Complex Numbers 04 | Argument of a Complex Number | Class 11 | JEE | Pace Series
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- Опубліковано 20 вер 2024
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Sir HW question bhannat tarike se solve ho gya.solution-
1) 5π/12
2)-3π/4
Yup! Answer is same
Brother 5π/6 AYEGA na ??
Mujhe samjayega?
7pi/12 hoga bro
@@sonupaswan9099 nhi bhai ans.5π/12 hi hoga
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TIMESTAMPS
0:00 Intro
1:49 Argument of a Complex No.
5:35 Principle Argument
15:04 Question 1
21:21 Question 2
27:07 Question 3
30:13 Questions
34:45 Highlights of Argument
38:20 Properties of Argument
50:18 Outro
Thank you so much bro 😊
49:46
arg(z1)=5pi/12
solution: by solving question
z1 comes _/3 -1 +i(1+_/3 )
TanQ=1+_/3 divided by _/3 -1
Rationalizing it I got 3.732
Which is equal to 5pi/12
Hence arg(z1) = 5pi/12
Could you please tell me how didi you convert 3.732 into 5pi/12
Answer for the homework question:
Arg(Z1)=5π/12
Arg(z2)=-3π/4
General arg(Z1)=5π/12+2kπ
General arg(z2)=-3π/4+2kπ.
Where k € I
Yes
good👍
Bhai kaise plz batao
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15:35
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SIR HOMEWORK QUESTION SOLUTIONS
1.) 5pi/4+2kpi
2.)-3pi/4+2kpi
@AceLer Tanishq why +2kπ here?
First question answer=π/4+π/6 or 5π/12
Second question answer =2kπ-9π/4 or -π/4
Kese kia
At 33:40
Sir wrote wrong
Instead of writing pie by 2 he wrote pie by 6
Yes u are right sir told 2 but write 6 and answer is also pie/2
@@karanbabu2107 wrote*
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Ya
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Yes
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33:39 par sir (Z6)=π/2 aaye ga .
Han sir ne mistake se likh diya π/6..
Aman sir jay ho!!!
No argument
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Principal arg(z) =amp(z)
-π < amp(z) < or = π
Hw que:1=> amp(z1) = 5π/12 at k=0 .... { amp(z1) is invalid for +integers(ans>π) and -integers(ans amp(z2) = -3π/4 at k=0 ...
..{invalid for +Integers(ans >π) and for -Integers(ans
Sir my answers to the homework questions are:
A. 5π/12 radians
B. -3π/4 radians
Thoda late Ho Gaya, par please check kar lijiega.
Please anybody tell if his/her answer matches.
yup my answer is the same!
correct answer
correct answer
Hey, Can u send the solution of the first H.W. from scratch, It would be a great help :)
All basics of argument learned
All concepts understood BHANATLY😉🤟
33:37 sir said π/2 but wrote π/6🙃. No problem insaan se hi galtiya hoti hai😃👍. Best sir in the whole Milky Way Galaxy 🌌✨❤️❤️
h.w question done 1st answer= 5pi/12
2nd question answer=-3pi/4
Can u tell me how didi u convert 3.732 into 5pi/12
Answers of HW questions are
Ans,1=5π/12
Ans.2=-3π/4
Kaise bhai batao
In first question, argument of ( 1+i ) is π/4 and of ( √3+i ) is π/6 . On adding π/4 + π/6 we get 5π/12
In the 2nd example, arg(z2) = 3 x arg ( 1-i) . So we get the ans. as -3π/4
Bhai tu poora formula ka achhe se use kr @@helllegend1579
@@helllegend1579in first question you have left 2kπ
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same...err...1 day left for my last attempt..well..life goes on
33:41
Arg(z) = pie /2
All basic & properties done bhannnatly...👏
HW questions:
(1)Sol:-5π/12+2kπ;k belongs to I
(2)Sol:--3π/4+2kπ;k belongs to I
Yes
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Sir , solved using the properties of arguments
Arg(z1) = 5𝛑 / 12 +2𝛑K
Arg(z2) = -3𝛑 / 4 + 2𝛑K
Here is the solution link
First : drive.google.com/file/d/18jVeeeJbhii9XT-ARHCAIO9MtkEabyhC/view?usp=drivesdk
Second : drive.google.com/file/d/18Y4in2bwA37JqQUxvq6EYNCiaKfS_HFp/view?usp=drivesdk
Thanks Brother ❤️❤️
Thanks brother
Thank you so much 👍🏻
Answer of Homework questions
1)5pi/12
2)--3pi/4
Solved using properties.
