This video shows a simple trick to determine if a molecule is polar or not where the central atom contains 1 lone pair. If you're working on compounds with multiple lone pairs on the central atom, then check this out: ua-cam.com/video/0khykhb3eiQ/v-deo.html Learning General Chemistry? Get your free Study Guide here 👉🏻chemsimplified.newzenler.com/f/gci Want to get your desired grades in Chemistry? Get your free training here 👉🏻 chemsimplified.newzenler.com/fp/taf
You're most welcome! I'm glad the video helped. I posted another video for more complex structures: ua-cam.com/video/0khykhb3eiQ/v-deo.html. Hope it helps. 😊
I have been studying Chemisry by 5 years but i didn't understand polar and non polar But by your video its become very easy to find polar and non polar Good luck 🤞
That's so good to know! By the way, you might want to check this out for structures with multiple lone pairs on the central atom: ua-cam.com/video/0khykhb3eiQ/v-deo.html
This is the best video on UA-cam on this topic. I have just sloved NEET 2021's question with this concept and I have found the answer in just seconds. Thank you so much.❤️
I have a chemistry exam over Molecular Geometry tomorrow and I have been stuck on figuring out whether a molecule is polar or nonpolar for hours. I keep getting told to look at the symmetry of the molecule but this confuses me too much. This way was much easier so thank you!
Yea... I fully understand where you're coming from. I used to struggle with that as well. Glad the video helps. Now, just in case you're going to deal with more complex structures tomorrow in your exam, here's another video that will help: ua-cam.com/video/0khykhb3eiQ/v-deo.html All the best in the exam. Crush it! 🤛🏼💪🏼
You are a very underrated UA-camr! This video helped me a lot, and you need more praise and love for the amazing content that you post! Thank you so much and may your channel have ever-growing success!
I'm glad you found the video helpful. Do share it with your friends who are struggling with the same stuff. You'll also want to check this out for central atom with multiple lone pairs: ua-cam.com/video/0khykhb3eiQ/v-deo.html
My pleasure. By the way, here's another one covering structure with multiple lone pairs: ua-cam.com/video/0khykhb3eiQ/v-deo.html. All the best in your chem test tomorrow!
Hopefully this info will still come in handy for your finals? Yea, using EN and shapes is the "right" way but I find it very challenging for most people. That's why I shared this simplified way. I have another video addressing structures with more than 1 lone pair on the central atom: ua-cam.com/video/0khykhb3eiQ/v-deo.html
That's good to know that this video is helpful. By the way, do check out this other video for structures with multiple lone pairs on the central atom: ua-cam.com/video/0khykhb3eiQ/v-deo.html
Thanks! I appreciate the feedback. I made a more recent video to cover structures with more steric centers: ua-cam.com/video/0khykhb3eiQ/v-deo.html. Do check it out.
You're most welcome! This method works most of the time. You might want to check this other video out for molecules with multiple lone pairs on the central atom : ua-cam.com/video/0khykhb3eiQ/v-deo.htmlsi=9Om0SAZr3pNhvi5k
Thanks! I'm glad you find the videos helpful. The shape of H-S-H is bent or angular. The 2 lone pairs are side by side, making it unsymmetrical. I talk about it here: ua-cam.com/video/0khykhb3eiQ/v-deo.htmlsi=riD6ZuE5db8RGHb3
Hey Leeyah, thanks so much for taking the time to let me know! So glad the video is helping you! By the way, do check this one out for structures with multiple lone pairs : ua-cam.com/video/0khykhb3eiQ/v-deo.html
I was also wondering if you have ANY exceptions to this rule...? If you could tell me what the exceptions are ( by tomorrow I hope ) it would really mean a lot :)
Hi Shaikh, hope my reply is still in time. Your previous comment on the symmetrical electron distribution is the exception to this rule. One that I've found so far is XeF4 where it has 2 lone pairs but it's nonpolar. Another hypothetical exception could be when a tetrahedral, triangular, linear, square planar molecule having different terminal atoms whereby all the terminal atoms have the SAME electronegativity and SAME bond types to the central atom.
Omg did you read my mind?!? All morning I've been on the hunt to find out why on Earth HCN is polar if it has a linear shape....THANK YOU!!!!!!!!!!!!! I'VE GOT IT NOW 😄❤❤❤
Wow! My class was so confusing on this subject it was all over the place and not succinct and there weren't definitive rules to determine polarity and here you have a fast and simple way. I wish they would have posted your video instead of the rambling confusing one I had to watch that just left me frustrated! THANK YOU!
You're most welcome! I'm glad the video helps. Here's another one in case you're working with compounds with higher steric number: ua-cam.com/video/0khykhb3eiQ/v-deo.html Hope your day gets better!
