[@kidsgames3352]

Really.....Nice from Tamilnadu

[@SantoshiFamily]

thanks and warm welcome Tamilnadu

[@onlymathematics835]

Bahut bdya guruji

[@SantoshiFamily]

thanks

[@tanishadixit_]

Hey!! U r doing a great job ❤️

[@SantoshiFamily]

Thank you so much 🙂

[@taranipradhani5333]

I just say.... Nice 💚

[@SantoshiFamily]

Many many thanks

[@satpaul4898]

Thank you sir great explanation

[@SantoshiFamily]

your welcome

[@sanjithar2355]

Nice

[@SantoshiFamily]

Thanks

[@mathew868]

sir how to find the subspace W1+W2 in this same question?

[@SantoshiFamily]

We will upload a video on this topic shortly

[@mathew868]

@@SantoshiFamily ok sir

[@mastrammeena328]

W1 + W2 will include the sum of vectors of W1 and W2
To sum krdo
W1+W2 = (x,x+y,z+y,x+z,2t)
i.e W1 + W2 = (x,y,z,t,a)
i.e the whole R⁵
So dim(w1 + w2) = 5 = dimW1 + dimW2 - dim(W1 ∩ W2)

[@riju3134]

@@mastrammeena328 thank you sir

[@SantoshiFamily]

Your welcome

[@shorts-fv6sr]

Sir option a true hoga because zero vector is neccesary in a subspace

[@SantoshiFamily]

option (b) is true

[@saptarshisahoo5075]

zero vector is not a basis vector.

[@shorts-fv6sr]

@@saptarshisahoo5075 what I say first check that

[@saptarshisahoo5075]

The question is asking to calculate dimension of intersection of sub spaces. So even if zero vector is in the intersection subspace, it is not a basis vector so number of basis vector is 3 as shown in the above solution. So option B is correct.

[@iitjammathematics]

Fjjgi

[@vinayksdhnmceducation3833]

Bro is question me answer1 aa rha h

[@SantoshiFamily]

How

[@vinayksdhnmceducation3833]

Bhai up pg mathematics ak girl ne solve kiya h

[@sahnilsiddique3174]

@@SantoshiFamily becz intersection of w1 and w2 is (0,0,0,0,t) and dimension of this over R is 1

[@SantoshiFamily]

Thanks