Cheers for the Video! Forgive me for the intrusion, I would appreciate your opinion. Have you thought about - Runayslarn Survival Manifestation (probably on Google)? It is a good exclusive guide for discovering how to repair your electronic items without the hard work. Ive heard some awesome things about it and my old buddy Taylor after a lifetime of fighting got cool results with it.
Sir the main thing you do is using less space to make an experiment so if you find a good space and make the video it wouldn't be more clumsy so make sure you have good space About the explanation part, you are really awesome so that I got a belief that I can rock the exam tomorrow thank you sir.
Do it get this right? A resistor is used to control Current? If so, is there a way to get higher current later on in a circuit again? I thought it would control the Volt value hehe.
hi. i have a question. when measuring current how do you know how to remove the resistor to measure current? this is bad wording sorry. like sometimes you removed it and left the end jn the open, ither times you moved it a space down. does it result in the same current?
the ammeter shorts the resistor. The current will go through the path of least resistance (the ammeter) so you must break the circuit in order to avoid that.
I am in the infancy stage of Electronics 101. To this point, I need a major clarification on battery voltage. I want to use a 12V battery with a breadboard to closer simulate the 15 volts across the rails on a HO scale track .... My confusion: .... You see many of these tiny, rectangular, 9V batteries being used with breadboards. A riding lawn mower typically has a 12V battery which is considerably larger than the tiny, rectangular 9V battery, yet the voltage comparison is 9V to 12V. Adding to my confusion is a 12V car battery which has the same 12V rating as the riding lawn mower battery, yet the car battery is quite a bit larger and heavier. What am I missing that differentiates between these voltage readings: 9V rectangular battery versus 12V mower battery versus 12V car battery. Thanks!!!
Hi MK Outdoor Adventures, thanks for watching. To ask questions, please go to my website clydelettsome.com and look for the "Ask the Expert" link. That is where I address questions. I typically use this area of UA-cam for comments from viewers. Thanks again.
Hi Aodh! Sorry for the confusion. I am not sure what you mean by run backward. If you mean decreased, that can happen sometimes when the connection is not good and there is a temporary loss of connectivity between components or the multimeter. If you mean change direction (a change from positive to negative or negative to positive), that will only happen if the electricity is AC. I hope this helps. If I did not answer your question, please go to www.clydelettsome.com/blog/ask-the-expert/ and post your question there for a more detail answer. Thanks. Like, subscribe, and share.
This is helping me a lot, but IDK why.. But I have 12 volt in and out and 2 resistors of 100 ohms and when I connect the 12 volts to the parallel circuit for some reason the voltage drop to 1.276 or some other number
Hi Alexander, This is a tough question to answer without knowing all of the information related to your circuit. With the limited information that I do know, it sounds like the switch is not only a switch or perhaps the charger has a significant amount of resistance relative to the two resistors in parallel. You will need to check: 1. What the output resistance/impedance of the charger. You may be able to get this by looking at the specifications written on the charger or finding the specifications for the charger online. 2. Obtain the datasheet for the switch and see if there is more to the switch, meaning are there other components in the switch. You will need to obtain the datasheet for the switch to know this. I hope this makes sense. Good Luck!
The only way theoretically that the currents should be the same is if all the resistors in parallel are the exact same value. In a real world experiment if all the parallel resistors are the same value, they will have approximately the same current.
Hi Ami, thank you for asking your question. I believe these videos may be helpful. ua-cam.com/video/gHBqJJQAaOs/v-deo.html and ua-cam.com/video/PGy9ankRawk/v-deo.html
Total current is I1 + I2 + I3 or you can break the circuit after the power supply. You can then test for total current at the break. If this does not make sense submit a question on my website. See this video (ua-cam.com/video/N_vqCYHPlkc/v-deo.html) to understand how to do this.
When measuring the current,can't you,instead of putting another wire where the second "leg" was,just put the multimeter cables on both "legs" of the resistance?
No - You can't do this because the multimeter must be in series with the circuit when taking measurements of current. However you can place the multimeter across both legs when measuring voltage.