You're most welcome. I'm glad you found the video helpful. Don't forget to check this one out for more complex structures : ua-cam.com/video/0khykhb3eiQ/v-deo.htmlsi=9Om0SAZr3pNhvi5k
thank you very much !!! I was so lucky to find this video! I watched more than 10 videos based on this and this was the perfect one. THANK YOU, ONCE AGAIN !
My pleasure! Here's an updated version: ua-cam.com/video/0khykhb3eiQ/v-deo.html It'll come in handy when dealing with structure with higher steric number.
@@ChemSimplified can you also made a video on how to identify whether a co ordination compound Is square planner or tetrahedral, everytime I get confused whenever question came in exam !!
wow God bless you !! this video helped me sooo much i spent 2 hours trying to figure this out my professors teaching wasnt helping and the other videos on UA-cam werent the least helpful either this one really help me understand in my own level of learning I appreciate you.
You're most welcome! I'm glad this video resonates with you and made it easy to understand. Be sure to check this one out too for structures with multiple lone pairs: ua-cam.com/video/0khykhb3eiQ/v-deo.html&feature=share8 May you nail all the polar or nonpolar questions!
@@ChemSimplified Thank you I will check it out once I’m done with HW. Do you have a video that explains delta notation to indicate the polarity of the bonds. Examples: Si-O P-Ci C-F
@jennifervarela2423 No, I don't and I should make a video on that! Just a quick guide to help, you'll want to place delta + on the atom with lower electronegativity and delta - on the atom with higher electronegativity. In Si-O bond, Si has electronegativity of 1.9 while O is 3.5. Therefore O will be delta - while Si will be delta +. The reason for that is that the atom with higher electronegativity will be able to attract the electron better, therefore making it slightly more negative, thus the delta negative. Hope this helps.
XeF4 is nonpolar because of the distribution of the lone pairs. The trick works, just need to add in the clause on how the lone pairs are distributed: symmetrical distribution of lone pairs = nonpolar, ie, XeF4, XeCl2. nonsymmetrical distribution of lone pairs = polar, ie. H2Se, H2O.
Thanks! I'm very glad I could help. By the way, do check this video out for structures that contain more than 1 lone pair: ua-cam.com/video/0khykhb3eiQ/v-deo.html
Dharchika, When you draw out the Lewis structure of H2O, O is the central atom and the 2 H are the terminal atoms. There will be 2 lone pairs (4 nonbonding electrons) surrounding oxygen. Since there are lone pairs around central atom, it fulfils the criteria for a polar molecule. Hope that clarifies your doubt.
Mais, thanks for asking. XeF4 is one of those rare example that made it through the crack. The reason XeF4 is nonpolar has to do with its geometry. The 2 lone pairs are located 180 degrees of each other with the 4 Fluorines located in a square planar geometry. Because of this arrangement, the electron distribution is symmetrical and therefore making the molecule nonpolar. Most of the common examples where you have 2 lone pairs, they are located right next to each other, in a manner that causes unsymmetrical electron distribution (like in bent/angular geometry), therefore making them polar by default.
@@ChemSimplified Can you go more full in dept about XeF4. This one is confusing because you can put the sahpe like a C2H4 and I would have thought of it as a polar molecule because it has 2 lone pairs ofter doing that. I wash I can show you a picture of what im talking about, but im confused on only that molecule
@@laurettamogekwukooper2188 XeF4 looks like this: www.quora.com/What-is-the-vsepr-structure-of-XeF4 Because the two lone pairs are located opposite of each other at 180 degrees, it makes the electron distribution symmetrical, therefore making the molecule nonpolar.
You are amazing! I was having so much trouble understanding this and it took you less than a minute to explain! I now can determine intermolecular forces too! WOW!!!!
Congrats!!! I'm so glad I could help. Thanks for taking the time to let me know. Truly appreciate it. 😊 Here's another video in case you are working with compounds with higher steric number: ua-cam.com/video/0khykhb3eiQ/v-deo.html
I'm so glad you found it helpful! Don't forget to check this one out for more complex structures : ua-cam.com/video/0khykhb3eiQ/v-deo.htmlsi=9Om0SAZr3pNhvi5k
You're most welcome. You might also want to check this video out in case you're working with structure with multiple lone pairs : ua-cam.com/video/0khykhb3eiQ/v-deo.html&feature=share8
Hi, it was soooooo helpful i was struggling with polarity for about 4 hours, and this 3 minutes video saved my life. I have a question, for the lone pair electrons, is it only one pair or any pairs?
