A Nice Ln Equation

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  • Опубліковано 14 лис 2024

КОМЕНТАРІ • 9

  • @adrianfletcher8963
    @adrianfletcher8963 Місяць тому +2

    Lol I need to stop doing the problems from the thumbnail. I got stuck cause I was like what are we solving? Then again, I should have known that there's 1 equation with 2 unknowns, so it's not like I could have solved for either

  • @forcelifeforce
    @forcelifeforce Місяць тому +1

    @ SyberMath Shorts -- You should put the arguments inside of grouping symbols: ln[(a + b)/3] = [ln(a) + ln(b)]/2.

  • @prollysine
    @prollysine Місяць тому

    ab/(a+b)=e , ab/(a+b)=e^2/e , ab=e^2 , a+b=e , b=(e+/-e*i*V3)/2 , a=(3e+/-e*i*V3)/2 ,

  • @rajeevlochan5499
    @rajeevlochan5499 Місяць тому

    Solve my problem if you are really capable of I guess
    IT IS AS FOLLOWS:
    if x^2+x=1
    then x^7+34/x+1=?

    • @AliAlperYILDIZ-mz6bo
      @AliAlperYILDIZ-mz6bo Місяць тому

      I'm going to call golden ratio = y in this equation.
      putting the -1 to left side and using the quadratic formula we get x = -y or y^(-1)
      Question wants you to answer (x^8 +x +34)/x
      Plug the answers we got in the first equation then you can find the exact value using binomial expression.

    • @AliAlperYILDIZ-mz6bo
      @AliAlperYILDIZ-mz6bo Місяць тому

      Or you can use fibonacci series to find the answer If you know that trick as well.

    • @Anonymous-zp4hb
      @Anonymous-zp4hb Місяць тому

      if xx = 1-x
      then x = (-1 +- sqrt5)/2
      let k be such that:
      kx = x^8 + x + 34
      if f[n] is the nth Fibonacci number, then it's easy to show that:
      (f[n] - f[n+1]x) (1 - x) = f[n+2] - f[n+3]x
      and since x^8 = (1-1x)^4
      and 1 = f[0] = f[1]
      we get x^8 = 13 - 21x
      and so the problem becomes
      k = 47/x - 20
      Plugging in the known values of x we get:
      k = (7 +- 47sqrt[5])/2
      which are approx:
      -49.047597471245057865615581215181
      or
      56.047597471245057865615581215185

    • @danielpraise2146
      @danielpraise2146 Місяць тому

      This is not hard at all