Just after 13:22 minutes, I feel, I owe you a nice comment and a like. Now that it is done, let me continue listerning to you up to the end. Thank you for your video.
When discussing translation of per unit impedance from one base to another. Could clarify a lot by stating Actual impedance does not change regardless of base system
Isn't it wrong to cancel kVA & KW @ 18:09 and before that, I mean how can we cancel out apparent power and real power without knowing if ckt is AC or DC? I really don't get it how kW and kVA cancellation is taking place. Sir, please explain.
@@aks5436 (1/6)^2 is a^2......a=turns ratio. To move impedence from the secondary side to the primary side we multiply the impedence on the secondary side by the turns ratio squared
Hi Kingsley. You can use the videos for online courses without any restrictions. Please donate any amount you wish to support my channel. My PayPal link is. paypal.me/pradeepyemula?locale.x=en_GB
thank you so much, actually, your manner is very clear and useful. could you tell me how can I get all lectures about power system analysis presented by you?
Hello sir, In starting of lecture you define per unit as any quantity's value in out of one is per unit but in your starting examples your per unit values exceeds their maximum value i.e. 1! How's this possible?
well explained sir... your videos are great, and easy to understand, Thank you...
Just after 13:22 minutes, I feel, I owe you a nice comment and a like. Now that it is done, let me continue listerning to you up to the end. Thank you for your video.
thanks a lot for your vedio i learn and refresh my mind regarding electrical engineering
PLEASE EXPLAIN (55:25 ) dividing by 6 square
Correct me if wrong- 4kW @0.8pf lag is wrong statement . Correct statement - Load 4kVA@0.8laf :-). many thanks
Excellent of series in EE .God bless you.
When discussing translation of per unit impedance from one base to another. Could clarify a lot by stating
Actual impedance does not change regardless of base system
Thank you so so much for such a brilliant lecture- truly appreciated
Isn't it wrong to cancel kVA & KW @ 18:09 and before that, I mean how can we cancel out apparent power and real power without knowing if ckt is AC or DC? I really don't get it how kW and kVA cancellation is taking place. Sir, please explain.
where did you get the 6 square? i know 6 is the trans ratio.
can you mention at what time in the video is your question about?
Pradeep Yemula hello sir i have a doubt Can i get your email id
@@pradeepyemula6015 55 20
@@aks5436 (1/6)^2 is a^2......a=turns ratio. To move impedence from the secondary side to the primary side we multiply the impedence on the secondary side by the turns ratio squared
Very nice idea having PU system lecteurs , I was stuck until I saw this videos
Thank you sir your lecture is very good
Why is it again the Z actual is divided to 6 squared? please some could tell me because i cant seem to grasp the idea of it.
simply brilliant.
you are an amazing teacher
Thank you Pradeep for your videos. Are there copyright restrictions on their re-use, say to facillitate an online course?
Hi Kingsley. You can use the videos for online courses without any restrictions. Please donate any amount you wish to support my channel. My PayPal link is. paypal.me/pradeepyemula?locale.x=en_GB
nice video thanks sir
Sir....complex power should be in KVA right???
Hi sir, do you have a pdf copy of this lecture?
thnk you very much.
thank you so much, actually, your manner is very clear and useful.
could you tell me how can I get all lectures about power system analysis presented by you?
Get seat in iith
Well Explained
I’m a little bit confused.. are you solving for single phase or three phase ?
Because as i know the apparent power of 3phase = sqrt(3)*|V|*|I|
BTSaddicted this calculation is for 1 phase
I have made a separate video on how to work with per unit system with 3phase. Please search later videos in this playlist.
Pradeep Yemula 👌🏼 thank you so much your videos are helpful
Hello sir,
In starting of lecture you define per unit as any quantity's value in out of one is per unit but in your starting examples your per unit values exceeds their maximum value i.e. 1!
How's this possible?
Sir please upload a video on equal area criterionand, swing equation
i have already uploaded videos on the topic of equal area criteria, kindly search on my channel you will find.
Sir at 29:29 for percentage losses you’ve to multiply by 100 because you said percentage
Please provide more videos sir🙏
thank you sir
Can put be greater than 1