I have looked at this circuit many times over many years. But your video is the first description of this circuit that actually allowed me to grasp the interaction between the circuit's components. BRAVO - superb job, AllAmericanFiveRadio! Thank you!
@AllAmericanFiveRadio You're welcome. As an electrical engineer, I've never even seen this circuit! I'm always astonished to learn new circuit configurations. Take care.
Your video is better than all other videos combined on multi-vibrator in You Tube. No one answered the question, how a transistor with negative base bias can act as ON switch. Moreover, your positioning of 22 mF capacitor, and 10K resistor has added a new helpful perspective to the circuit.. You have provided me the right handle, to study the circuit on my work bench in more detail. Thanks
Thank you for posting this. Your video is the only one I could find that explains how a flip flop circuit works. Other videos just tell you how to construct one with no in depth explanation.
Hi AAFR, Rick, Thankyou for the most excellent electronics tutorials on YT. If someone had no experience with electronics, they would probably understand what was said. I watch all I can and take notes on each one. Take care, have fun. C.
Thx all americanradio! I always wanted to know how flip flops work...it's one thing to see how they are built to actually be explained how they work! Thx keep up the awesome videos please!
Thanks mediaguardian Yes thats right on the ground-base voltages. The 10K supplies the + voltage to turn on the transistor. The cap supplies the - voltage to turn off the transistor. If the 10K was changed to a resistor to high it would not turn on the transistor. If to low it would keep the transistor on.
Thanks AndyDaviesByTheSea Thanks Andy, I tried an oscilloscope and a digital meter to show the negative pulse. The scope was to fast and the digital meter would not show the same results each time, the pulse was not long enough. The analog meter worked great for the demo. Regards Rick
Thanks for an excellent explanation of a clever bit of circuitry. I stared at the schematic for a while and couldn't make sense of it, but your blow by blow account of what is happening really made the light-bulb go on in my head, especially with that negative charge in the cap and the surge turning the transistor off when you disconnect the lead shorting the andt ohm resistor.
This is great! I saw something similar to this circuit elsewhere and put it together, it didn't work. Reworked it thinking I did something wrong, nothing. This really helps zero in on things. I wanted to ask, is there a way to do this with 3V? I'm trying to put this on a pin (like a button to wear) and 12V is not really something I can get on a pin. Can things be swapped for lower resistances that it'd still work?
I think a IC circuit may be useful. JK Flip Flop ua-cam.com/video/zo0UR5BgK1M/v-deo.html D Flip Flop Clocked with 555 Timer ua-cam.com/video/l5MM9-rt8b0/v-deo.html Binary Counter Cascading D Flip Flop and 555 clock timer driver ua-cam.com/video/ter5f0UjvHc/v-deo.html Cascade FlipFlop AND Gate Logic Demo ua-cam.com/video/mwkKQ0jYJ8o/v-deo.html IGBT Astable Multivibrator ua-cam.com/video/PnAiAhZH9hw/v-deo.html
@@AllAmericanFiveRadio okay, I'll take a look. I'm trying to avoid ICs since I'm having like 100+ of these made so it can shoot the price up pretty quick.
+only using transistor circuits (OUTC) That is not at all uncommon. Flip Flop circuits are somewhat difficult to get working because both sides have to be balanced. But when you find that balance they work great. I think the next most difficult circuits are RF transmitters and RF oscillators. It is so great to know you got your Flip Flop circuit working! Thanks!
Hi there mate !! (I'm in Australia, and in my mid 60's). This is the 1st time I've seen your stuff.... The SECOND i saw the 'AllAmericanFive' part, it instantly clicked, remembering the ubiquitous standard '5 Valve' super-het radios i used to play around with, and fix. I miss the warm glow of Valves on a workbench !!! I guess you like to keep things 'Old-School', as do I, generally, but lately i've been using computer circuit simulation software for prototyping etc... It has come a long way, especially when it can run continuously in Real Time, and Meter any voltages or currents live, in any part of complex circuits, just with mouse pointing. (Not to mention all component/IC specs/dimensions, with auto track/pcb creation). Great explanations from you, & look forward to going over more of your 'many' posts !! Thanks....
I subscribed due to an earlier video, words cannot express how happy I'm feeling Its my eureka moment every time I watch one of these instructional videos. Thank you in advance and prior to my sub.
Thanks Lachlan Baird-MacKenzie I'm going to experiment building another flip-flop circuit using FET transistors. My thinking right now is it would be easier to build and work better, but it could be just the opposite. Anyway it will be an interesting experiment.
Thanks engmustafa83 The transistors are 2N2222, both about 210 beta. All resistors are 5%. The caps are 10WVDC. Like I said in the video it did take me a little time to get this to work. I had to swop out a few parts to get thinks to match.
@IBreedBassetts9C When the 100 ohm resistor is back in the circuit this produces a voltage drop. The capacitor is charged with out a voltage drop. When the resistor is back in the circuit the voltage drop across the base-emitter junction is high enough to forward bias it, driving the transistor into saturation.
The transistor that is 'off ' gets a positive pulse through the 10K resistor turning it 'on' when the other transistor that was 'on' gets a negative pulse from the 22uf capacitor when the tiger is opened. I drove it with a signal generator
I found a very good PDF on the MC34063A. Google “MC34063A - Step-Up/Down/Inverting Switching Regulators” The PDF will be close to the top of the page. It has descriptions of the chip, the specs, and circuit examples.
everycircuit.com/circuit/4857314209955840 I got it to work on EveryCircuit with a little tweaking. When you first run the simulation bush the button I added near the right capacitor and it works after that.
