sir ,plz guide us me and my freinds ,,,, in class 10 .... I will be obliged you to for this.

[@b-zar8912]

Dude, even I'm in Class 10. Best option would be to just memorize it.

[@dappinireddysrinivasareddd528]

If S8 what is the answer

[@afreenkhudsia7223]

Wow!

[@wbreslyn]

Thanks!

[@rupabhattacharjee7099]

It's for you that I have been able to pass in chemistry. My chemistry teacher sucks

[@wbreslyn]

Glad I can help and all the best in chem!

[@khadijamuhammad9459]

S8 formula for sulphur

[@riyagupta5919]

👍👍👍

[@sajidsaikia4735]

Do it in ABCD methode

[@MumtazAli-st5ih]

Arigato osimas

[@parminderkaur7856]

So eligent so beautiful just loooking like a wow

[@sriramululanka8930]

👍

[@theneonyoutuber]

Do it your own

[@ookabokhairallah8312]

خايفه هيا الي تجيني في الامتحان فيها افكار و انا منحبش الافكار

[@Uniqueworld5152]

How oxygen become 13

[@ronakgamer1986]

Yeyeyeeyyeyeyyeyeeyey

[@rakhisingh8573]

Ya it is tough

[@wbreslyn]

Agreed!

[@michaelonyango487]

You are a fast

[@wbreslyn]

Thanks!

[@pranavkulkarni9061]

Who is getting oxidised here

[@neetubawa4233]

Sulphur

[@avikyadav1116]

You have knowledge but you is not genius............

[@princeyadavvishalsirkediwa4599]

that is very simple equation and you take very time so i take you dislike 1 minute question

[@wbreslyn]

No problem!

[@sujit1970dutta]

Thank you sir

[@parnasridatta3419]

Thank you so much sir...

[@wbreslyn]

Most welcome!

[@sudhakar.ksudhakar.k6768]

Thank you

[@wbreslyn]

Welcome!

[@moviefreak7737]

👍👍👍

[@wbreslyn]

Thanks!

[@Squeakyduck5000]

Thank you sir

[@nirajsingh115]

Thank you sir