![Lp. Сердце Вселенной #60 РОЖДЕНИЕ ЛОЛОЛОШКИ [Финал] • Майнкрафт](http://i.ytimg.com/vi/YoR0pAV9FVQ/mqdefault.jpg)
Thank you so much! My professor didn't explain anything for the labs and I've been stumped!
Thanks a million man. I've been measuring amps wrong for about an hour, you really helped out.
Gotta say this helped me so much for my lab, greatly appreciated!
Glad it helped!
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You are a very good teacher. Thanks.
Thank you Thank you!! I have lab tomorrow and I feel way more confident.
Wonderful!
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Thank you very much, that was so helpful !! My son had a report due and this saved him !!
Awesome! Glad it was helpful.
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jeeesssss. I have been trying to figure this our for 2 hours!!! Thank you!!!!
Glad I could help!
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Thank you so much! This was really helpful !! I finally understand how to do this
Cheers for the Video! Forgive me for the intrusion, I would appreciate your opinion. Have you thought about - Runayslarn Survival Manifestation (probably on Google)? It is a good exclusive guide for discovering how to repair your electronic items without the hard work. Ive heard some awesome things about it and my old buddy Taylor after a lifetime of fighting got cool results with it.
Sir the main thing you do is using less space to make an experiment so if you find a good space and make the video it wouldn't be more clumsy so make sure you have good space
About the explanation part, you are really awesome so that I got a belief that I can rock the exam tomorrow thank you sir.
Thank you for the advice.
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thanks a lot for explaining the concept. You have surely helped a lot of people
Great!
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CAL
Thank you very much! you have solved a problem i'm looking for our an our!!!! no one talks of this on internet
Glad I could help.
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Aye just thank u so much 🥰
Why don't our lab instructors teach this way? 😭
Happy to help.
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Thanks, very easy to understand and straightforward.
thank you so much !! took me forever to find a video like this.
oh thank you man, very nice explained...
Thank you. Please like, share, and subscribe.
This video helped me alot.
Great! Happy to hear that it helped.
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Thank you for your detailed video.
Thank u soo much i was ao confused but u cleared everything very nicely
Have a question? What is the purpose of removing the other end of the resistor to a different hole when checking current?
To break the circuit
so that all electrons flowing through the circuit must also go through the ammeter
Great video! Thank you !
Your welcome! Subscribe and share!
Thanks just helped me out a lot .
No problem 👍
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@@CALettsomePhDPE done
great video, thanks Doc
Very welcome.
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sir, to find I1 we have to break the circuit from the one end of the battery terminal right?
Or would that give the total current?
Thank you so much!! You saved me
thank you for real your videos helped
Thank you very much sir 🙏🏻🙏🏻
You are welcome. Please like, share, and subscribe.
Do it get this right? A resistor is used to control Current?
If so, is there a way to get higher current later on in a circuit again?
I thought it would control the Volt value hehe.
resistor control current in parallel..
resistor control voltage in series..
I wish my Robotics teacher taught like you 😭
Great job!!
Thank you.
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Thanks. Sir im in my first 10 grade and i like to learn more about electric please do more videos on ohms kirchoff lows
hi. i have a question.
when measuring current how do you know how to remove the resistor to measure current? this is bad wording sorry. like sometimes you removed it and left the end jn the open, ither times you moved it a space down. does it result in the same current?
Thanks sir. Nice explain
You are welcome. Please like, subscribe and share.
Sir why do we need to break the circuit to measure current?
the ammeter shorts the resistor. The current will go through the path of least resistance (the ammeter) so you must break the circuit in order to avoid that.
@@mperez7974 you seem to know about this subject ,,, so why would that give any different results than using Ohms Law ? Thank you .
@@humaidalqubaisi9194 it should not.
How did you connect the voltage supply? I dont see any wires going in
this really helped thanx
I am in the infancy stage of Electronics 101. To this point, I need a major clarification on battery voltage. I want to use a 12V battery with a breadboard to closer simulate the 15 volts across the rails on a HO scale track .... My confusion: .... You see many of these tiny, rectangular, 9V batteries being used with breadboards. A riding lawn mower typically has a 12V battery which is considerably larger than the tiny, rectangular 9V battery, yet the voltage comparison is 9V to 12V. Adding to my confusion is a 12V car battery which has the same 12V rating as the riding lawn mower battery, yet the car battery is quite a bit larger and heavier. What am I missing that differentiates between these voltage readings: 9V rectangular battery versus 12V mower battery versus 12V car battery. Thanks!!!