@hardstyle905 Mostly multi-stage amplifiers considering bandwidth and impedance, signals and systems, electromagnetics... Chances are is that I simply forgot since it was likely a few years back when I learned this.
so im planing on building one of these circuits for my car. ive got 4 coilpacks currently in parallel batch fire. which isnt desirable. they are 4 wire coils with 12v pos, earth, 5v trigger send, and trigger return (tells the ecu fire was successful). i want to make this circuit using 12v to the coilpacks as the source voltage (data input) and instead of a switch, i want to tap into the 5v trigger, and hook it to a mosfet to act as a high speed relay for the switch. in effect, the q and bar q will turn my batch fire into a proper waste fire where coils 1&4 are powered on q and 2&3 powered on q bar. the trigger will fire every 2.67ms at redline, and coil fall and charge is supposedly 1.8ms so that all looks good to me. THE QUESTION: will running 12v (i THINK 6a but i havent put an amp clamp on it) through this type of circuit be possible? im new to digital circuitry and im having trouble figuring out if this will work like a charm, or burn up and die. i have a schematic i can send you as well as all sorts of specs like trigger rate etc anyways, any help would be appreciated!
i watch the breakdown circuit flip flops and learn how it work, is there anyway u can do a breakdown of a MC34063 switch-mode boost converter. The reason for this is how can i built a power surply with an input 3v - 6v and the out of 19v and an ajustable current. What is the max current and lowest current that i can get. " THANK YOU"
@AllAmericanFiveRadio Hi Rick, I’m sure we learn a lot from creating the video’s as it’s only when you have to ‘Prove it’ that you realise some of the little intricacies for yourself, well that’s how it works for me hi hi. Kind Regards ... Andy
Hi, I enjoy your videos and am trying to learn electronics (I am a retired computer scientist). I am trying to figure out the difference in the voltages when the led is lit. Am I to assume the ground-base voltage takes into account the voltage drop across the 100ohm resister whereas the emitter-base voltage doesn't? Also, what is the significance of the 10K resisters in parallel with the caps? Could they be 5K or 20K? Thanks, Jim
Hello , I appreciate your work and explanations of circuits, question..will this flip flop circuit work as an h bridge, similar to an h bridge running in astable mode reversing a dc motor??
The H bridge provides two paths to power, one positive and negative, and the other one negative and positive. This flip-flop circuit does have a path to positive when the light is lit, but the other side is open, no path to the negative side.
I don't understand how the negative voltage pulse is achieved at 4:14 . From my perspective, opening the switch will increase the base to ground voltage from about +0.2V to +1.26V . How does the base voltage drop below 0V ?
I built the same circuit and the only difference is that i used 47uF caps.When i turned it on (using 9v dc) the leds started blinking rythmically (without pressing the switch).And by rythmically i mean that the first led turned on and then it turned off and simultaniusly as the other one turned off the other led turned on and then that led turned off and simultaniusly the first led turned back on and so on.This happens quite fast.(with approx. 0.25s delays).Is it becouse i used lower voltage,larger caps or some other reason?Thanks in advance.
I would try changing some resistors, like the 100 Ohm to 50 Ohms or 200 Ohms. If that does not work try the 10K and so on. Getting flip flop circuits to work can be a challenge.
Great explanation as always! By the way, do you have any simple solutions to the bounce issue you mentioned in the video? I keep having false triggers when I use a slide or button switch on these IC circuits. All my research points to using a Schmit trigger, but that seems to me to be over complicating a simple switch.
Hi, AllAmericanFiveRadio, Congratulations on a great job! Well done! I am just unclear on one thing - when you power up the circuit, why wouldn't both transistors go into conducting state, that is, allow current to pass through CE junction? As far as I can see, when you power up the whole thing, BE junction is immediately forward-biased and thus both transistors should be conducting. Am i missing on something? Many thanks for some kind of clarification
Great working, and simple. NO HORRIBLE BUILDING PROBLEMS....hehehe. Thanks, and by the way, If one tries to find the 22uF cap. just about anywhere on line or Raido Sha.k, one has trouble finding it. Hense; I just know people are building this- this is what computers are made of basically and shows appreciation for computers. :O) in luie, of course of the movements I have been preaching for 27 years I last posted. :O) you don't have to reply to me again, other people do.
Thanks for the idea , i tried on transistor BD679 it worked but its getting hot then i add heat sink it worked little bit longer but again flip flop getting slower,,lets see
Thanks for this video, much appreciated, but I am confused. At 2:12 talking about voltage levels, the right trans is on the left is not, but the left has a ground to base voltage of 1.26 which would seem to be enough bias to turn on the transistor? And another point I don't understand, if the right trans base is getting it's voltage from the left diode side, wouldn't that mean current is going through the left side diode and would cause it to turn on, it has a 12 volt positive bias above it? Obviously I'm missing something here and would greatly appreciate any explanation, thank you
+gw25 For a junction transistor to conduct current between emitter and collector, the emitter and base junction must be biased from about 0.6 to 0.7 V DC, measured between the emitter and base. And this is not the case in either of your questions, that's why the transistor is not conducting. So if the voltages on the emitter and base never exceeds 0.6 to 0.7 V DC the transistor is not conducting.