That's great to know! The number of lone pairs and the way the lone pairs are distributed do matter. I talked a little more about that here: ua-cam.com/video/0khykhb3eiQ/v-deo.html Hope that helps. 😊
That's awesome. Glad the video helps. By the way, you might want to check this out too for structures with more than 1 lone pairs: ua-cam.com/video/0khykhb3eiQ/v-deo.html
Keep in mind, the exceptions to this rule is, if the geometrical shape is linear or planar, it is always a non polar molecule. Since the symmetrical shape cancels the dipoles
I'm glad the video is helpful. Do share it with your friends. If you need to classify structures with multiple lone pairs, you can check this one out: ua-cam.com/video/0khykhb3eiQ/v-deo.html
Hey Emily, I'm so glad the video helps. Just in case you need to deal with structures with multiple lone pairs, definitely check this one out: ua-cam.com/video/0khykhb3eiQ/v-deo.html
It's my pleasure, Maria. I'm glad you find the video helpful. Do check this one out too for structures with multiple lone pairs: ua-cam.com/video/0khykhb3eiQ/v-deo.html
Ma'am this is really helpful for me ....my concept is cleared now...thankuuu so much...after 4 video I came through your video and finally this helps🥰❤️❤️.... Love from INDIA🇮🇳
Hi Shaikh, it will work generally for the major contributors of resonance structures, meaning, not the ones with lots of charge separation. All the best in your test!
You're most welcome. By the way, do check this out in case you're working with multiple lone pairs on the central atom : ua-cam.com/video/0khykhb3eiQ/v-deo.html
Hi mam , thnx for the vid , it was quik and simple , just wanted to know , What about compounds like HF , there isn't any central or terminal atom here, but it is Polar , like if I were to consider both these atoms as terminal atoms , obviously they are different , so by the second statement it is Polar , Is this the correct way to take it , or should this question be understood in a different manner ? and again thnx for the vid.......Cheers !
Glad the video helps and thanks for asking such great question. Your hunch is right. There's more to it if you are only looking at 2 atoms in the molecule. In this case, we look at the electronegativity difference between the 2 atoms to figure out the type of bond is present. =0.5 is polar covalent >= 2 is ionic So as long as the electronegativity difference is 0.5 and above, you can classify that molecule as polar. Hope this helps.
Thanks! I'm glad you find this helpful. Don't forget to check this one out for structures with multiple lone pairs : ua-cam.com/video/0khykhb3eiQ/v-deo.htmlsi=9Om0SAZr3pNhvi5k
Thanks, I'm glad the video helps. Just in case you encounter structure with more steric number, do check out this video: ua-cam.com/video/0khykhb3eiQ/v-deo.html All the best in your test tomorrow!
It is... Just that XeF4 has more than 1 lone pairs so we'll need to take note on how they are arranged. I've posted a video on this: ua-cam.com/video/0khykhb3eiQ/v-deo.html Hope that helps.
The reason why C2H5OH is polar is due to the OH group (hydroxyl). Since O is highly electronegative, it creates a large difference in electronegativity difference with H, making the OH bond polar. I'm glad my videos are helpful. Thanks for watching them and I will greatly appreciate it if you share with others who need them. 😊
@@ChemSimplified if it is polar why TiO2 is so behave when it dispersed in non polar oil without any surfactant? Is SiO2 also polar or non polar? Thanks for replying to my comments
You're most welcome. Glad you like it. Don't forget to check this one out too for compounds with more lone pairs: ua-cam.com/video/0khykhb3eiQ/v-deo.htmlsi=9Om0SAZr3pNhvi5k
That's really good to know. By the way, if you're working with multiple lone pairs on central atom, you'll want to check this out: ua-cam.com/video/0khykhb3eiQ/v-deo.html
This video shows a simple trick to determine if a molecule is polar or not where the central atom contains 1 lone pair. If you're working on compounds with multiple lone pairs on the central atom, then check this out: ua-cam.com/video/0khykhb3eiQ/v-deo.html
Learning General Chemistry? Get your free Study Guide here 👉🏻chemsimplified.newzenler.com/f/gci
Want to get your desired grades in Chemistry? Get your free training here 👉🏻 chemsimplified.newzenler.com/fp/taf
Mam where r u from
The vedio was great
Thank u mam👏🏻
All r polar
Thanks! I'm from Malaysia.
You're welcome.
OMG THIS WAS SO MUCH BETTER THAN ALL OF THE OTHERS ON UA-cam THANK YOU SO MUCH!
You're most welcome! I'm glad the video helped. I posted another video for more complex structures: ua-cam.com/video/0khykhb3eiQ/v-deo.html. Hope it helps. 😊
ChemSimplified thank you so much
My pleasure!
Just wanna say a simple and an amazing word " wow"
Thank you!
This helped out a lot, thanks. I have a chemistry test tomorrow and I had no idea how to determine polarity before this video.
Hi Rox, so glad this helps. All the best in your exam tomorrow!
Same here 😢😂
I’m in gen chem 2 in college and out of everything and everywhere I’ve looked this is literally THE MOST HELPFUL VIDEO!!!! Thank you so much!!!!!