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Concepts are crystal clear now.
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Sir H.W question ka Answer: 5π/12 & -3π/4🙃
Nd sir saari properties BHANNAT tarike se yaad hogyi hh 😆🙃
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1. arg(z1)=5π/12
General arg(z1)=5π/12+2Kπ(K belongs to set of all integers)
2. arg(z2)= - 3π/4
General arg(z2)= -3π/4 + 2Kπ (K belongs to set of all integers)
Yeh bhannat maya,
PCB student ko bhi pasand aaya.. 😆
Thank you sir..🙏😁
I understood everything what my teacher couldn't make me in a week😊
Thanks a lot sir best maths sir I have seen in my life till now😊😊😊😊
Bhannat Sir is the best maths teacher alive😁
48:35
All properties of Argument learnt.
1 . arg(z1) = 5 pi/12
2 . arg (z2) = -3pi/4
No
Hii I'm abdurrahman now I'm starting jee preparation and I'm attending his bhannat sir math class and his last two questions I solved and I checked my answer in comment box then I see your answers my answer is also same as your.
@@shaikhking1365 Bahat Badia Bro , Prepare well .All the Best
Short tips for students
If Quadrant -I Re(z) >0 & Im(z)>0
Theta = alpha
If Quadrant -II Re(z) 0
Theta =pi - alpha
If Quadrant -III Re(z)
All Basics of Complex Number is Done.
All Properties Of Argument Is Learn.
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Q.1=z1=(1+i). (√3+i)
=arg(1+i) + arg(√3+i) + 2kπ
=argπ/4 +argπ/6 +2kπ
=5π/12 +2kπ
Q. 2=z2=(1-i)
=3(arg(1-i) +2kπ
3 arg(π/4) +2kπ
= 3π/4+2kπ
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Hw questions:
Arg(z1)=5π/12
Arg(z2)=-π/4.
✌️✌️✌️
Yes it is correct
Homework answer 1 =
arg(Z1) = 5π/12+2kπ
Homework answer 2 =
arg(Z2) = -3π/4+2kπ
Z¹=7π/12
Z² =3π/4
Sir, at 47:47 you said that arg(z) = -arg (z)
If is not on negative real axis.
But I think that this thing is equally valid when z is on positive real axis.
As if z=4 or we can say z= 4 + 0 I.
It's conjugate (z bar) = 4 - 0 I.
Hence, z= z bar .
Exactly ,you are right
@@chaitanyaprasad1016 Thanks
First one is 5π÷12 and 2nd is -3π÷4
33:38 he said π/2 and wrote π/6
1 H.W question ka ans. 5π\12+2kπ,k belongs to integer .2 question ka answer -3π\4+2kπ,k belongs to integer by using 1 and 4 properties of argument respectively.🙂🙂🙂🙂🙂✅✅✅✅done bhannatly
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HW questions
1) 5π/12
2) -3π/4
Homework Question Answers:-
Q1. [(5π)/12]+2πk
Q2. [(3π)/4]+2πk
Same ans.
Answers of h.w questions
Ans. 1= 5π/12 +2kπ ,k belongs to I
Ans. 2= -3π/4 +2kπ ,k belongs to I
😉😉
Correct kr lena Bhailog 34:39 pr arg(z6)=π/2 aur v thodi choti choti mistakes hui h plz ignore them and enjoy the lecture!!
🔥Home work Question Answer is :-
🔴Q1) arg(z1)= 5π/12
🔴Q2)arg(z2)= -3π/4 #Bhannatgang
bhai pls solution bta do
@@visheshgupta640 bhai properties dekhna arg(Z1.Z2) or arg(Z^n) wali ho jaiga bohot easy h
Ans: a_=5pi/12
b_=-3pi/4
Because in _a_,tan(15)=√3+1/√3-1
tan75=5pi/12..............