+AllAmericanFiveRadio < Thank you again good sir. I still have a point of confusion and I guess it's more in the nature of diodes. At 5:25 there is a path from the right diode, through the 470 resistor, then crossing over to the left side of circuit going up the 10K resistor, through the base to emitter junction, and then through the 100 Resistor to ground. So the right diode has a 12 volt source right above it and then a path to ground making a complete circuit. Does it not light up because the 10K resistor limits the current too much to light the diode. B/c currently I have a understanding that diode will conduct, and in the case of an LED light up, when it has more than a .7 (or so) positive bias across it, resistors are just used to drop all the rest of the voltage and limit the current. Thanks again and hopefully I'm not being a pest.
+gw25 In this circuit the transistors have only two states, when they are conducting it is a dead short, when they are not conducting they have infinite ohms. So the side that is conducting shorts out the 12 V DC and the other side cannot see it. When that side stops conducting it is wide open, now the other side can see the 12 V DC because it is no longer shorted out. Keep asking your questions, I can remember the first time when I was trying to figure this out.
+AllAmericanFiveRadio , thanks and I shall. So I believe I understand what you are saying about the transistors. When one is on it allows the 12 V source a path for the LED with only a 470 and 100 resistor to ground allowing for a good deal of current. But here is what I'm still failing to grasp. The right diode is on it is b/c the right transistor is on. And I believe what turns the right transistor on is b/c it has a voltage on the base to emiter junction greater than .7 volts. I believe that voltage source is coming from the left diode (which is currently off) circuit. At 3:56 you clearly show this. So if there is current flowing form the left (off) diode to the base of the right transmitter, why is the left transistor not forward biased enough to turn on. I enterperate you last explanation as when the right transistor is on it is sucking all the current from the voltage source, but as I currently understand things the right transistor is only on b/c of the voltage/current it is getting from the left (off diode) path. I also don't fully understand how the voltage for the ground to base is 1.97 volts on the right side transistor at 3:56. Again if it's voltage comes from the left (off side) then wouldn't the voltage on the right side transistor base be what was left after the 10K resistor. As I currently calculate that would be (11.3/ 470 + 10K + 100) * 10470 = 11.19 voltage droped at the after the right transistor 10K resistor. Thanks again
+gw25 Think the problem you're having is you're not understanding what a transistor does in the circuit. The side that the LED is lit, take the transistor out of the circuit and put in a straight wire from collector to emitter. So now the resistors that are in circuit are the 470 ohm and the 100 ohm to ground. I think this video will help. Transistor, How Does it Work in a Circuit, Demo ua-cam.com/video/vs3zUHdlsYY/v-deo.html
Hola espero que me ayudes , arme dos flip flop y me funciona de maravilla como esta en tu diagrama lo que sucede es que cuando lo conecte a la protoboard presiono el pulsor y el otro flip flop también lo hace , como hago para que no interfiera en al otro circuito en mi proyecto necesitó los dos flip flop alimentados con una batería espero que me ayudes
12 V diode lamps are LEDs. It would have to make sure that the 12 V diode lamps you want to use do not exceed the current limitations of the transistors.
I just built this circuit, but I have an anomaly. I do see the LEDs flip-flopping, however, the "flopped" LED is NOT completely off, that is, it is dimmer than the "flipped" LED, but it is nevertheless on. One thing I did differently is I have a 560 (instead of 470) ohm resistor inline with the LED, and the resistor tied to the power supply instead of the LED, and then the LED is tied to the collector of the transistor. Could this be the reason why the off LED is not off all the way?
+ZillaYT This is not uncommon with flip-flop circuits. There has to be parts on one side that do not match other side. To get a discrete component flip-flop circuit to work properly each part on both sides must be matched. Flip-flop circuits are one of the hardest circuits to get working properly. You have done well to get it to work at all. When I originally built the circuit I swapped out many components until I got everything to match. If you measure the voltages, I would start at the transistors collector, this information can be helpful in determining which part needs to be changed out to match the side that is working properly.
+AllAmericanFiveRadio Here's what I see, all in Volts. Flip means transistor's corresponding LED tied to its collector is on, flop means it's off. Q1 Vcc-GND: Flip, 0.97, Flop, 5.601 Vce: Flip, 0.078, Flop, 4.71 Vbe: Flip, 0.72, Flop, 0.11 Q2 Vcc-GND: Flip, 0.994, Flop, 5,598 Vce: Flip, 0.11, Flop, 4.7 Vbe: Flip, 0.75, Flop, 0.084
+ZillaYT Another troubleshooting technique is to swap parts between each side. When the unwanted result moves you have found the part you need to replace.
At 4.03 are you saying that the capacitor discharges in the base of the transistor and turns to off? Wouldn't a current turn it on? Sorry, my understanding of electronics is still in the early stages. :s
I'm using NPN transistors, and the N and P denote the type of material doping, in this case silicon. The base material is doped P, that means if you put a positive bias on it the transistor will turn on. If you put a negative bias on it it will turn off the transistor.
Positive current at the base of a NPN transistor will turn it on while its there, but negative current will turn it off, Notice that capacitor only gave a very short negative pulse, if the other transistor did not turn on or was not in the circuit this transistor will come back on again when negative pulse ended, Because the other transistor came on and positive current stopped flowing through the base of first transistor it stayed off.
