Physics, Torque (13 of 13) Static Equilibrium, Mobile Calculations

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  • Опубліковано 12 лис 2024

КОМЕНТАРІ • 47

  • @Crazylust
    @Crazylust 4 роки тому +16

    All 13 videos were superb...don't know why we need to pay universities tuitions anymore.

    • @stepbystepscience
      @stepbystepscience  4 роки тому +8

      That is a great comment, thank you very much. Maybe I should open my own university?!?!

    • @Crazylust
      @Crazylust 4 роки тому +1

      Step-by-Step Science you should open something for sure. Your teaching is better than my professor lol
      I wish you make tons of money from this because you deserves it. 😁

  • @MrJuicy-rq3ls
    @MrJuicy-rq3ls 3 роки тому +7

    Made it through all 13 videos, and I cannot thank you enough! Best professor

  • @inajessen4500
    @inajessen4500 3 роки тому +8

    This was so understandable and helpful after some frustration in class, trying to grasp the whole equilibrium deal. Thank you!

  • @MK-kq2mi
    @MK-kq2mi 5 років тому +7

    Best person ever to explain torque !!!! Thank you so much brother !!

  • @lunaseo1088
    @lunaseo1088 3 роки тому +1

    Finally came up with a video that truly helps. I felt to dumb for crying over such lesson, It's soooo easy thankyou for making this easy. Thankyou.

  • @michaeloh671
    @michaeloh671 4 роки тому +4

    Can you also talk about when there is mass for hanger(green, orange, purple)?

  • @patriciaturano4171
    @patriciaturano4171 3 роки тому +1

    I love his explanation!

  • @keankean6747
    @keankean6747 3 роки тому +1

    Thank you so much for sharing! It was a great help😇 God bless you

  • @vincentsapone8247
    @vincentsapone8247 Рік тому +1

    Are we assuming the boards are of negligible mass? We would need to include the mass of the boards in the next step and also, the torque of each board if not centered.

    • @stepbystepscience
      @stepbystepscience  Рік тому

      Yes, we are ignoring the mass cross pieces.

    • @waleedsirelkhtim2447
      @waleedsirelkhtim2447 Рік тому

      ​@@stepbystepscience I'm stuck on multiple problems where the crosspieces' mass isn't negotiable. Any advise?
      Thank you.

  • @joshpeligrino3512
    @joshpeligrino3512 3 роки тому +1

    This lightens up my burden 👍☺️

  • @particleonazock2246
    @particleonazock2246 3 роки тому +2

    That is how you do the "Mobiul" problem.

  • @ARUNKUMAR-bu6jd
    @ARUNKUMAR-bu6jd 6 років тому +2

    Very Nicee....
    Sir!!!

    • @manglam7749
      @manglam7749 4 роки тому

      level down bekar hai bakbash ahi

  • @blackpinkyrosie7049
    @blackpinkyrosie7049 11 місяців тому +1

    Does the length of the string affects the balance?

    • @stepbystepscience
      @stepbystepscience  11 місяців тому

      Most of the time we do not consider the mass of the string. So no, the length of the string does not effect the balance. It does not matter how far down the object hangs. Unless you use let it hang down a lot of string and then the mass of the string can significantly affect the mass at the end of the balance.

  • @sherrynottingham2643
    @sherrynottingham2643 2 роки тому

    What if there is another arm where m3 is in your diagram with 2 items now hanging from an arm? How would you calculate the weight of each of the objects? Say now m3 and m4 and d is not equal for them?

  • @coryryder6775
    @coryryder6775 4 роки тому +1

    My teacher has us doing a project where he is having the equation Ax+By=Cz for the mobile, with A being the far left, B being the middle, and C being the end. Could you explain this equation? I don't understand what value I'm supposed to be plugging in for B.

  • @Shackled
    @Shackled 4 роки тому

    Hell yeah! Love it!

  • @RomuelMedija
    @RomuelMedija 3 роки тому +1

    Thank you so much

  • @bharatkumarprajapati170
    @bharatkumarprajapati170 6 років тому

    Please , make video on why kinetic energy = 1/2 (mv^2)

  • @mughatoamugha9029
    @mughatoamugha9029 6 років тому +2

    thank you

  • @ifraharshad6103
    @ifraharshad6103 4 роки тому +1

    I am still confused why didn't we use Mass times acceleration due to gravity?

    • @stepbystepscience
      @stepbystepscience  4 роки тому

      Technically each of the masses should be multiplied by 9.81 m/s2 to get the force, but if each of the masses is multiplied by 9.81 then they would all cancel out and you would get the same answer.

    • @ifraharshad6103
      @ifraharshad6103 4 роки тому

      Thank you!

  • @deleteaman
    @deleteaman 4 роки тому

    you're awesome

  • @chiegargallo3620
    @chiegargallo3620 3 роки тому +1

    STEM PA SELF HAHA😂

  • @kouroshkalantari4473
    @kouroshkalantari4473 11 місяців тому

    why is the force just mass and not mass x gravity??

    • @stepbystepscience
      @stepbystepscience  11 місяців тому

      Technically it is supposed to be the mass x gravity to get the force exerted by each object. But because you would be multiplying by and then dividing by gravity in each case the gravity just cancels out. So as I explained in the video I did not do it.

  • @leianneaguilor6306
    @leianneaguilor6306 3 роки тому +1

    When ur module doesn't make sense

  • @Saeed-ox6ih
    @Saeed-ox6ih 2 роки тому +1

    Thank you