(L-30) Aldol Condensation || with Mechanism || Aldehyde ketones Chemical Rxn. || NEET JEE
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- Опубліковано 13 жов 2024
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Sir I got 58/60 in organic chemistry test of KCET exam.
Thank you so much sir.
All was possible only bcaz of u👍👍
Are Bhai party de tbb
Congratulations
Wow congratulations
Congratulations 😃😃
Bro which books did u refer?
4-Methyl Pent-3-en-2-one ..From Ketone by "Aldol condensation"
Mesityl oxide
@@Honest_Penaldo_fan Hein ?
@@itzpkg what hein? I said the common name of the compound you wrote
@@Honest_Penaldo_fan I was just kidding...dude
Actually Mene 2 Sal phle comment Kiya tha....or 2 sal bad kisi ne reply Diya ...
Kudos to your attention ‼️❤️
@@itzpkg Ok thanks 😂😂... You are appreciated
Itna quality education to hame kahi par bhi nahi milta even no coaching centre will provide this . Arvind Arora sir to chemistry ke badshah he ❤️ jo sare bharat ku educate karna chahte he.thank u so much sir for your hardwork.
Bhai coaching wala jayada nhi fek diya
@@vishugamer5676 😂😂😂
Lol😂
Bohot badiya sir
बस कर पगले रुलाएगा क्या
*Sir, what I like the most about your videos is that, it is short without compromising the major topics and basics...please keep this pattern in future also!👍*
You taught this wayy better than my PhD professors in university 😃 lots of respect from Pakistan 💚
We learn this in school 🤣🤣🤣🤣🤣,and our competition is way to high,this is considered as trash after JEE exams in college 1st there is whole different thing
@@varnitamishra9491 hehe, we also have to learn this in high school but yeah I never did and always left this topic on choice but in uni's 1st semester, the first topic they taught us was this and I had no choice but to learn🥲🥲
@@Fatimafaisal220 we have no choice to leave any topic in pcm if we are serious jee aspirant
@@varnitamishra9491 what's jee aspirant?
@@Fatimafaisal220 for Engineering
Sir ketone Wala ho gya ... Answer is 4-methyl pent-3-en-2-one #thank_u_sir
That is my answer too
Nice
Sir
Ketones
Magic
A
Raha
Hai
I got the same!!!
Mera bhi 🥳
Same
Ketone wale hi Gaya sir.
Aldol form is 4-hydroxy 4- methyl pentan-2-one.
After condensation, it is 4-methyl pent-3 -en-2 one.
Ncert
Bas galti nikalo
Sir
@@adityaraj9926 hmm
Yes correct. Thanks for mentioning the answer. I was able to check mine. ☺
4 hydroxy 4 methyl pentan2one. (Without heating)
After heat:-
4 methyl pent3 en2one.
We are done in ketone form according to aldol condensation
Have a look on this video too at
ua-cam.com/video/z91KRTmXv9g/v-deo.html
P
P
Hi
Sir I am preparing for GPAT. .and prefer watching your description videos...I love the way you describe sir.....Huge respect....🙏
Sir my answer.......... 4-methylpent-3en-2one. (aldol condensation product)
the ans for aldol condensation of acetons is
( 4-Methyl pent-3-ene-2-one)
ya exactly 👍
Yes sm2u
Same😊
Sir it's ans is before condensation 4 hydroxy 4 methyl pent 2 one and after heating answer is 4 methyl pent 3en 2 one....
Book se koi nhi bta dega
I have done sir and the answer is 4methylPent-3ene-2one.
Thank you sir.
The ans is 4-methyl pent 3-en 2-one. Sry sir thora late Ho gaya. 😀😀
Same..
Same....
Same to you
yeah same😊😊
same
Superb method of teaching.... Love u sir
(CH3)2-C=CH-C=OCH3
Answer 4-methylpent-3-en-2-one
Sir the final product is
4-methyl pent 3-en-2one
adol 4hydroxy 4methyl pent-2-one after heat 4methyl pent 3-en -2one
Sah8 hai
Done sir answer is -4-methy pent-3-en-2-one.