Flip-flop circuits are very balanced circuits. The impedance or resistance at the collector is much higher than at the emitter. When the 22 µF capacitor charges the current charging the capacitor never exceeds the transistors trigger threshold. When the 100 ohm resistor is shorted, this makes the impedance at the emitter even less and that causes the charged 22 µF capacitor to produce a negative pulse on the base of the NPN transistor turning it off. Thanks Sam
The 2n3904 should work just fine. It is important that the parts on both sides of the flip-flop matches close as possible. Because of that they can be a little tricky to build, but once you get them working, they work very well. Good luck.
You can, you may need to lower or eliminate the 470 Ohm resistors. If you want a free running circuit you might try an Astable Multivibrator. IGBT Astable Multivibrator ua-cam.com/video/PnAiAhZH9hw/v-deo.html
@@ShivaShankar-rj4rg Your welcome. One more think I would build with LEDs first. Get the flip flop working than change the circuit. The components on each side must be matched as close as possible.
GOOD CIRCUIT AND WORKS thanks in the name of the slow car sticker movment, part time for appreciation and love, The Box Club, publish on and off media, say so as a "greeting", the Future Consciousness "sin" detection unit (Pro Jahnn and Dunne), write things down, I would have been people's psychiatrist, human robots ( not publishible), and psychic, not contemporary war, Again GOOD CIRCUIT WORKS LIKE A CHARM
Hm. I used NPN. So I read the diagram right. The circuit even oscillates when I press the button continuesly, but it does not switch. Hm... I used C547B transistors and tried to find similar capacitors. Maybe the transistors are not quite right. Can you take a look at them and tell me which properties are important and not-met?
From what I can see about the C547B transistors you are using, they should work as long as they're good working transistors. The transistors I am using are just general purpose 2N2222's. Building a flip-flop circuit can be somewhat of a challenge. The transistors I used I made sure that they have the same Beta, amplification factor. Also all the other components, resistors and capacitors, were chosen as close to being the matched as possible. So another words all the components on one side have the same characteristics as the other side.
I have looked at this circuit many times over many years. But your video is the first description of this circuit that actually allowed me to grasp the interaction between the circuit's components. BRAVO - superb job, AllAmericanFiveRadio! Thank you!
+Allan Fay THANKS!
Thanks god . I thought that I am the only one who didn't understand this circuit principle 😅
I'm finding this video strangely soothing.
Then drink three beers and watch this video.
Superheterodyne AA5 from End to End
ua-cam.com/video/glakoNN4lwA/v-deo.html
Great explanation! This is one of those more difficult parts of electronics to follow but with your one step at a time most everyone can get it.
@AllAmericanFiveRadio You're welcome. As an electrical engineer, I've never even seen this circuit! I'm always astonished to learn new circuit configurations. Take care.
Your video is better than all other videos combined on multi-vibrator in You Tube. No one answered the question, how a transistor with negative base bias can act as ON switch. Moreover, your positioning of 22 mF capacitor, and 10K resistor has added a new helpful perspective to the circuit.. You have provided me the right handle, to study the circuit on my work bench in more detail. Thanks
Thanks and good luck
Thank you for posting this.
Your video is the only one I could find that explains how a flip flop circuit works. Other videos just tell you how to construct one with no in depth explanation.
Thanks and your welcome.
Hi AAFR, Rick, Thankyou for the most excellent electronics tutorials on YT. If someone had no experience with electronics, they would probably understand what was said. I watch all I can and take notes on each one. Take care, have fun. C.
this is the best explanation for this circuit that i have seen. i understand although my english is not good. thank you sir.
Thanks and your welcome.
Thx all americanradio! I always wanted to know how flip flops work...it's one thing to see how they are built to actually be explained how they work! Thx keep up the awesome videos please!
Thanks mediaguardian
Yes thats right on the ground-base voltages. The 10K supplies the + voltage to turn on the transistor. The cap supplies the - voltage to turn off the transistor. If the 10K was changed to a resistor to high it would not turn on the transistor. If to low it would keep the transistor on.
i remember staring at the schematic of this circuit for hours when i was a child trying to figure out how does it work
Thanks AndyDaviesByTheSea
Thanks Andy,
I tried an oscilloscope and a digital meter to show the negative pulse. The scope was to fast and the digital meter would not show the same results each time, the pulse was not long enough. The analog meter worked great for the demo.
Regards
Rick
Thanks for an excellent explanation of a clever bit of circuitry. I stared at the schematic for a while and couldn't make sense of it, but your blow by blow account of what is happening really made the light-bulb go on in my head, especially with that negative charge in the cap and the surge turning the transistor off when you disconnect the lead shorting the andt ohm resistor.
This is great! I saw something similar to this circuit elsewhere and put it together, it didn't work. Reworked it thinking I did something wrong, nothing. This really helps zero in on things.
I wanted to ask, is there a way to do this with 3V? I'm trying to put this on a pin (like a button to wear) and 12V is not really something I can get on a pin. Can things be swapped for lower resistances that it'd still work?
I think a IC circuit may be useful.
