Great job and thank you - I don't understand why my professor can't understand that we need this type of breakdown BEFORE we get into the really complex equations and theories. Now it all makes so much more sense.!
Ahh I was looking for more videos on how this like the calculations too. I finally understood through your video. I know 7 years is a long time, but I would definitely watch to learn.
Julia I'm out of your world yet thats good to see such a beautiful soul trying to give out to world what has been learnt. I'm good with philosophie and with your help, better at thermodynamics, thanks a lot :)
0:53 Only reversible! adiabatic processes are isentropic (ΔS=0). In typical adiabatic processes, there is no heat transfer across the system's boundaries (ΔQ=0)
At 5:54 I think your air standard cycle represents the T-S cycle in wrong way because the T3 is the maximum temperature where as T4 is temperature less than T3 but greater than T2. By the way I like the line "Believe me I am Engineer😂😂" I know every engineer's hardships. And love your content ❤❤. And can we join in insta.
Think u can try to add some explanation on the equipment involved in the carnot cycle (compressor, turbine etc.) and try to explain heat pump and refrigerator, and also try explain some concepts like why the curve for adiabatic is steeper than the isothermal line, why adiabatic processes are also isentropic etc, I did spend some time to read it up on the internet just now :) Anyway very good job and clear explanation, pronunciation is nice and clear n u seem very passionate about the subject!
Женщина просто лучшая, если б не она, я бы этого гребаного Романюка и ТТД учила бы полтора года. Так же хочу сказать спасибо тиндеру за то, что я выучила английский
The short answer is that entropy is a measure of the disorder in a system. A process happening with constant entropy, means a reversible process with no heat transfer. Idealized processes that expand and compress fluids, are examples of constant entropy processes. That is an oversimplified explanation, but the idea is that time's arrow always points to either an increase in entropy, or constant entropy. You cannot destroy entropy; you can generate it, keep it the same, discard it to your surroundings, or bring it in from your surroundings, but you cannot destroy it without time running backwards. Entropy enters a system with heat transfer, and the amount of entropy is proportional to the heat transferred and inversely proportional to the Kelvin temperature at which it transfers. The formula is delta S = delta Q/T, for a constant temperature heat addition process. So an adiabatic and reversible process will have no change in entropy. A reversible process, is an idealized version of a process that doesn't destroy any entropy. The process is possible in both directions. Examples of such processes that could be reversible in the upper limit of perfection are: Motors and generators Turbines and compressors Compression and expansion of a gas in a cylinder with no heat transfer at the same time Heat transfer across an infinitesimal temperature difference Electric current through superconductors The following processes are inherently irreversible: Throttling valves Sudden expansion of a gas Heat transfer across a finite temperature difference Mixing Any process involving frictional heating or ohmic heating
Quality is mass of vapor, over total mass of liquid plus vapor. We define it this way, because we want high quality steam (i.e. mostly vapor) to exit a turbine.
Omg 7 years later. This helped me so much ty 😊
Great job and thank you - I don't understand why my professor can't understand that we need this type of breakdown BEFORE we get into the really complex equations and theories. Now it all makes so much more sense.!
pro tip: watch movies at Flixzone. Been using it for watching loads of movies recently.
@Ahmir Jaxen Definitely, have been using Flixzone for months myself :)
@Ahmir Jaxen Yup, been using Flixzone for months myself :D
Your professor knows what he’s doing. He wants to weed out the people who can’t conceptualize this stuff on their own.
@@HawkGTboy His professor is a dick, professors are paid to TEACH, not weed out
its so clear to me now whilst i'm studying for my thermo exam. Thanks a ton!
Watching this 5 years later in the UK has actually saved me thank you
Love that this random video is still helping people! Good luck on your exams!
Julia you've helped me couz this wasn't making sense to me but now I will become good at it thanks ❤
It makes so much fricking sense now!!! Holy Cow! Somebody please give that girl a sponsor! Geez!
Thank you!!!!! Don't know where I'd be without this video!
Ahh I was looking for more videos on how this like the calculations too. I finally understood through your video. I know 7 years is a long time, but I would definitely watch to learn.
Im also studing mechanical engineering and this helped me so much!!
thanks from Spain! :D
I can confirm, one year after you and the symptoms remain.
2024 and still going strong @@yodartt
that "cool" at 4:45 killed me haha
thanks for the vid! will definitely help me not die in my thermo exam
:D
Adiabatic means that no heat transfer occurs. Entropy is constant ONLY in a reversible, adiabatic process but not in an irreversible one.
I have my HVAC test tomorrow and this was a life saver. Thanks a lot🤗🤗
THANK YOU Lin saved me a lot of time summarising these myself
this is going to help me on my Thermo test, thank you
Kudos for the great job done 👍
Wish I knew this when I took Thermo. Great video!
Not too shabby. The video wasn't fancy like a full time youtuber but the points that were important were gotten across!
youre a bit of a legend for this
Julia I'm out of your world yet thats good to see such a beautiful soul trying to give out to world what has been learnt.
I'm good with philosophie and with your help, better at thermodynamics, thanks a lot :)
You're the GOATm exactly what I was looking for !!
0:53 Only reversible! adiabatic processes are isentropic (ΔS=0). In typical adiabatic processes, there is no heat transfer across the system's boundaries (ΔQ=0)
Thank you Julia ! You did a great job ! This is really difficult for me to understand, but your presentation helps a lot ! All the best to you ;-)
I explains lot clearly and give me a exact image . Thanks a lot for the effort taken for making this vedio
OMG Julia! You hit the spot!!!