The answer is Mesityl oxide.
4-hydroxy,4-methyl pentane-2-one
For acetone,,,,,,,,4-methyl pent-3-en-2-one ..........
Thankyou so much sir for putting ur immense efforts to teach us! You are the best chemistry teacher across youtube, you work very hard for us! Thankyou again~
#funny
Sir apka jitna sukhriyada karu utna kam hai ap soch nai sakte ap hum jaise gareeb bache jo coaching afford nai sakta unke liye ap kitne bade efforts de rahe hai thank you so much sir
Ans. 4-hydroxy -4-4methyl pentan- 2 one . ... After heat to give :- 4-hydroxy-4-4methyl pent-3- en- 2 one
Ketone -4-methyl pent-3ene-2one
even after three year no one can beat sir in chemistry
change it 4 man
Change it 5
Finally sir mujhe aldol aa gya .... maine bahut teachers se smjhne ki kosis ki but .... but aap se behtrrr koi n smjhaye...apne pura concept hi clear kr diya...thanku sir sooo much🙏🙏🙏
SIR Ketone wala ho gaya.. ans.: 4-METHYLPENT-3-EN-2-ONE...
*THANK YOU SO MUCH SIR😀😀😀😀😀😀😀😀😀😀🤗🤗🤗🤗🤗😊😊😊😊😊😀😀😀😀😀😀😀😀😀*
4 hydroxy 4 methyl pentan 2 one --------------4 methyl pent 3 en 2 one
Sir Ketone wala ho gaya. Sir Andol- 4-hydroxy,4-methyl pentan-2-one. And, After Condensation it becomes 4-methyl pent-3-ene-2-one. Sir Ek question h, Condensation k baad Jo product bana kya hum usko generally Enone bol sakte h.
Aap mechanism bhut deeply or ache se btate ho
4-methyl pent 3-en 2-one😁😁
Sir ans is....4 methyl pent-3-ene-2-one...
Yes sir ho gya... 4 methyl pent-3-en-2-one...
Answer for aldol condensation while using ketone is 4-methyl pent 3-ene 2-anl
(CH3)2-C=CH-CO-CH3
Misityl oxide
@@Crazy_Gamer4855. Now these things don't matter to me, moving forward with coding
Answer of hw question
Mesityl oxide or 4-Methylpent-3-en-2-one
Ketone Ka aldol condensation karka 1st:aldol product is
4-hydroxy-4-methylpentan-2-one
2nd:enal product is
4-methylpent-3-en-2-one
Product is 4-Methyl pent-3-en-2-one.
Thankyou so much sir and team
4 hydroxy 4 mithyl petane 2 one and 4 methyl pent 3ene 2 one
sir ketone wala ho gaya 4Hydroxy-4methyl-pentan-2-one
after condensation(∆) 4Methyl-pent-3-en-2-one
Yes sir done the answer is 4-methylpent-3-en-2-one
Hello sir, i m from pakistan.really in love with ur concepts.all my conceps are covered ur amazing.Love from Pakistan💚💚💚
Loss of hydrogen from alpha position during the loss of water leads to formation of conjugated double bonds which the second reason why hydrogen is released from alpha carbon....nice lecture by the way👍
Thanks sir it really works.
Now i am able to work out the questions.
Well explained.
After condensation 4-methylpent-3-en-2-one
Thank you so much sir🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗
Sir ketone ka solve ho gya h
Ans:- 4-Methylpent-3-en-2-one.
Thank-you very much sir,👍👍👍
ANSWER
4 methyl pent-3-en-2-one
🔴आपसे अच्छी केमिस्ट्री अन्य कोई नहीं पढ़ा सकता। 👍☝️😘👏💝
..........Thank you so much dear sir ji 🙏 Love you.
4-methylpent ,3-en 2-one. Sir I think is the correct answer.
