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When I saw what you did in method 1, I did wonder if the same method could be used before distributing. Nice 👍
Fantastic question...❤❤❤.
موفقين عزيزي 😊
شكرًا لك! 😊
love these vids man
Thank you! I'm glad to hear that 😍
Sviluppo e risulta x°4+(14/3)x^3+7x^2+(14/3)x+1=0...lavoro la quartica e ottengo (x^2+(7/3)x+1)^2-(2x/3)^2=0...a questo punto risolvo facilmente ..
My answers are very radical, to the point that they are incorrect. Nice job though!
thanks
When I saw what you did in method 1, I did wonder if the same method could be used before distributing. Nice 👍
Fantastic question...❤❤❤.
موفقين عزيزي 😊
شكرًا لك! 😊
love these vids man
Thank you! I'm glad to hear that 😍
Sviluppo e risulta x°4+(14/3)x^3+7x^2+(14/3)x+1=0...lavoro la quartica e ottengo (x^2+(7/3)x+1)^2-(2x/3)^2=0...a questo punto risolvo facilmente ..
My answers are very radical, to the point that they are incorrect. Nice job though!
thanks