Thank you so much, Kenna!!! Your feedback meant a lot. Thanks for taking the time to let me know. I really appreciate it! 😊
Someone finally made it simple and quick 🙌🏻 thank you!!!
Glad it helped!!! 😀
I have been studying Chemisry by 5 years but i didn't understand polar and non polar But by your video its become very easy to find polar and non polar
Good luck 🤞
That's so good to know! By the way, you might want to check this out for structures with multiple lone pairs on the central atom: ua-cam.com/video/0khykhb3eiQ/v-deo.html
You just saved my chemistry grade...THANK YOU!!!!
You are most welcome!!! Happy I could help. 😄
Wow, that would have been helpful in chemistry. It took me way too many videos to find someone to break it down as simply as this. Thank you.
My pleasure! By the way, if you're working with multiple lone pairs, you might want to check this out too: ua-cam.com/video/0khykhb3eiQ/v-deo.html
This is the best video on UA-cam on this topic. I have just sloved NEET 2021's question with this concept and I have found the answer in just seconds.
Thank you so much.❤️
That's awesome! Do check this one out too because in NEET you'll have structures with multiple lone pairs: ua-cam.com/video/0khykhb3eiQ/v-deo.html
I have a chemistry exam over Molecular Geometry tomorrow and I have been stuck on figuring out whether a molecule is polar or nonpolar for hours. I keep getting told to look at the symmetry of the molecule but this confuses me too much. This way was much easier so thank you!
Yea... I fully understand where you're coming from. I used to struggle with that as well. Glad the video helps. Now, just in case you're going to deal with more complex structures tomorrow in your exam, here's another video that will help: ua-cam.com/video/0khykhb3eiQ/v-deo.html All the best in the exam. Crush it! 🤛🏼💪🏼
@@ChemSimplified XeF4 polar or non polar? PLease explain
I talk about structures with multiple lone pairs here: ua-cam.com/video/0khykhb3eiQ/v-deo.html
You are a very underrated UA-camr! This video helped me a lot, and you need more praise and love for the amazing content that you post!
Thank you so much and may your channel have ever-growing success!
Thanks so much for taking the time to feedback. Greatly appreciate it! It will definitely grow with support from you and others.
I don't know if u know this or not but u save 1000s of students every year THNX ALOT!!
You're most welcome and thanks for taking the time to let me know. I'm very glad my videos are helpful. 😉
I just watched a 45 min video describing in a far more complicated way than you did in less than 3 min! Thank you! 🙂
I'm glad you found the video helpful. Do share it with your friends who are struggling with the same stuff. You'll also want to check this out for central atom with multiple lone pairs: ua-cam.com/video/0khykhb3eiQ/v-deo.html
TYSM FOR THIS i have a chem test tomorrow and this will really help me out
My pleasure. By the way, here's another one covering structure with multiple lone pairs: ua-cam.com/video/0khykhb3eiQ/v-deo.html. All the best in your chem test tomorrow!
THANK GOD! If I had known this three hours ago I would not be crying rn. Everyone uses EN charges and shapes but I don't know that! You are AMAZING
Hopefully this info will still come in handy for your finals? Yea, using EN and shapes is the "right" way but I find it very challenging for most people. That's why I shared this simplified way. I have another video addressing structures with more than 1 lone pair on the central atom: ua-cam.com/video/0khykhb3eiQ/v-deo.html
I been hitting my head on this question for months now but u, I so happy that u made this video thanks so much
That's good to know that this video is helpful. By the way, do check out this other video for structures with multiple lone pairs on the central atom: ua-cam.com/video/0khykhb3eiQ/v-deo.html
This is the best video on UA-cam hands down. It's simple, and straight to the point.
Thanks! I appreciate the feedback. I made a more recent video to cover structures with more steric centers: ua-cam.com/video/0khykhb3eiQ/v-deo.html. Do check it out.
Thank you so much!! All the other videos were confusing. This is so much easier.
You are most welcome, Lucky One. I'm so glad it's helpful. 😊
Thank you so much for the simplified explanation. Does this method work for all molecules though?
You're most welcome! This method works most of the time. You might want to check this other video out for molecules with multiple lone pairs on the central atom : ua-cam.com/video/0khykhb3eiQ/v-deo.htmlsi=9Om0SAZr3pNhvi5k
Thanks mam these was the best video to classify whether the molecule is a polar or a non polar.
Thanks! That meant a lot. ☺️
What about H-S-H? it has 2 lone pairs does that make it symmetrical? Love your videos!
Thanks! I'm glad you find the videos helpful.