Ho gya sir ketone wala ans 4-Methylpent-3-ene-2-one
Done sir. Ans is 4-methylpent-3-en-2-one
Sir thank u ans is 4methyl pent-3en-2one
Wow very nice method of teaching love u sir 😊❤
Sir ketone wala ho gya
Answer is 4 Hydroxy- 4 methyl pentenon 2
Answer of hw is 4 methyl pent 3-en 2 one
Ketone wala ho gya sir ji thank you so much
Thanks a lot sir I cracked iit because of you.
Ketone product=4-methyl pent-3-en-2-one
Sir ketone wala ho gya mujhse
Product - 4 methylpent-3-en-2-one
Its an aldol condendation product
FOR KETONE PRODUCT IS
4 methyl pent-3 en -2 one
Thank you so much sir board pr smjhane k ly 🙏 ..ap best ho sir🙏❤️
Sir aa gaya ans... 4-methylpent-3-en-2-one
Sir I got 4-methyl pent-3-en-2-one & thank you so much sir 🙂👍
Sir ketone wala ho gaya
Ans: 4-methyl-pent-3-en-2-one
Thanx sir
Done sir..the ans. Is 4methly pent3ene 2one.
Experience is the best teacher sir...👌
Good presentation sir
Ketone waala ho gya pretty much easy🖤
How did the removal of h and oh occur(mechanism)???
Please like so that sir can see this doubt
By heating 🔥
@@aadil77982 thanks
H in the form of H+ leaves and attacks(retention) on OH and creates H2O+ and it leaves takes electron water gets removed and C- and C+ form a bond .....
This is E1 reaction mechanism
Have a look on this video too at
ua-cam.com/video/z91KRTmXv9g/v-deo.html
aap too real guru ji ho
Thank you soo much sir u explained the best nd I was very confused with aldol condensation bt after watching ur video all confusion is gone THANKS AGAIN😀
Yes sir ketone wala ho gaya answer- 4- Methylpent-3-en-2-one and thanks sir
Love you sir 😍 your way of explaining is too good
Have a look on this video too at
ua-cam.com/video/z91KRTmXv9g/v-deo.html
we have done aldol condensation for ketone
I did my homework sr it was quite simple 😊😊😊
ARMY 💜
Ans. 4-Methyl-pent-3-en-2-one
Thankyou so much sir ❣️
bahut aache se samjhaye sir
Sir g u r great
I slove all bsc questions because of ure good lecture
The answer of aldol condensation for ketone is 4 methyl pent 3 ene 2 one
I cleared my homework and I am waiting for your next interesting video cross aldol.
Sir ans nhi aaya
The answer for aldol ketone is ch3-c(ch3)double bond ch-co-ch3..!
Sir u r so nyc
Sir can u upload the vedio on the basis of intramoleculer aldol condensation
Thank you madejee team for their support to coaching free india
Thankyou so much sir, NCERT skipped several steps of this reaction so it was really difficult to understand and remember.
Yaa you are absolutely correct ✌️🤞🥺
4 -methylpentane-3-en-2-one. For acetophenone
Sir question ho gya 👌
🙏Thanks for the effort you make on us, sir
Hey bro can you explain the in dilute naoh is present you know I understand that in naoh oh- is gone for formation of bonding then where is na???
@@DeepakKumar-sf3tuin solution with water
@@DeepakKumar-sf3tuNaOh was base it work was till it gives OH ion not Na
Srr u r only one ☝whose teaching method is much better for us😍😍 Thankuu so much sr 🙏🙏may God bless uh srr🥰🥰🥰
🥰🥰
Thank u sir
Now its easy😀
Ans is 4-methyl pent 3-en 2-ol
Sir can you do a video on Latimer diagram. The question related to it had been asked in NEET 2018
Sir apke ase hi jote jote topic ki vedio bohot achi hai pura smh mae ata hai or ek baat bolu sir koi topic na chore chahe woh topic bache ko aye na naaye