ARRAY PRACTICE PROBLEMS | Must do Array Questions | DSA Problems | GeeksforGeeks
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- Опубліковано 7 лип 2024
- 🚀 Join GeeksforGeeks in our next DSA Course video as we delve into the fascinating world of ARRAY PRACTICE PROBLEMS!
Uncover the secrets of solving well-known array problems that are frequently asked in interviews. We'll not only walk you through the problems but also provide strategic insights on how to approach and master them.
🕵️♂️ Elevate your problem-solving skills and gain a deeper understanding of Arrays and Array Manipulation.
Prepare to conquer your next interview with confidence and finesse by practicing our DSA Problems.
Read More: www.geeksforgeeks.org/top-50-...
💻 Following are the Practice Problems we have discussed in the video (suggest you to try it yourself):
00:00 - Introduction
00:30 - Leaders in an array: practice.geeksforgeeks.org/pr...
02:40 - Sort an array 0s, 1s, and 2s : practice.geeksforgeeks.org/pr...
04:23 - Count More than n/k Occurences: practice.geeksforgeeks.org/pr...
06:25 - Kadane's Algorithm: practice.geeksforgeeks.org/pr...
08:14 - Smallest Positive missing number: practice.geeksforgeeks.org/pr...
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Suggest some more practice question here!
Hey sir, if possible, try to explain implementation of recursion problems with more than 2 recursion calls & explain how to build logic in the first place to write such recursion functions.
Thank you for the suggestion. We will definitely try to make a video on the same. Till then, you can search for the same on: www.geeksforgeeks.org/
Sir where is the code of the problems ur just explaining
Leaders in an array:-
brute force approach:-
my_array = list(map(int, input("Enter comma seperated values").split(",")))
n = len(my_array)
ans = []
for i in range(n):
leader = True
for j in range(i+1, n):
if my_array[j] > my_array[i]:
leader = False
if leader == True:
ans.append(my_array[i])
print(ans)
optimal approach:-
my_array = list(map(int, input("Enter comma separated values").split(",")))
n = len(my_array)
ans = []
maxi = 0
for i in reversed(range(n)):
if my_array[i] >= maxi:
ans.append(my_array[i])
maxi = max(my_array[i], maxi)
ans.reverse()
print(ans)
Sort an array of 0s 1s 2a using DNF Algorithm
my_array = list(map(int, input("Enter space separated elements with 0s 1s 2s").split()))
n = len(my_array)
low = 0
mid = 0
high = n-1
while mid
where can i find solution to these problems?
public static void main (String [] args){
int [] arr={16, 17, 4, 3, 5, 2};
int n= arr.length;
int max= arr[n-1];
System.out.println("Leader of the array is "+ max);
for(int i=n-2;i>=0; i--){
if(arr[i]>max){
max= arr[i];
System.out.println("Leaders of the array "+ max);
}
}
}
thanks@@3dDigitalArtToday
Bhai hacking so jata hai
Bakwaas
@vandnajaiswal3254 If you can't speak well then don't speak anything at all. You don't know how much courage, practice, and hard work it takes to become a mentor in geeks for geeks. If you cannot encourage something good out there, stay quiet and don't speak badly.