The shape of H-S-H is bent or angular. The 2 lone pairs are side by side, making it unsymmetrical. I talk about it here: ua-cam.com/video/0khykhb3eiQ/v-deo.htmlsi=riD6ZuE5db8RGHb3
You are an angel, thank you for this amazing tip, it made it wayyy more easier!! ♥️
It's my pleasure. I like to simplify learning where possible. 😀
THIS IS THE BEST EXPLANATION ON THE ENTIRE PLANET THANK U SO MUCH
Hey Leeyah, thanks so much for taking the time to let me know! So glad the video is helping you! By the way, do check this one out for structures with multiple lone pairs : ua-cam.com/video/0khykhb3eiQ/v-deo.html
I was also wondering if you have ANY exceptions to this rule...? If you could tell me what the exceptions are ( by tomorrow I hope ) it would really mean a lot :)
Hi Shaikh, hope my reply is still in time. Your previous comment on the symmetrical electron distribution is the exception to this rule. One that I've found so far is XeF4 where it has 2 lone pairs but it's nonpolar.
Another hypothetical exception could be when a tetrahedral, triangular, linear, square planar molecule having different terminal atoms whereby all the terminal atoms have the SAME electronegativity and SAME bond types to the central atom.
Omg did you read my mind?!? All morning I've been on the hunt to find out why on Earth HCN is polar if it has a linear shape....THANK YOU!!!!!!!!!!!!! I'VE GOT IT NOW 😄❤❤❤
Glad we found each other! 😄 You're most welcome.
this was super helpful!! thank you
You're most welcome, Kelsi!
Wow! My class was so confusing on this subject it was all over the place and not succinct and there weren't definitive rules to determine polarity and here you have a fast and simple way. I wish they would have posted your video instead of the rambling confusing one I had to watch that just left me frustrated! THANK YOU!
You're most welcome! I'm glad the video helps. Here's another one in case you're working with compounds with higher steric number: ua-cam.com/video/0khykhb3eiQ/v-deo.html
Hope your day gets better!
OH MY GOD I LOVE YOU SO MUCH I WAS STRUGGLING SO HARD
Haha... Happy the video helped, Katherine. 😀
OMG THANK YOU SO MUCH! THIS WAS THE MOST CONFUSING CONCEPT FOR ME IN CHEM AND YOU CLEARED IT IN A MINUTE! MUCH LOVE
You're most welcome. I'm glad you found the video helpful. Don't forget to check this one out for more complex structures : ua-cam.com/video/0khykhb3eiQ/v-deo.htmlsi=9Om0SAZr3pNhvi5k
Your nope and yup accent is wowwww😍😍😍
Thank u so much u made our world easiesttttt
You're most welcome! Truly glad the video helped. 😊
thank you very much !!! I was so lucky to find this video! I watched more than 10 videos based on this and this was the perfect one.
THANK YOU, ONCE AGAIN !
My pleasure! Here's an updated version: ua-cam.com/video/0khykhb3eiQ/v-deo.html It'll come in handy when dealing with structure with higher steric number.
thank u queen
My pleasure 😉
I m very glad after watching this video..Now my concepts about polar and non polar molecules are clear... Thanks for your effort..
That's really awesome! I'm glad the video is helpful. It's my pleasure.
What about XeF4 it has lone paise but it is non polar
I talked about it here: ua-cam.com/video/0khykhb3eiQ/v-deo.htmlsi=9Om0SAZr3pNhvi5k
@@ChemSimplified oh , thank you, all cleared !!!
@Tejaswi8955 Awesome!
@@ChemSimplified 😊🥳✌️
@@ChemSimplified can you also made a video on how to identify whether a co ordination compound Is square planner or tetrahedral, everytime I get confused whenever question came in exam !!
wow God bless you !! this video helped me sooo much i spent 2 hours trying to figure this out my professors teaching wasnt helping and the other videos on UA-cam werent the least helpful either this one really help me understand in my own level of learning I appreciate you.
You're most welcome! I'm glad this video resonates with you and made it easy to understand. Be sure to check this one out too for structures with multiple lone pairs: ua-cam.com/video/0khykhb3eiQ/v-deo.html&feature=share8
May you nail all the polar or nonpolar questions!
@@ChemSimplified Thank you I will check it out once I’m done with HW. Do you have a video that explains delta notation to indicate the polarity of the bonds. Examples:
Si-O
P-Ci
C-F
@jennifervarela2423 No, I don't and I should make a video on that!
Just a quick guide to help, you'll want to place delta + on the atom with lower electronegativity and delta - on the atom with higher electronegativity.
In Si-O bond, Si has electronegativity of 1.9 while O is 3.5. Therefore O will be delta - while Si will be delta +.
The reason for that is that the atom with higher electronegativity will be able to attract the electron better, therefore making it slightly more negative, thus the delta negative. Hope this helps.
Mam it doesn't work for all the molecules....if I'm wrong just try for XeF4 compound even though it is non polar...with ur trick it comes polar 😨🤔🤔
XeF4 is nonpolar because of the distribution of the lone pairs. The trick works, just need to add in the clause on how the lone pairs are distributed:
symmetrical distribution of lone pairs = nonpolar, ie, XeF4, XeCl2.
nonsymmetrical distribution of lone pairs = polar, ie. H2Se, H2O.
