Validate an IP Address | String | GFG POTD | C++ | Java | Code Kar Lo

[@mrdeath9132]

Sir What a Beautiful Explanation

[@code_kar_lo]

Thanks 🙏❤️

[@NiazNiaz-y9c]

well and informative explain vaiya💖

[@code_kar_lo]

Thanks a lot 🙏❤️

[@arnab027]

First time I am facing this problem
I submitted a wrong code which passed all tc
After watching ur video I realized that I did a small wrong for which code should not run
And surprisingly now i am trying to submit the old code which was accepted it is showing Rte 😅

[@AMANKUMAR-bt6cw]

Sometimes GFG changes the test cases.
I also faced the same problems a few times.

[@arnab027]

@@AMANKUMAR-bt6cw achha

[@code_kar_lo]

Yes gfg changes the test cases.

[@salmaniproductions1104]

Solved on my own, Thank you bhaiyya

[@code_kar_lo]

Keep it up 🙌

[@salmaniproductions1104]

@@code_kar_lo yes thank you bhaiya

[@kshitijsingh8754]

if (str[index + 1] == '0' && i - index - 1 > 1) return false;
if (str[index + 1] == '0' && str.length() - index - 1 > 1) return false;
for checking leading zeros at start and end

[@aizad786iqbal]

i solved on my own, but they changed test cases, did few modifications now , working fine
idk why they do this...
btw we can use regex to solve these type of problem also....
I will try that later...
and ye technically TC bhi O(1) hua an since str length is 15 max....

[@code_kar_lo]

Hn string ki length bohat jyada nhi hogi

[@mohitjain9402]

public boolean isValid(String str) {
String[] arrOfStr = str.split("\\.");

if(arrOfStr.length != 4){
return false;
}
for(int i=0;i 1) && (arrOfStr[i].charAt(0)) == '0' ){
return false;
}
int x=Integer.parseInt(arrOfStr[i]);
if(x

[@pain9569]

sahi hai bhai, mera bhi same logic hi tha bs andr
int val = Integer.parseInt(arr[i]);
if(val255){
return false;
}
ye inner loop m code tha sare tc pass kr gye