Very nice indeed! Congrats!
I liked your T shirt..
Love from india🇮🇳🇮🇳❤️
I m mechanical engineer
Muchs needed informations 4 my brains! Thx!
Great explanations!
wow! A semester covered simply, very well... Thank you!!!! :)
23/6/2022. I have state exam in 4 days and this is so helpful. Thank you Julia Lin for clear explanation :)
Thank you so much! This helped a lot I just couldn't focus well because you're so beautiful and I'm just staring at your face most of the time.
Great job
It really helped me. thnx...from India
Thanks Julia, this gonna save me on my midterm 😩😩
Julia, you're awesome :)
This was a generally good video, and i would especially use this video for revision on key concepts!
Gret exxplaniton. I lyke it! Smartness!
Thanks a lot, the video was very helpful.
Huge help. Thank you so much for making the video!
Thank you so much for this
Thank you so much. Please keep making more of these.
This helps a lot, thank you sm 🙏🏽
Thank you for making it extra simple!
At 5:54 I think your air standard cycle represents the T-S cycle in wrong way because the T3 is the maximum temperature where as T4 is temperature less than T3 but greater than T2.
By the way I like the line "Believe me I am Engineer😂😂"
I know every engineer's hardships. And love your content ❤❤. And can we join in insta.
Awesome! Thanks!!
I am majoring in biological engineering but this is still really helpful. So thanks!
Thanks!!! It was really useful
So helpful!! Thank you!
Think u can try to add some explanation on the equipment involved in the carnot cycle (compressor, turbine etc.) and try to explain heat pump and refrigerator, and also try explain some concepts like why the curve for adiabatic is steeper than the isothermal line, why adiabatic processes are also isentropic etc, I did spend some time to read it up on the internet just now :)
Anyway very good job and clear explanation, pronunciation is nice and clear n u seem very passionate about the subject!
Thank you so much for the explanation!!! It was really helpful in making my understanding clear!!!!
Bravo Bravo Bravo !
Love you mam 😍❤️
Very informative
Thank you very much
slay Queen!!!
thank youuuuuu
You are good!
Oh my god thank you u like a angel 😘😄
I trust her, she is an engineer...
Great video
sweet vid !
thanks!
Watching this 20 mins before my exam 😂
I like the explanation of video..trust me I'm not engineer...😂😂😂
thank you
thx so much loved the video!! #youmademepassthiscourse
谢谢小林同学
Haha her t-shirt 😂
Женщина просто лучшая, если б не она, я бы этого гребаного Романюка и ТТД учила бы полтора года. Так же хочу сказать спасибо тиндеру за то, что я выучила английский
Thank you!
hello Julia... it really helped... may u help me with some more topics...
Isotherms on T-S diagram are
Parallelogram to S or T?
yes indeed
In middle of pv diagram there will be mixture of liquid and vapour not (liquid and gas). But I like your explanation 👍
Got 20 minutes before my exam wish me luck
trust me im an engineer
It would be more helpfull if you included the P-h diagrams too. Btw, it was helpful.
hi where do you belong to
Nooo i just saw this video after my exams 😭
can u plz use whiteboard so that the diagram would be clear to see!
AWESOME!!! Btw did you win? lol
Thank you so much. You are such a wonderful teacher❤️
Lots of love from INDIA
Thank you. I’m having a hard time with entropy. Can anyone tell me what constant entropy means?
Thanks
The short answer is that entropy is a measure of the disorder in a system. A process happening with constant entropy, means a reversible process with no heat transfer. Idealized processes that expand and compress fluids, are examples of constant entropy processes.
That is an oversimplified explanation, but the idea is that time's arrow always points to either an increase in entropy, or constant entropy. You cannot destroy entropy; you can generate it, keep it the same, discard it to your surroundings, or bring it in from your surroundings, but you cannot destroy it without time running backwards. Entropy enters a system with heat transfer, and the amount of entropy is proportional to the heat transferred and inversely proportional to the Kelvin temperature at which it transfers. The formula is delta S = delta Q/T, for a constant temperature heat addition process. So an adiabatic and reversible process will have no change in entropy.
A reversible process, is an idealized version of a process that doesn't destroy any entropy. The process is possible in both directions. Examples of such processes that could be reversible in the upper limit of perfection are:
Motors and generators
Turbines and compressors
Compression and expansion of a gas in a cylinder with no heat transfer at the same time
Heat transfer across an infinitesimal temperature difference
Electric current through superconductors
The following processes are inherently irreversible:
Throttling valves
Sudden expansion of a gas
Heat transfer across a finite temperature difference
Mixing
Any process involving frictional heating or ohmic heating
@@carultch thank you. That’s a lot to think about. I appreciate it!
Isn't it mass of vapor over mass of liquid minus the mass of vapor?
Quality is mass of vapor, over total mass of liquid plus vapor. We define it this way, because we want high quality steam (i.e. mostly vapor) to exit a turbine.
btr den my swedish lecturer LOL
Adiabatic is not certainly isoentropic!
Idealized adiabatic processes are isentropic. Some adiabatic processes are not, such as a throttling valve.
👇if you’re a chemical engineer student
Great video
thanks!
Thank you!
Thank you!