JK Flip Flop
ua-cam.com/video/zo0UR5BgK1M/v-deo.html
D Flip Flop Clocked with 555 Timer
ua-cam.com/video/l5MM9-rt8b0/v-deo.html
Binary Counter Cascading D Flip Flop and 555 clock timer driver
ua-cam.com/video/ter5f0UjvHc/v-deo.html
Cascade FlipFlop AND Gate Logic Demo
ua-cam.com/video/mwkKQ0jYJ8o/v-deo.html
IGBT Astable Multivibrator
ua-cam.com/video/PnAiAhZH9hw/v-deo.html
@@AllAmericanFiveRadio okay, I'll take a look. I'm trying to avoid ICs since I'm having like 100+ of these made so it can shoot the price up pretty quick.
Tried your circuit. Works very well thanks alot its brilliant!
I built this circuit and it works well .I had to make a few changes in values to make it .Thanks a lot.
+only using transistor circuits (OUTC)
That is not at all uncommon. Flip Flop circuits are somewhat difficult to get working because both sides have to be balanced. But when you find that balance they work great. I think the next most difficult circuits are RF transmitters and RF oscillators. It is so great to know you got your Flip Flop circuit working! Thanks!
Hi there mate !! (I'm in Australia, and in my mid 60's). This is the 1st time I've seen your stuff....
The SECOND i saw the 'AllAmericanFive' part, it instantly clicked, remembering the ubiquitous standard '5 Valve'
super-het radios i used to play around with, and fix. I miss the warm glow of Valves on a workbench !!!
I guess you like to keep things 'Old-School', as do I, generally, but lately i've been using computer circuit
simulation software for prototyping etc... It has come a long way, especially when it can run continuously
in Real Time, and Meter any voltages or currents live, in any part of complex circuits, just with mouse pointing.
(Not to mention all component/IC specs/dimensions, with auto track/pcb creation).
Great explanations from you, & look forward to going over more of your 'many' posts !! Thanks....
Thanks
I subscribed due to an earlier video, words cannot express how happy I'm feeling Its my eureka moment every time I watch one of these instructional videos. Thank you in advance and prior to my sub.
Thanks Lachlan Baird-MacKenzie
I'm going to experiment building another flip-flop circuit using FET transistors. My thinking right now is it would be easier to build and work better, but it could be just the opposite. Anyway it will be an interesting experiment.
Thanks engmustafa83
The transistors are 2N2222, both about 210 beta. All resistors are 5%. The caps are 10WVDC. Like I said in the video it did take me a little time to get this to work. I had to swop out a few parts to get thinks to match.
@IBreedBassetts9C
When the 100 ohm resistor is back in the circuit this produces a voltage drop. The capacitor is charged with out a voltage drop. When the resistor is back in the circuit the voltage drop across the base-emitter junction is high enough to forward bias it, driving the transistor into saturation.
Google your transistor number and if they are PNP transistors, reverse the battery and reverse the electrolytic capacitors. I used 2N2222
Phenomenal demonstration. You explain things very clearly. Keep it up!
The transistor that is 'off ' gets a positive pulse through the 10K resistor turning it 'on' when the other transistor that was 'on' gets a negative pulse from the 22uf capacitor when the tiger is opened.
I drove it with a signal generator
I found a very good PDF on the MC34063A.
Google “MC34063A - Step-Up/Down/Inverting Switching Regulators”
The PDF will be close to the top of the page. It has descriptions of the chip, the specs, and circuit examples.
Thanks razrbhr8888
The Flip-Flop is one of the basic circuits in a large number of chips.
Very nice explanation of that circuit. Your videos are great.
Spot on explanation. Nothing is left unclear. Thanks for sharing.
Thank you, and your welcome.
everycircuit.com/circuit/4857314209955840 I got it to work on EveryCircuit with a little tweaking. When you first run the simulation bush the button I added near the right capacitor and it works after that.
That is good news.
@hardstyle905 Mostly multi-stage amplifiers considering bandwidth and impedance, signals and systems, electromagnetics...
Chances are is that I simply forgot since it was likely a few years back when I learned this.
so im planing on building one of these circuits for my car. ive got 4 coilpacks currently in parallel batch fire. which isnt desirable. they are 4 wire coils with 12v pos, earth, 5v trigger send, and trigger return (tells the ecu fire was successful).
i want to make this circuit using 12v to the coilpacks as the source voltage (data input) and instead of a switch, i want to tap into the 5v trigger, and hook it to a mosfet to act as a high speed relay for the switch.
in effect, the q and bar q will turn my batch fire into a proper waste fire where coils 1&4 are powered on q and 2&3 powered on q bar.
the trigger will fire every 2.67ms at redline, and coil fall and charge is supposedly 1.8ms so that all looks good to me.
THE QUESTION:
will running 12v (i THINK 6a but i havent put an amp clamp on it) through this type of circuit be possible? im new to digital circuitry and im having trouble figuring out if this will work like a charm, or burn up and die.
i have a schematic i can send you as well as all sorts of specs like trigger rate etc
anyways, any help would be appreciated!
i watch the breakdown circuit flip flops and learn how it work, is there anyway u can do a breakdown of a MC34063 switch-mode boost converter. The reason for this is how can i built a power surply with an input 3v - 6v and the out of 19v and an ajustable current. What is the max current and lowest current that i can get. " THANK YOU"
@AllAmericanFiveRadio
Hi Rick, I’m sure we learn a lot from creating the video’s as it’s only when you have to ‘Prove it’ that you realise some of the little intricacies for yourself, well that’s how it works for me hi hi.