Thanku mam
No problem 😉
Thankuuuu😢😢😢😢😢😢
You're welcome. 😊
Thank you soooo much!!!!!!!!! This is by far the BEST video on UA-cam!!! You saved my life!
Thanks! I'm very glad I could help. By the way, do check this video out for structures that contain more than 1 lone pair: ua-cam.com/video/0khykhb3eiQ/v-deo.html
@@ChemSimplified checking it out…. ASAP! Thnx again!
My pleasure!
Doubt
How is h2o a polar molecule?
Dharchika,
When you draw out the Lewis structure of H2O, O is the central atom and the 2 H are the terminal atoms. There will be 2 lone pairs (4 nonbonding electrons) surrounding oxygen. Since there are lone pairs around central atom, it fulfils the criteria for a polar molecule.
Hope that clarifies your doubt.
Chem Simplified
Thanks a lot
I forgot to think in that way
You are most welcome.
Omg so much simple and quick. Thank you!!!
Thank you,
But why is XeF4 non-polar?
Though it has 2 pairs of lone electrons?
Mais, thanks for asking.
XeF4 is one of those rare example that made it through the crack. The reason XeF4 is nonpolar has to do with its geometry. The 2 lone pairs are located 180 degrees of each other with the 4 Fluorines located in a square planar geometry. Because of this arrangement, the electron distribution is symmetrical and therefore making the molecule nonpolar.
Most of the common examples where you have 2 lone pairs, they are located right next to each other, in a manner that causes unsymmetrical electron distribution (like in bent/angular geometry), therefore making them polar by default.
@@ChemSimplified Can you go more full in dept about XeF4. This one is confusing because you can put the sahpe like a C2H4 and I would have thought of it as a polar molecule because it has 2 lone pairs ofter doing that. I wash I can show you a picture of what im talking about, but im confused on only that molecule
@@laurettamogekwukooper2188 XeF4 looks like this: www.quora.com/What-is-the-vsepr-structure-of-XeF4
Because the two lone pairs are located opposite of each other at 180 degrees, it makes the electron distribution symmetrical, therefore making the molecule nonpolar.
@@ChemSimplified Oh, ok I see it now. And that goes for it vice versa if a pair was on the left, and another on the right?
@@michaelonyemenam258 Yea what he said
Finally, someone who can explain it in a good and simple way!
Appreciate your feedback. Thanks!
You are amazing! I was having so much trouble understanding this and it took you less than a minute to explain! I now can determine intermolecular forces too! WOW!!!!
Congrats!!! I'm so glad I could help. Thanks for taking the time to let me know. Truly appreciate it. 😊
Here's another video in case you are working with compounds with higher steric number: ua-cam.com/video/0khykhb3eiQ/v-deo.html
Omg thank you ❤️❤️😭 my online Chem class is lacking in explanations. I appreciate this so much!!
Chem test tomorrow and you explained it so simply. Thank you so much!
You are most welcome and all the best in your test tomorrow!
Wow!!! Thank you for showing this simple but very effective way!
My pleasure! Be sure to check this other video out for more complex structures: ua-cam.com/video/0khykhb3eiQ/v-deo.html&feature=share8
Fantastic .. It is very useful trick for my exams...
I'm glad! Don't forget to check this one out too for structures with multiple lone pairs : ua-cam.com/video/0khykhb3eiQ/v-deo.htmlsi=9Om0SAZr3pNhvi5k
One thing I want to say thank you so much maam🙏, you are literally a life saver
You're most welcome. I'm glad I could help when you're in need. 🤗 Do help share the videos with others who need them too. That will mean a lot to me.
SUPER HELPFUL! Absolutely amazed
I'm so glad you found it helpful! Don't forget to check this one out for more complex structures : ua-cam.com/video/0khykhb3eiQ/v-deo.htmlsi=9Om0SAZr3pNhvi5k
I miss you so much. You are the best teacher in my whole life. I wish I can go back to those days
thanks for giving me a really helpful video . i spent almost 2 hours to understand this topic but you make it 1000x easier 🤩
That's really great to know! Thanks for taking the time to feedback. It's my pleasure to help. 😊
Thank you so much! I was having so much trouble understanding polarity/nonpolarity before watching this video :)
You're most welcome. You might also want to check this video out in case you're working with structure with multiple lone pairs : ua-cam.com/video/0khykhb3eiQ/v-deo.html&feature=share8
This saved me! every other video has made this way more complicated than it needed to be
I'm glad the video helps. 😊 Thanks for letting me know. I appreciate that!
Oh my God, you are a lifesaver! Thank you so much! This changes everything
You're most welcome! Glad I could help. 😁
Hi, it was soooooo helpful i was struggling with polarity for about 4 hours, and this 3 minutes video saved my life. I have a question, for the lone pair electrons, is it only one pair or any pairs?
