For admission in Classroom or Online courses for IIT-JEE /NEET at Narayana Jaipur Center, fill the enquiry form - forms.gle/gpnEELwNnsnePg8u6 Register for Admission Test of infinIITy SRG batch for JEE(Adv) 2025, click - ntsc.narayanatalent.com
Hi bro I am in 11th and studied complex nos. Only till ncert level , and now finding difficult to understand my jee module...will it be helpful for me to watch this session and then read the module.?..
It won't help with the module truthfully speaking. It would be better if you do complex number till jee mains level which will make you ready for module problems. Also save this for later as it contains really invaluable problem solving approach to math problems in general. You can watch it now but dont forget to revisit it in 12th.
quality of teaching aisi h ki recording se krna pdta h .live me to schock me aa gya tha ki shuru kiya complex se aur que krwa diya ITF ka .just continue till ADV
To Adithya Pathak sir, ( 11:52 ) If I approach this question with ITF, I'm getting the answer as 3, whereas if i approach the problem with complex number method the answer as 3i (√-9). What must be the right answer? Please clarify, what I'm missing in this particular approach. Thank you 💛⚡
For admission in Classroom or Online courses for IIT-JEE /NEET at Narayana Jaipur Center, fill the enquiry form - forms.gle/gpnEELwNnsnePg8u6
Register for Admission Test of infinIITy SRG batch for JEE(Adv) 2025, click - ntsc.narayanatalent.com
Amazing. This is real out of the box thinking which is needed in JEE ADVANCED
Thanks Rishi
Before this sir used to teach in allen kohinoor batch mumbai
Ya …
I am in mumbai allen ....Kohinoor is dream for us though couldn't make it can they take in if I score in mains 2 attempt
13:26 sir the complex number is 5 + root3(i)
Yes you are right, it will be 5 + root3i, thanks
Thanks for pointing out..calculation error..will be careful in future
Hmm bhai mera bhi vhi dimag atak gya tha mene calculate Kiya to ans diif ths
superb sir!!! aaj kuch naya sikha finally ...
Hi bro I am in 11th and studied complex nos. Only till ncert level , and now finding difficult to understand my jee module...will it be helpful for me to watch this session and then read the module.?..
It won't help with the module truthfully speaking. It would be better if you do complex number till jee mains level which will make you ready for module problems.
Also save this for later as it contains really invaluable problem solving approach to math problems in general. You can watch it now but dont forget to revisit it in 12th.
@@NightSwamp. Okay.
Thanks
Really needed sir please continue till adv with long lecture ❤
Ya sure
Thankyou Sir. aaj bahut naya approach seekha. ab inverse trig se dar nahi lagega.
Thanks
This is called extraordinary application for an ordinary concept…wow ..god bless you sir…❤
Thanks Ravi
This was an excellent explanation! You made a complex topic so easy to understand. Thank you sir.
Thanks
amazing session sir thank you so much 🙏🙏
Thanks
sir superb concept..will definitely use this approach for inverse trigonometry
5:53 sir n=51/8 aa raha hain
yes it is correct, thanks
yes bcz there's a bit mistake in the ques. it should be tan-inverse (1/4) in place of tan-inverse(1/9)
I found it useful for me…Mumbai students are missing you sir…❤
Thanks
Are u in Kohinoor?
You Just continue these extraordinary classes sir ❤❤❤❤
Thanks
Thank you Sir, your online classes are very helpful 🙏
Thanks
Thank You Sir learned a new approach today
Thanks Atharva…
Aditya pathak sir ❤❤
Thanks dear
Very good explanation 👏👏👏
Thanks
thank you so much sir 🙏 please give more types of questions..
awesome lecture sir! Helped a lot!
Thanks beta
11:14 really didnt knew about this method to solve inverse trigonometry with complex no.s like that thank you
Thanks
@adityapathak7653 looking forward to next lecture sir will you teach p and c , probability also in algebra
Epic
Thanks
quality of teaching aisi h ki recording se krna pdta h .live me to schock me aa gya tha ki shuru kiya complex se aur que krwa diya ITF ka .just continue till ADV
Thanks 😊
Thank sir for this wonderful lecture ❤❤
Thanks
6:48 x=4/3
Sir please increase duration of lectures
Block strategy when release
Thank you sir, I am in 11th but have a little knowledge of inverse trigo and your complex number approach is so intresting, thank you so much.
Thanks Soumyadip…it will help you in coming days…
Thanks
Welcome
I am in mumbai allen ....Kohinoor is dream for us though couldn't make it can they take in if I score in mains 2 attempt
To Adithya Pathak sir, ( 11:52 )
If I approach this question with ITF, I'm getting the answer as 3, whereas if i approach the problem with complex number method the answer as 3i (√-9). What must be the right answer?
Please clarify, what I'm missing in this particular approach.
Thank you 💛⚡
Post the image of your approach
@@adityapathak7653 Sir, as per you what is the correct answer?
I'm getting a blunder answer, π= 3i
(From π^2=-9) At the end of solving for a^2+b^2
Sir I think , sin ( tita1 +tita2 +.....tita n ) = cos tita1 . cos tita2 .........cos tita n ( S1-S3+..........) 😅
8 question. 1 one print mistake sir
Ya it’s calculation error…he told that correctly but written down it by mistake I think…😊
there is a print mistake in question 8 part 1, we will correct it, thanks
There is calculation and a print error beta…thanks for pointing it out..will take care in future
Thanks sir for ur response
In 5 th question the triangle should have √3 instead of 3...😊😊😊😊😊
Ya it’s a calculation error…but conceptually all good ….
yes there should be root3i, thanks
There is a calculation error beta…will take care in future if hanks for pointing it out
@@adityapathak7653 ok sir
23:00 - review
Sir atleast recording upload krdena saare lec ki
It’s already there
Sir please help our parents not allowe to pay 100 rupees for test fees please give it free sir please please 🥺 sir
Sir please long session pls sirr
Nope buddy ,this is enough upto daily basis 😊
Fappp