A rectangle’s length is 3 more than twice the width. If the perimeter is 60. What are the L and W?

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[@JoeG2324]

l = length
w = width
l = 2w + 3
2(l) + 2(w) = 60
2(2w + 3) + 2w = 60
4w + 6 + 2w = 60
6w + 6 = 60
-6 -6
6w = 54
w = 9
l = 21

[@trevorbowling3417]

I love algebra and love solving equations. I got this correct. Keeps me sharp.

[@chrisdissanayake6979]

Let the length of the rectangle be L and the width be W.
L= 2W+3--(1)
2L+2W=60--(2)
Substituting for L in the equation (2),
2(2W+3)+2W= 60
4W+6+2W=60
6W=60-6
6W=54
W=9
Substituting in equation (1),
L=(2x9)+3
L=18+3
L=21
The dimensions of the rectangle are:
Length = 21 units.
Width = 9 units.

[@jald910]

Length plus width = 30, so W is width and length is (2W +3). W + 2W + 3 = 30. 3W = 27. W =9 and L = 21.

[@russelllomando8460]

got 9, 21 X and 2X + 3 so 6X + 6 = 60 simple equation thanks for the fun

[@robertperez5983]

Wrong And is 36x 24

[@NerdAlert911]

9x21

[@subasu478]

9 and 21

[@ResourcefulNomad]

L=21
W=9