That's great to know! The number of lone pairs and the way the lone pairs are distributed do matter. I talked a little more about that here: ua-cam.com/video/0khykhb3eiQ/v-deo.html
Hope that helps. 😊
I have understand the concept of polar and no-npolar , thanks for you.
But the problem is in biggest compounds.
You are most welcome. You'll need to analyse the larger compounds and unfortunately there's no shortcut for that.
Easy peasy lemon squeeze,,, this helps me a lot ,, save my one hr lecture for this concept thank you love from India,,
That's awesome. Glad the video helps. By the way, you might want to check this out too for structures with more than 1 lone pairs: ua-cam.com/video/0khykhb3eiQ/v-deo.html
Best time saver ever. Thanks
My pleasure. By the way, don't forget to check this out for structures with more than 1 lone pair: ua-cam.com/video/0khykhb3eiQ/v-deo.html
Keep in mind, the exceptions to this rule is, if the geometrical shape is linear or planar, it is always a non polar molecule.
Since the symmetrical shape cancels the dipoles
Very helpful video👍👍 to explain this topic. Thanks ma'am🌼
I'm glad the video is helpful. Do share it with your friends. If you need to classify structures with multiple lone pairs, you can check this one out: ua-cam.com/video/0khykhb3eiQ/v-deo.html
Thanks a lot! Truly! I was totally no idea of these. But then after your description, only a few minutes, I fully understand 😆 really do thanks a lot
You're most welcome. That's really good to know! 😉
i watched 4 videos on it and this was the only one that made sense omg ty so much
Hey Emily, I'm so glad the video helps. Just in case you need to deal with structures with multiple lone pairs, definitely check this one out: ua-cam.com/video/0khykhb3eiQ/v-deo.html
Thank you so much! You just saved me so much time and stress.
You're most welcome. You might also want to check this out for structures with multiple lone pairs: ua-cam.com/video/0khykhb3eiQ/v-deo.html
Thank you so much for keeping it simple! I have watched countless videos and no video explained as simple/well as you did!
It's my pleasure, Maria. I'm glad you find the video helpful. Do check this one out too for structures with multiple lone pairs: ua-cam.com/video/0khykhb3eiQ/v-deo.html
Ma'am this is really helpful for me ....my concept is cleared now...thankuuu so much...after 4 video I came through your video and finally this helps🥰❤️❤️.... Love from INDIA🇮🇳
That's really good to know. I'm glad the videos are helpful and thanks for taking the time to let me know.
No one explained this better than you did. Ty for the video!
It's my pleasure. Thanks for your feedback. 😊
I do not know how to thank you enough. This video makes everything so much easier. Thank you so much!
You are most welcome. It's my pleasure being able to help. 😊
Loved the way you explained thanks loads of love from India 😃
Thanks! I'm glad you like it. By the way, do check this out for structures with multiple lone pairs : ua-cam.com/video/0khykhb3eiQ/v-deo.html
I have test today so hopefully you can reply fast enough!
Does this work with resonance structures?
Hi Shaikh, it will work generally for the major contributors of resonance structures, meaning, not the ones with lots of charge separation.
All the best in your test!
Thank you so much. This video makes it easier than ever
You're most welcome. By the way, do check this out in case you're working with multiple lone pairs on the central atom : ua-cam.com/video/0khykhb3eiQ/v-deo.html
Ty for this concept i was confused but this video cleared my doubts
I'm glad to be of assistance. 😊
Hi mam , thnx for the vid , it was quik and simple , just wanted to know , What about compounds like HF , there isn't any central or terminal atom here, but it is Polar , like if I were to consider both these atoms as terminal atoms , obviously they are different , so by the second statement it is Polar , Is this the correct way to take it , or should this question be understood in a different manner ? and again thnx for the vid.......Cheers !
Glad the video helps and thanks for asking such great question. Your hunch is right. There's more to it if you are only looking at 2 atoms in the molecule. In this case, we look at the electronegativity difference between the 2 atoms to figure out the type of bond is present.
=0.5 is polar covalent
>= 2 is ionic
So as long as the electronegativity difference is 0.5 and above, you can classify that molecule as polar.
Hope this helps.
