My understanding is that the trypsin is extracted from the pancreas as a by product of the food industry. It can probably be artificially synthesized, but this method is much easier and cheaper.
Thanks for your question Lianna. For this solution we want 150 mL of a 0.25 % (w/v) solution of Trypsin. This is 0.25 per cent (centum is Latin for 100), so 0.25 per 100. It is (w/v) which means weight (g) by volume (mL). All this means 0.25 g of Trypsin (weight) for every 100 mL of final solution (volume). I usually use a proportionally statement (2 fractions that are equal to each other) to solve this. 0.25 g Trypsin / 100 mL Solution = x g Trypsin / 150 mL Solution. Solve for x to determine the mass of Trypsin you must use. Hopefully you can see with the proportionally statement, we can sub in any concentration or final volume to easily calculate how much chemical you need to weight. If you would like more information on these type of calculations, check out my lecture on Solutions here. ua-cam.com/video/sCwFnsxq6ic/v-deo.html
I must say, I like the explanation that came with the visual preparation. It will make my write-up look much more professional. Thanks a lot.😊
I am glad it was helpful. Just out of interest, where are you doing a write-up?
@@ProfessorDrewCollop I'm doing my A-levels and I needed to make research on everything that deals with enzyme controlled rate of reaction.
Good luck.
@@ProfessorDrewCollop Thank you😁
Nice explanation
Are any animals killed during the extraction of Trypsin from their pancreas ? Or can it be done without killing the animal ?
My understanding is that the trypsin is extracted from the pancreas as a by product of the food industry. It can probably be artificially synthesized, but this method is much easier and cheaper.
@@ProfessorDrewCollop Thanks Professor .
Can you explain your calculation for .25% trypsin
Thanks for your question Lianna.
For this solution we want 150 mL of a 0.25 % (w/v) solution of Trypsin. This is 0.25 per cent (centum is Latin for 100), so 0.25 per 100. It is (w/v) which means weight (g) by volume (mL).
All this means 0.25 g of Trypsin (weight) for every 100 mL of final solution (volume).
I usually use a proportionally statement (2 fractions that are equal to each other) to solve this. 0.25 g Trypsin / 100 mL Solution = x g Trypsin / 150 mL Solution. Solve for x to determine the mass of Trypsin you must use.
Hopefully you can see with the proportionally statement, we can sub in any concentration or final volume to easily calculate how much chemical you need to weight.
If you would like more information on these type of calculations, check out my lecture on Solutions here.
ua-cam.com/video/sCwFnsxq6ic/v-deo.html
@@ProfessorDrewCollop may I know calculation for EDTA
I explained the calculation in my previous comment. Can I clarify anything?