Kind Regards ... Andy
Very useful and easy to understand!Thank you!
Hi,
I enjoy your videos and am trying to learn electronics (I am a retired computer scientist). I am trying to figure out the difference in the voltages when the led is lit. Am I to assume the ground-base voltage takes into account the voltage drop across the 100ohm resister whereas the emitter-base voltage doesn't? Also, what is the significance of the 10K resisters in parallel with the caps? Could they be 5K or 20K?
Thanks,
Jim
nevermind, just had to play around with resistor values for 7 volts
Instead of using two 470 ohm resistors, can we put only one 470 ohm resistor, just right after "+"?
I don't think that will work, but give it a try.
Yeah, you can. As long as the LED is in series with the resistor you are good.
Hello , I appreciate your work and explanations of circuits, question..will this flip flop circuit work as an h bridge, similar to an h bridge running in astable mode reversing a dc motor??
The H bridge provides two paths to power, one positive and negative, and the other one negative and positive. This flip-flop circuit does have a path to positive when the light is lit, but the other side is open, no path to the negative side.
I would have the Flip Flop drive relays or solid state SCRs
Great video. What are the voltages across the 22uF capacitor ?
+Sss Ttt It would be under 12VDC
Thank you for your answer
Thank you, +AllAmericanFiveRadio. You saved my final project in a Electronics Lab.
I'm glad this video helped.
you have a soothing voice
I don't understand how the negative voltage pulse is achieved at 4:14 . From my perspective, opening the switch will increase the base to ground voltage from about +0.2V to +1.26V . How does the base voltage drop below 0V ?
When the switch is closed the capacitor charges. When the switch is open, now there is 100 ohms more in the circuit, the capacitor discharges.
I built the same circuit and the only difference is that i used 47uF caps.When i turned it on (using 9v dc) the leds started blinking rythmically (without pressing the switch).And by rythmically i mean that the first led turned on and then it turned off and simultaniusly as the other one turned off the other led turned on and then that led turned off and simultaniusly the first led turned back on and so on.This happens quite fast.(with approx. 0.25s delays).Is it becouse i used lower voltage,larger caps or some other reason?Thanks in advance.
I would try changing some resistors, like the 100 Ohm to 50 Ohms or 200 Ohms. If that does not work try the 10K and so on. Getting flip flop circuits to work can be a challenge.
Great explanation as always! By the way, do you have any simple solutions to the bounce issue you mentioned in the video? I keep having false triggers when I use a slide or button switch on these IC circuits. All my research points to using a Schmit trigger, but that seems to me to be over complicating a simple switch.
Yes a Schmitt trigger is good. You might try just a transistor to trigger the flip flop. Thanks
@@AllAmericanFiveRadio
Thanks! Found a simple NPN inverter circuit that works great with a button.
Hi, AllAmericanFiveRadio,
Congratulations on a great job! Well done!
I am just unclear on one thing - when you power up the circuit, why wouldn't both transistors go into conducting state, that is, allow current to pass through CE junction? As far as I can see, when you power up the whole thing, BE junction is immediately forward-biased and thus both transistors should be conducting. Am i missing on something?
Many thanks for some kind of clarification
The flip-flop circuit is a balanced matched circuit. However each side is not perfectly balanced, so when the power is applied one side will dominate.
AllAmericanFiveRadio , thank you very much for your answer!
Great working, and simple. NO HORRIBLE BUILDING PROBLEMS....hehehe. Thanks, and by the way, If one tries to find the 22uF cap. just about anywhere on line or Raido Sha.k, one has trouble finding it. Hense; I just know people are building this- this is what computers are made of basically and shows appreciation for computers. :O)
in luie, of course of the movements I have been preaching for 27 years I last posted.
:O)
you don't have to reply to me again, other people do.
good tutorial , if you could explain same flip flop but on 12 vDC ( 21watt) what the values it will be ,, thank you for sharing ,
I'm not sure what you're asking.
thanks , my goal is to use it on car stop light , it is 12v 21WATT , all i need is the values of transistors +resistor and capacitor , Thanks again
i think you can use this circuit with relays ...
Thanks for the idea , i tried on transistor BD679 it worked but its getting hot then i add heat sink it worked little bit longer but again flip flop getting slower,,lets see
Kavindu Gilshan gracias. jose
i got an oscillator instead of a flip flop?
Hello Sir,
Can you please explain preset and clear function of flip flop with the help of transistors? I do not need block diagram.
For preset or reset you bias the transistor on or off
good day. can I use a 3.7v supply for this circuit?
You may need to change the biasing
You may need to change the biasing
What kind of diod did you use please thanks in advance
Any general purpose LED should work. I bought these from Radio Shack.
Thanks John T Schiffer Jr
Is there any way you can automate the switch so it you do not have to open and close it manually?
Yes, do a Search on my channel on “MOSFET Multivibrator Build and Demo”
You can use other transistor types besides MOSFET
Yes, it's called an astable multivibrator and it's a very similar circuit to this.
Thanks. :)
Thanks for this video, much appreciated, but I am confused. At 2:12 talking about voltage levels, the right trans is on the left is not, but the left has a ground to base voltage of 1.26 which would seem to be enough bias to turn on the transistor?
