C array of strings🧵

C array of strings tutorial example explained
#C #string #array

[@BroCodez]

#include
#include
int main()
{
char cars[][10] = {"Mustang","Corvette","Camaro"};
//cars[0] = "Tesla";
strcpy(cars[0], "Tesla");
for(int i = 0; i < sizeof(cars)/sizeof(cars[0]); i++)
{
printf("%s
", cars[i]);
}
return 0;
}

[@sanaolsadako3417]

How can I insert another string in that array?

[@markangelcalaycay4165]

2:54 2:54 2:54 2:54 2:54

[@benoitgauthier6089]

One VERY important point when using strcpy() that really should have been mentionned:
The destination string should be large enough to accept the source string. Otherwise, it will overflow on other memory adresses and potentially corrupt your program

[@Aymanne-io6vb]

You can also put space to occupy the string space being replaced if the string to replace another string is not large enough, not a permanent solution though:
#include
#include
int main(){
char names[][10] = {"Hello", "Cameroon", "Doremi", "colagge"};
printf("No. of rows: %d
", sizeof(names)/sizeof(names[0] ) ) ;
printf("No. of cols: %d
", sizeof(names)/sizeof(names[0] ) ) ;
strcpy(names[1], "Dora " ); //Changes value of a string array. Put space to occupy the rest of the letters since the initial string is large.
for(int i = 0; i < sizeof(names)/sizeof(names[0]) ; i++){
printf(" %s
", names[i]);
}
/*
for(int i = 0; i < sizeof(names)/sizeof(names[0]); i++){
for(int j = 0; j < sizeof(names[0])/sizeof(names[0][0]); j++){
printf("%c", names[i][j]);
}
printf("
");
}
*/
return 0;
}

[@alexiosalexiou3180]

Thanks, simple, straight to the point, analytical.

[@mohammedazzan7529]

yours was the simplest to understand thank you.

[@kevser176]

ı really couldnt get this topic but now everything is clear. thanks you are the best🥺

[@marbles5590]

Thank you for this video! It can also be *cars[ ] in order to not have wastage of memory

[@movieyouser]

Sir, you are the help I needed

[@minari_0324]

damn you made our 30-60 min lecture into 3 mins

[@sebastienroux1790]

Can you replace for example "tesla" with a variable that ="tesla" ?

[@TheScissorunner]

char sub[ ] = "tesla";
printf("sub = %s
", sub);
strcpy(cars[0], sub);

[@andrewdales9727]

Yes

[@sumitupadhyay8699]

Can we use use strings in 1d arrays?

[@dkp8230]

I'm pretty late but i think no since a string itself is an array of characters so an array of strings must be a type of 2D array

[@zraie2455]

A string is a 1D array of characters

[@ambeikaam3609]

yepp for example: #include
#define MAX_LEN 10
int main(void) {
char lecturer_name[MAX_LEN] = {'A','n','g','e','l','a' };
char lecturer_name[MAX_LEN] = "Angela"; //this is a string
char word[MAX_LEN] = {'h', 'e', 'l', 'l', 'o', '\0'};
int i = 0;
while (i < MAX_LEN) {
printf("%c", lecturer_name[i]);
i++;
}
printf("
");
return 0;
}

[@TheLivingCrittles]

I dont understand the math for the for loop... sizeof(cars) would be 2, since 0 counts as an index. sizeof(cars[0]) is Tesla, which is 5 characters... so wouldn't you be comparing 0, 1, and 2 against 2/5 which is 0.4? so shouldn't the loop break after the first element? so confused...

[@moaz_king_1001]

thanks for help :)

[@DarkDevilVaqif]

10k subs in a day nice

[@kevser176]

ı wish ı can like this video multiple times

[@bernardev3]

THANKS BRO!!!!

[@umutaydn6184]

thanks alot!

[@arkabrian5796]

THANK YOU SO MUCH!!!

[@Artameful]

Thx bro

[@kyte8131]

and how the hell do i take input from user?

[@zkskakksis1514]

Scanf

[@shouryadeepbera7114]

​@@zkskakksis1514causes problem when you take consecutive inputs using a loop.

[@zkskakksis1514]

​@@shouryadeepbera7114what do you mean?

[@shouryadeepbera7114]

@@zkskakksis1514 try taking inputs in a string array using loop, it will cause errors...which can be fixed by clearing the input buffer after each input.

[@zraie2455]

@@shouryadeepbera7114
#include
#include
#define NAME_LIST_SIZE 10
#define MAX_STR_LEN 21
int main() {
char name_list[NAME_LIST_SIZE][MAX_STR_LEN];
printf("Please enter a name: ");
char user_input[MAX_STR_LEN];
int i = 0;
while(i < NAME_LIST_SIZE && fgets(user_input, MAX_STR_LEN, stdin) != NULL) {
strncpy(name_list[i], user_input, strlen(user_input) - 1);
printf("%s
", name_list[i]);
i++;
printf("Please enter a name: ");
}
printf("
Program finish ^_^");
return 0;
}
It's better to use fgets in that case

[@potatopoo6978]

Why is mustang not printed?

[@MRCN49]

we changed it to "Tesla" a line below

[@vlastimirzdravkovic7624]

I fucking love you

[@roronoazoro5672]

can someone tell why did it not print mustang?

[@Wintre_Hesmith]

The 9th line of code, strcpy replaced the first string element "Mustang" with "Tesla" instead

[@roronoazoro5672]

@@Wintre_Hesmith alr thanks bud

[@latesttrailers-yb8pr]

Mine ain't working

[@MostaphaQamar]

dark theme sucks. view is not clear. use light color

[@stonedcodingtom9097]

Thx Bro