And by the way, have you seen this one? I talk about classifying molecules with multiple lone pairs: ua-cam.com/video/0khykhb3eiQ/v-deo.html
This so so much easier, you saved me on my first chem exam! Thank you ❤
you are amazing this is so good thank you
Thanks! I'm glad you find this helpful. Don't forget to check this one out for structures with multiple lone pairs : ua-cam.com/video/0khykhb3eiQ/v-deo.htmlsi=9Om0SAZr3pNhvi5k
God bless you you just cleared all my confusion in 3mins wooow
Thank you! Happy to help. By the way, do check this out for structures with multiple lone pairs: ua-cam.com/video/0khykhb3eiQ/v-deo.html
Excellent explanation super trick👍👌🏻👌🏻👌🏻🎉🎉
Thank you! Thank you! 😁
Literally saved me, understand 100% now! THANK YOU SO MUCH :))
That's awesome! Don't forget to check this one out for multiple lone pairs: ua-cam.com/video/0khykhb3eiQ/v-deo.html&feature=share8
Hi!!! I wanted to say how helpful this video was, Thankyou so much! I’m taking my test tmr and this made me feel a lot better!
Thanks, I'm glad the video helps. Just in case you encounter structure with more steric number, do check out this video: ua-cam.com/video/0khykhb3eiQ/v-deo.html
All the best in your test tomorrow!
Thank you so much ma'am
I was looking for this explanation but it was really very good
I'm really glad the video helps. I made another video for more complex structure: ua-cam.com/video/0khykhb3eiQ/v-deo.html Do check it out. 😊
U r great maam ,thanks for clearing my concept
Thanks. I'm glad my video helps. Thanks for letting me know.
Thank u so much i have been struggling so much to identify but this is so much helpful
god bless u
You're most welcome. I'm glad I could help. 😊
Thank you. You saved my life.
I'm glad you clicked on my video 😊
I know I’m late but This helped so much more then the others thank you
thank u mam..u r really a most wanted tutor in this pandemic situation due to our online classes...lots of likes from INDIA
Thank you so much. That meant a lot to me. 😍
This is soo good, I was scratching my head until now
I'm glad I could help. ☺️ If you need to determine structures with higher steric number, here's another video: ua-cam.com/video/0khykhb3eiQ/v-deo.html
Thank you so so much! This helped me pass a test, and it even helped me look smart in front of my crush! Thank you!
That's so awesome!!! 🎉🎊 Congrats on passing your test and more importantly looking good to people that matters to you! 😉
This trick is amazing! But is this trick true for XeF4?
It is... Just that XeF4 has more than 1 lone pairs so we'll need to take note on how they are arranged. I've posted a video on this: ua-cam.com/video/0khykhb3eiQ/v-deo.html Hope that helps.
Can you please explain to me why C2H5OH is polar? Btw ur video helped me A LOT
The reason why C2H5OH is polar is due to the OH group (hydroxyl). Since O is highly electronegative, it creates a large difference in electronegativity difference with H, making the OH bond polar. I'm glad my videos are helpful. Thanks for watching them and I will greatly appreciate it if you share with others who need them. 😊
so helpful, ... what about TiO2? could you please let me know if it is polar or non polar? thank you.
TiO2 is an ionic compound, therefore it is naturally polar.
@@ChemSimplified if it is polar why TiO2 is so behave when it dispersed in non polar oil without any surfactant? Is SiO2 also polar or non polar? Thanks for replying to my comments
I am very happy by clearing my concept about polar or non polar
That's awesome. If you come across structures with multiple lone pairs, do check this out: ua-cam.com/video/0khykhb3eiQ/v-deo.html
Thank you so much! I have a chem test and couldn't understand how to figure out how to determine polarity but when I watched your video it clicked!
That's great! All the best for your exam! In case you encounter more complex structures, do watch this: ua-cam.com/video/0khykhb3eiQ/v-deo.html
Thank you so much mam I finally understood 👍🏻👍🏻👍🏻👍🏻👍🏻
You're most welcome! 😊
Thanks so much - saved me for my chem exam tommorow - love from the UK !
Very glad I could help. All the best in your exam! 💪🏼
it is very easy and simple way. Just tnx very much.
You're most welcome! I'm glad to be able to help and thanks for taking the time to let me know!
OH THIS IS AMAZING!! THANK YOU SOO MUCH ❤
You're most welcome. Glad you like it. Don't forget to check this one out too for compounds with more lone pairs: ua-cam.com/video/0khykhb3eiQ/v-deo.htmlsi=9Om0SAZr3pNhvi5k
Lots of thanks for you Ma'am, you explained it well. Thank you.
My pleasure. I'm glad the video helps. 😊
You explained it so easily. Thank you
Thanks! And you're most welcome. I have a more updated version here : ua-cam.com/video/0khykhb3eiQ/v-deo.html
Thank you!! Its very helpful👍
I'm very glad. By the way, here's another one for structures with more than 1 lone pair on central atom: ua-cam.com/video/0khykhb3eiQ/v-deo.html
This was very simple to understand, thank you.
That's really good to know. By the way, if you're working with multiple lone pairs on central atom, you'll want to check this out: ua-cam.com/video/0khykhb3eiQ/v-deo.html
You solved my problem finally 😍 thank you so much.. stay happy 💓
That's awesome. You too! 😊