And another point I don't understand, if the right trans base is getting it's voltage from the left diode side, wouldn't that mean current is going through the left side diode and would cause it to turn on, it has a 12 volt positive bias above it? Obviously I'm missing something here and would greatly appreciate any explanation, thank you
+gw25
For a junction transistor to conduct current between emitter and collector, the emitter and base junction must be biased from about 0.6 to 0.7 V DC, measured between the emitter and base. And this is not the case in either of your questions, that's why the transistor is not conducting. So if the voltages on the emitter and base never exceeds 0.6 to 0.7 V DC the transistor is not conducting.
+AllAmericanFiveRadio < Thank you again good sir. I still have a point of confusion and I guess it's more in the nature of diodes. At 5:25 there is a path from the right diode, through the 470 resistor, then crossing over to the left side of circuit going up the 10K resistor, through the base to emitter junction, and then through the 100 Resistor to ground. So the right diode has a 12 volt source right above it and then a path to ground making a complete circuit. Does it not light up because the 10K resistor limits the current too much to light the diode. B/c currently I have a understanding that diode will conduct, and in the case of an LED light up, when it has more than a .7 (or so) positive bias across it, resistors are just used to drop all the rest of the voltage and limit the current. Thanks again and hopefully I'm not being a pest.
+gw25
In this circuit the transistors have only two states, when they are conducting it is a dead short, when they are not conducting they have infinite ohms. So the side that is conducting shorts out the 12 V DC and the other side cannot see it. When that side stops conducting it is wide open, now the other side can see the 12 V DC because it is no longer shorted out.
Keep asking your questions, I can remember the first time when I was trying to figure this out.
+AllAmericanFiveRadio , thanks and I shall. So I believe I understand what you are saying about the transistors. When one is on it allows the 12 V source a path for the LED with only a 470 and 100 resistor to ground allowing for a good deal of current. But here is what I'm still failing to grasp. The right diode is on it is b/c the right transistor is on. And I believe what turns the right transistor on is b/c it has a voltage on the base to emiter junction greater than .7 volts. I believe that voltage source is coming from the left diode (which is currently off) circuit. At 3:56 you clearly show this. So if there is current flowing form the left (off) diode to the base of the right transmitter, why is the left transistor not forward biased enough to turn on. I enterperate you last explanation as when the right transistor is on it is sucking all the current from the voltage source, but as I currently understand things the right transistor is only on b/c of the voltage/current it is getting from the left (off diode) path.
I also don't fully understand how the voltage for the ground to base is 1.97 volts on the right side transistor at 3:56. Again if it's voltage comes from the left (off side) then wouldn't the voltage on the right side transistor base be what was left after the 10K resistor. As I currently calculate that would be (11.3/ 470 + 10K + 100) * 10470 = 11.19 voltage droped at the after the right transistor 10K resistor.
Thanks again
+gw25
Think the problem you're having is you're not understanding what a transistor does in the circuit. The side that the LED is lit, take the transistor out of the circuit and put in a straight wire from collector to emitter. So now the resistors that are in circuit are the 470 ohm and the 100 ohm to ground.
I think this video will help.
Transistor, How Does it Work in a Circuit, Demo
ua-cam.com/video/vs3zUHdlsYY/v-deo.html
What program did you use to make the schematic at 3:40? Adobe Photoshop?
Hola espero que me ayudes , arme dos flip flop y me funciona de maravilla como esta en tu diagrama lo que sucede es que cuando lo conecte a la protoboard presiono el pulsor y el otro flip flop también lo hace , como hago para que no interfiera en al otro circuito en mi proyecto necesitó los dos flip flop alimentados con una batería espero que me ayudes
I'll be glad to help but I'm not sure what you are asking.
Hi Rick, nice demo again.
Kind Regards ... Andy
can I use two 12V diode lamps instead of LEDs?
12 V diode lamps are LEDs. It would have to make sure that the 12 V diode lamps you want to use do not exceed the current limitations of the transistors.
I just built this circuit, but I have an anomaly. I do see the LEDs flip-flopping, however, the "flopped" LED is NOT completely off, that is, it is dimmer than the "flipped" LED, but it is nevertheless on. One thing I did differently is I have a 560 (instead of 470) ohm resistor inline with the LED, and the resistor tied to the power supply instead of the LED, and then the LED is tied to the collector of the transistor. Could this be the reason why the off LED is not off all the way?
+ZillaYT
This is not uncommon with flip-flop circuits. There has to be parts on one side that do not match other side. To get a discrete component flip-flop circuit to work properly each part on both sides must be matched. Flip-flop circuits are one of the hardest circuits to get working properly. You have done well to get it to work at all. When I originally built the circuit I swapped out many components until I got everything to match. If you measure the voltages, I would start at the transistors collector, this information can be helpful in determining which part needs to be changed out to match the side that is working properly.
+AllAmericanFiveRadio
Here's what I see, all in Volts. Flip means transistor's corresponding LED tied to its collector is on, flop means it's off.
Q1
Vcc-GND: Flip, 0.97, Flop, 5.601
Vce: Flip, 0.078, Flop, 4.71
Vbe: Flip, 0.72, Flop, 0.11
Q2
Vcc-GND: Flip, 0.994, Flop, 5,598
Vce: Flip, 0.11, Flop, 4.7
Vbe: Flip, 0.75, Flop, 0.084
+ZillaYT
Another troubleshooting technique is to swap parts between each side. When the unwanted result moves you have found the part you need to replace.