Hi MK Outdoor Adventures, thanks for watching. To ask questions, please go to my website clydelettsome.com and look for the "Ask the Expert" link. That is where I address questions. I typically use this area of UA-cam for comments from viewers. Thanks again.
What caused the electricity to run backwards in that second one?
Hi Aodh! Sorry for the confusion. I am not sure what you mean by run backward. If you mean decreased, that can happen sometimes when the connection is not good and there is a temporary loss of connectivity between components or the multimeter. If you mean change direction (a change from positive to negative or negative to positive), that will only happen if the electricity is AC. I hope this helps. If I did not answer your question, please go to www.clydelettsome.com/blog/ask-the-expert/ and post your question there for a more detail answer. Thanks. Like, subscribe, and share.
@@CALettsomePhDPEThanks, I watched again and I've got it now. My mistake.
Thank you so much Sir.
Good video now i have a better understanding and I also like to know you I did ur board like that with those terminals neat
life saver thank you!
i cant understand where you broke the wire and where you placed it again
This is helping me a lot, but IDK why.. But I have 12 volt in and out and 2 resistors of 100 ohms and when I connect the 12 volts to the parallel circuit for some reason the voltage drop to 1.276 or some other number
Hi Alexander,
This is a tough question to answer without knowing all of the information related to your circuit. With the limited information that I do know, it sounds like the switch is not only a switch or perhaps the charger has a significant amount of resistance relative to the two resistors in parallel.
You will need to check:
1. What the output resistance/impedance of the charger. You may be able to get this by looking at the specifications written on the charger or finding the specifications for the charger online.
2. Obtain the datasheet for the switch and see if there is more to the switch, meaning are there other components in the switch. You will need to obtain the datasheet for the switch to know this.
I hope this makes sense.
Good Luck!
Where can i get a breadboard like the one you have?
A number of companies sell similar boards. You may try Amazon, Digi-key, or Mouser for starters.
Why is ur negative wire (black) measured in the positive side
Or I'm I wrong 🤷♀️🤔
My doubt also that please tell me
It was a jumper cable only.
THANK YOU SO MUCH
You're welcome!
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IDK if anyone can answer this but whenever I measure the current I'm getting the same current though out all the resistors.
The only way theoretically that the currents should be the same is if all the resistors in parallel are the exact same value. In a real world experiment if all the parallel resistors are the same value, they will have approximately the same current.
Sorry sir but how can i know where to put these registers?
Hi Ami, thank you for asking your question. I believe these videos may be helpful. ua-cam.com/video/gHBqJJQAaOs/v-deo.html and ua-cam.com/video/PGy9ankRawk/v-deo.html
sir very nice
How to measure total current?
Total current is I1 + I2 + I3 or you can break the circuit after the power supply. You can then test for total current at the break. If this does not make sense submit a question on my website. See this video (ua-cam.com/video/N_vqCYHPlkc/v-deo.html) to understand how to do this.
Thanks 😊
You are welcome!
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Why voltages were egual to each other
Parallel components have the same voltage across them. This video may help ua-cam.com/video/u3wkDyqCXU0/v-deo.html .
Thank you I wish very much for you
I made 2ohm 10ohm resistors and 10Volt circuit. When I connected only to a 10ohm resistor, it burned out. Why is it?
Bless you
Thank you
7.12 for current
When measuring the current,can't you,instead of putting another wire where the second "leg" was,just put the multimeter cables on both "legs" of the resistance?
No, it will burn the multimeter fuse, because it's in parallel and will make a short circuit
No - You can't do this because the multimeter must be in series with the circuit when taking measurements of current. However you can place the multimeter across both legs when measuring voltage.
Why is your polarity negative
Because the wires are oppositely connected, meaning positive with negative and the negative with the positive.
He held the prongs on the opposite sides. That's why he had -5V. Still correct just point of view
Thanks sir
Ah yes of course 🤔🍷
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What happened to his thumb?
Dont put your fingers in the circuit
thank you ^_^
I can't see what you're doing. I wished you focused in a little more.