Hi, the flat response in the graphs on most pages don't correspond with the BW indication...just on page 12 it is shown right. Otherwise really good...thanks!
Yes - on slide 11 the BW line is in the wrong place (should be to the right) and on slide 9 it's correct for Gaussian but should have moved to the right for Flat. All the other slides are correct. Thanks for letting me know!
Thank you! The bandwidth of a probe is a function of several things, but the attenuation (10x) is not a significant contributor to probe bandwidth in most cases.
@@ゾカリクゾ 10x probes generally have wider bandwidths than 1X probes because the capacitance in the probe tip of a 10x probe helps to cancel out the inherent capacitance of the scope input - it's this capacitance, not the attenuation _per se_ ,that leads to wider bandwidth. Hope that makes sense!
Sir, how does the bandwidth relate to the scope sample rate ? and should the sample rate be at least twice as the bandwidth of the scope ? Thanks Eng.Paul
If you listen to the spoken text (or turn on subtitles), I say "The bandwidth of an oscilloscope is defined as the frequency at which the measured amplitude of a sinusoidal input signal is decreased or attenuated by 3 dB" Since oscilloscopes measure voltage, a 3dB reduction is approximately 70% of the original amplitude (sqrt(2)/2). You're absolutely right that it would make no sense to talk about frequency being decreased by 3 dB :) But I can see where the bullet point might be confusing by itself, so thanks for letting me know!
As per mentioned formula, -3dB = 20 log10(Vout/Vin) 0.7=Vout/Vin This is the standard ratio as it attenuate 3dB. So, if Vin=5v, then Vout=3.5v if Vin=10v, then Vout=7v Then it reduces 30% whatever the input voltage.
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Nice explanation about Bandwidth. Thank you so much!
Really appreciate the comment - thanks!
Hi, the flat response in the graphs on most pages don't correspond with the BW indication...just on page 12 it is shown right. Otherwise really good...thanks!
Yes - on slide 11 the BW line is in the wrong place (should be to the right) and on slide 9 it's correct for Gaussian but should have moved to the right for Flat. All the other slides are correct. Thanks for letting me know!
Hi,
Thank you, that was excellent.
Is the 10x on the probe related to this topic as well? How does it contribute?
Regards.
Thank you! The bandwidth of a probe is a function of several things, but the attenuation (10x) is not a significant contributor to probe bandwidth in most cases.
@@pauldenisowski thank you.
Maybe I'm misunderstanding the comment, but doesn't a 10x probe increase probe bandwidth?@@pauldenisowski
@@ゾカリクゾ 10x probes generally have wider bandwidths than 1X probes because the capacitance in the probe tip of a 10x probe helps to cancel out the inherent capacitance of the scope input - it's this capacitance, not the attenuation _per se_ ,that leads to wider bandwidth. Hope that makes sense!
Thanks for the clarification! Totally clear now.@@pauldenisowski
Great presentation as always, thank you!
Thank you!
Sir, how does the bandwidth relate to the scope sample rate ?
and should the sample rate be at least twice as the bandwidth of the scope ?
Thanks Eng.Paul
Excellent explanation as always. Thank you very much.
Thanks for the feeback!
GREAT presentation, excellent speaker, Thanks
Thank you!
Very useful information.
Thanks!
This is great content
Thanks! There's more oscilloscope-related content coming soon!
Thanks a lot for this video.
Thanks for watching!
Why are you saying that frequency attenuated by 3 dB is (~30%)? WTF!
If you listen to the spoken text (or turn on subtitles), I say "The bandwidth of an oscilloscope is defined as the frequency at which the measured amplitude of a sinusoidal input signal is decreased or attenuated by 3 dB" Since oscilloscopes measure voltage, a 3dB reduction is approximately 70% of the original amplitude (sqrt(2)/2). You're absolutely right that it would make no sense to talk about frequency being decreased by 3 dB :) But I can see where the bullet point might be confusing by itself, so thanks for letting me know!
As per mentioned formula,
-3dB = 20 log10(Vout/Vin)
0.7=Vout/Vin
This is the standard ratio as it attenuate 3dB.
So, if Vin=5v, then Vout=3.5v
if Vin=10v, then Vout=7v
Then it reduces 30% whatever the input voltage.