+AllAmericanFiveRadio
In my case, the unwanted result, that is the LED being dimly on on the flopped side, is on BOTH sides.
+ZillaYT
You never said it was both sides. The bias needs to be changed.
Another great informative video.
Thanks!
Keep up the good work.
At 4.03 are you saying that the capacitor discharges in the base of the transistor and turns to off? Wouldn't a current turn it on? Sorry, my understanding of electronics is still in the early stages. :s
I'm using NPN transistors, and the N and P denote the type of material doping, in this case silicon. The base material is doped P, that means if you put a positive bias on it the transistor will turn on. If you put a negative bias on it it will turn off the transistor.
Many thanks for the info. :)
Positive current at the base of a NPN transistor will turn it on while its there, but negative current will turn it off, Notice that capacitor only gave a very short negative pulse, if the other transistor did not turn on or was not in the circuit this transistor will come back on again when negative pulse ended, Because the other transistor came on and positive current stopped flowing through the base of first transistor it stayed off.
Flip-flop circuits are very balanced circuits. The impedance or resistance at the collector is much higher than at the emitter. When the 22 µF capacitor charges the current charging the capacitor never exceeds the transistors trigger threshold. When the 100 ohm resistor is shorted, this makes the impedance at the emitter even less and that causes the charged 22 µF capacitor to produce a negative pulse on the base of the NPN transistor turning it off.
Thanks Sam
Excelente !, que transistor usas ?
+Dario Gruber Thanks
2N222
excellent explanation!
Love it!
Thanks SpeakerFreak95
it is okay if i used 2n3904 transistor instead of 2n2222??
The 2n3904 should work just fine. It is important that the parts on both sides of the flip-flop matches close as possible. Because of that they can be a little tricky to build, but once you get them working, they work very well. Good luck.
Me fue de mucha ayuda, ¡gracias!
Your welcome!
@KyleCarrington
Memory and logic, A NotA, CPU....
Can we use 12v relay in lieu of LEDs?
You can, you may need to lower or eliminate the 470 Ohm resistors. If you want a free running circuit you might try an Astable Multivibrator.
IGBT Astable Multivibrator
ua-cam.com/video/PnAiAhZH9hw/v-deo.html
You also may need diodes across the relay windings.
@@AllAmericanFiveRadio Thanks
@@ShivaShankar-rj4rg Your welcome. One more think I would build with LEDs first. Get the flip flop working than change the circuit. The components on each side must be matched as close as possible.
Thanks ElectricSparq
What happen if I use a mic in the place of switch ?
sie, is it possible to build all flipflops in one ic??????
JK Flip Flop CD4027BE
ua-cam.com/video/zo0UR5BgK1M/v-deo.html
D Flip Flop Clocked with 555 Timer
ua-cam.com/video/l5MM9-rt8b0/v-deo.html
Now I know how quartz clocks work
Thanks
Thanks fingerboy18
Awesome explanation! Thank you so much!
Thanks
Glad the video helped.
Adobes, FreeHand 11, Photoshop Elements 10, Premiere Elements 10
What is the transistors numbers
The transistor number is 2N2222.
Ask your questions.
Thanks for your quick response 😊
Thanks for this great tutorial
Thank you, and your welcome.
is this a series or parallel circuit
both
Thanks PoirierMike
Thanks kitzenmovies
GOOD CIRCUIT AND WORKS
thanks in the name of the slow car sticker movment, part time for appreciation and love, The Box Club, publish on and off media, say so as a "greeting", the Future Consciousness "sin" detection unit (Pro Jahnn and Dunne), write things down, I would have been people's psychiatrist, human robots ( not publishible), and psychic, not contemporary war,
Again GOOD CIRCUIT WORKS LIKE A CHARM
why one of the led is double blinking?
Camera strobing
Thanks maahal
Good explanation
Thanks sir for your quite description
Hmpf. It's not working.
Are these PNP or NPN transistors?
NPN
Hm. I used NPN. So I read the diagram right. The circuit even oscillates when I press the button continuesly, but it does not switch. Hm... I used C547B transistors and tried to find similar capacitors. Maybe the transistors are not quite right. Can you take a look at them and tell me which properties are important and not-met?
From what I can see about the C547B transistors you are using, they should work as long as they're good working transistors. The transistors I am using are just general purpose 2N2222's.
Building a flip-flop circuit can be somewhat of a challenge. The transistors I used I made sure that they have the same Beta, amplification factor. Also all the other components, resistors and capacitors, were chosen as close to being the matched as possible. So another words all the components on one side have the same characteristics as the other side.
Beta amplification factor?
www.learningaboutelectronics.com/Articles/How-to-calculate-beta-of-a-transistor
Thanks THEtechknight
excellent explanation thanks
Azeddine Bouyadaine
Thanks Azeddine Bouyadaine
good bro. Your scheme amazing with on off one switch. You are goD😘
Thanks
+AllAmericanFiveRadio Hehe Nothing Bro
Thanks lawnmowerrecycler
thanks for the video,, i am grateful to you.
RC Time Constant
awesome, just what i was looking for, it works very good,
Thanks manojsam79
oi!Gostei muito do seu vídeo. Eu me inscrevi no seu canal e cliquei em gostei. obrigado por me ajudar
Thank you, and your welcome.
Very Helpful video
+irfan mughal
Thanks
great video helped me alot
Thanks
Thank you Sir !!
hey, great video!