If you haven't watched this video yet, read this. Don't stop the video to try and answer the questions or you'll be sitting there all day. In the second problem starting at 2:40, he doesn't provide enough information to solve the problem until after he tells you to pause the video. In the last problem starting at 6:45, he doesn't tell you that the charged mass is actually connected to a rope until after he tells you to pause the video. Otherwise, this is a great series. Enjoy...
hi wanna ask, since the positive charged particle follows the direction of the electric force between the plates, would the path of an electron also be the same, or would it go towards the positive side of the plates, ie upwards?
I have a question about the last problem. Wouldn't mgsin(θ) also be added to Ftsin(θ)? because gravity is the force that would keep the pendulum oscillating back and forth if there were no electric field, so wouldn't qE = mgsin(θ) rather than Ftsin(θ)?
+Mohammad Bilal An electric field points in the direction that its force exerts on a positive test charge. Since the field exerts a leftward force on the test charge, the electric field must point to the left.
I only gotta problem on last question... The doubt is.. Why the electric field weren't on the right side along with left, up,down ,forward, and backward. Overall electric field should have been to all directions 😌😌😌 I love you lasseviren😘😘😘😘😘😘
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If you haven't watched this video yet, read this. Don't stop the video to try and answer the questions or you'll be sitting there all day. In the second problem starting at 2:40, he doesn't provide enough information to solve the problem until after he tells you to pause the video. In the last problem starting at 6:45, he doesn't tell you that the charged mass is actually connected to a rope until after he tells you to pause the video. Otherwise, this is a great series. Enjoy...
These videos are unbelievable. Thanks!
You saved my day lasseviren thanks you a lot
hi wanna ask, since the positive charged particle follows the direction of the electric force between the plates, would the path of an electron also be the same, or would it go towards the positive side of the plates, ie upwards?
You sir, are doing god's work! Lol, but seriously, if I pass this physics class, it'll be because of you. Thank you!
I have a question about the last problem. Wouldn't mgsin(θ) also be added to Ftsin(θ)? because gravity is the force that would keep the pendulum oscillating back and forth if there were no electric field, so wouldn't qE = mgsin(θ) rather than Ftsin(θ)?
thx a lot! .why are your asking how big is Vektor E but you solve just E ?
How did you determined the direction of electric field at 709
- via YTPak(.com)
+Mohammad Bilal An electric field points in the direction that its force exerts on a positive test charge. Since the field exerts a leftward force on the test charge, the electric field must point to the left.
thanks
Where's the Calculus??
I only gotta problem on last question... The doubt is..
Why the electric field weren't on the right side along with left, up,down ,forward, and backward. Overall electric field should have been to all directions 😌😌😌
I love you lasseviren😘😘😘😘😘😘
vijaysingh chauhan he assumed the electric field is uniform
??