hello sir you said there is a link of a video in description to find the value of appropriate k value, where is that? 🤔🤔 I think you forgot to keep that...
good presentation but one thing is clear we have value of K =5 then we will go up to 5 instance or we will go to five instance that have low distance with our data point please clear it
sir suppose if k=3 ,there are 2 under weight and 1 over weight ,then label is under weight ,for same problem if k=9 there are 4 under weight and 5 over weight here we assign class label as over weirght .but for k=3 and k= 9 we are assigning 2 different labels for same data,how can we justify it?
No x2 and y2 will not change (x2, y2) Is the test or new example Here we need to find the distance from test or new example to all other examples Follow the video: ua-cam.com/video/gCZsLAzHlEM/v-deo.html
Today exam i got this question only they asked only K=3,5 I wrote if K=3 Healthy If K=5 Deficient(they gave as Healthy and Deficient not Normal, Underweight) 😅😅😅😅😅😅
Solid Video. Thank you
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u r awsome sir
hello sir you said there is a link of a video in description to find the value of appropriate k value, where is that? 🤔🤔 I think you forgot to keep that...
Same here
will the value of K given in the question or there is another method to find the value of K
given
Sir what if in class both the result become equal
Use the first come first serve basis
good presentation but one thing is clear we have value of K =5 then we will go up to 5 instance or we will go to five instance that have low distance with our data point please clear it
Consider the 5 instances with minimum distance
Based on the majority you can assign the class for the New instance
thank you
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very clear explanation !!!!
Thank You
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sir suppose if k=3 ,there are 2 under weight and 1 over weight ,then label is under weight ,for same problem if k=9 there are 4 under weight and 5 over weight here we assign class label as over weirght .but for k=3 and k= 9 we are assigning 2 different labels for same data,how can we justify it?
Yes someone reply plz
@@handeercel7285 This means that the data is more scattered. One class elements are not in close enough.
ua-cam.com/video/UAIIW3Bs5HE/v-deo.html this is also one video which will help you
Ig k value is supposed to be less than or equal to N/2
@@theepicbeatdropper6807 what if it is equal to N/2? i mean if i get two normal and two underweight?what should i take as class label
Wonderful sir😘
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What will we fill near ?mark?
So nice sir
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Thank you teacher >
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How should we apply this algorithm if we have more than 2 attributes?
Great explanation!
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the values of weights change in according to the question after ranking please check the question
Sir two distance are level how we will give a rank for that ..
That is an ambiguous state
In such case you need increase the value of k and then make a dicision
Sir if we did not get a K value how did i find sir
Thank you sir
X2 or y2 value fix rha ge ya change hogi
No x2 and y2 will not change
(x2, y2) Is the test or new example
Here we need to find the distance from test or new example to all other examples
Follow the video: ua-cam.com/video/gCZsLAzHlEM/v-deo.html
Sir where is the video to find the appropriate k values ??
Please attacj it asap i have my exams tomorrow
It will be given in question paper don't worry .
What if we have equal number of NORMAL AND UNDERWEIGHT 🤔🤫
Yes someone plz reply
Choose the value for K to be odd to ignore such situations
Choose the value for K to be odd to ignore such situations
For example: K= 3,5,7
Today exam i got this question only they asked only K=3,5 I wrote if K=3 Healthy If K=5 Deficient(they gave as Healthy and Deficient not Normal, Underweight) 😅😅😅😅😅😅
@@harshitareddy6335 ❤️ hi Reddy
How to evaluate KNN?
i think we are just making a prediction
😀🙏❤️🤗👍😀
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SVCE 💩
Welcome to SVCE vro ≡(▔﹏▔)≡
hi corona engineer
more like SVCE🤡
SVCE faculty intelligence 200% downhill trend.
Known for placements but not
Great explanation ❤
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