In _b_,we find z=-2-2i
tanΦ=1then Φ=45 i.e.,pi/4
Due to 3rd quad. Φ=-(pi-pi/4)=-3pi/4........................
B is wrong, ans is -9π/4
O:45 reminded me of carryminati , kaise hai aap log...😂
Exatly...🤣🤣
I was watching this an suddenly I came here to see that is anyone have commented on the kase ho aap log
Homework
1) 5π/12
2) -3π/4
Aaryan
HOMEWORK (QUES 2)::👇👇👇👇👇
drive.google.com/file/d/1FhHzY8VAj2LUxKvc79C5UPmqkLde05jq/view?usp=drivesdk
Your solutions are same as my solutions . But tumko Na thoda aur explanation dalna hoga sol. Me ki konsi property use kri h bcz school me no. Cut ho jate h agr Shi se explain nhi kiya or next year board h to abhi se hi habit me daal lo👍......allover is best 👍🙂🙃
@@pratibhakushwah7445 thanks
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Arg(z1):5pi/12
Arg(z2): -3pi/4
33:37 You said right but wrote wrong it should be π/2
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All properties learn
Ans of hw by using properties
1-) 5π/12 +2kπ
2-) -3π/4 +2Kπ
Sir's today's starting is absolutely very creative as well this new getup......🙂
Kyu chod gaye sir...itna accha padate hoo😭😭😭
Alakh sir ki umaar kitni ho....❤️
👇
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Alakh sir ki video hai
Dekh Lo
Thanks me later ☺☺
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@keval buch Bhai log like he nhi karte😭😭
Answer of homework questions
Question 1=arg(Z1)=5π/12 and answer of question 2
=-3π/4,properties ke maddat se solve kiya aaur solve ho jaya.
Kar bhala to ho bhala!
3rd law of motion in
Alakh sir's language.
Love you Alakh sir and team.
Answer of homework questions
1. arg(Z1) = 5pi/12
2. arg(Z2) = -3pi/4
Oho itni jaldi👍👍
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arg(z1), =5π/12
arg(z2) =-3π/4
Sir I heartly like this lecture and a lot of thanks to you and your team
homework questions : 1] arg [5pi/16] 2] arg[3pi/4] . plz reply sir if my answers are correct
Sir there is so much of clearity after attending this lecture
Thank You Sir
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Answers is 5pi/12 & -3pi/4 respectively . is my ans. is correct sir ?
#Homework_Answer
1. 5π/12 (by first property)
2. -3π/4 (by fourth property)
48:31
All Basics Done bhannatli.
Answer of Homework question
Arg(z1)= 10pie/24
Arg(z2)= -3pie/4
0:49 I got heart attack.
But I am still watching this lecture in heaven
How's the weather up there?
Sir waise to aapne shi kha tha but likhne me mistake ho gya 33:37 min me π/2 hoga.....,. Nice teaching skill sir ji 👍😊❤️
Sir Basic And Formulae Done 👍🏻
Solution to HW Question-
1st HW-- Ans=5pi/12
2nd HW-- Ans=3pi/4
Sir thank you for such an amazing session
HW
IN Q1 USE THE PROPERTY ARG(Z1.Z2) = ARG(Z1) + ARG(Z2) + 2Kπ
IN Q2 USE THE PROPERTY ARG (Z^n) = n.ARG(Z)
👍
Sir arg(z1) = 5π/12 + 2Kπ (K € I)
& arg(z2) = -3π/4 + 2Kπ (K € I)
That's all today's Homework
bhai kasae aaya plz solution bata do?
Sir basics ,properties of mod ,arg,conj
Yad ho gya ek dm BHAAANAAAAATTT tarike ss✌️✌️🙏
15:53
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46:56 if z lies on positive x real axis then also arg z will be equal to arg z conjugate......cause both are 0
Yes, I also think so 👍
Best teacher i have ever come acrossed.
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All basics are done bhhanatly... Thank you so much sir for this quality education.❤️❤️❤️
Arguments clear hai sir....dhanyavad sir
A huge respect to you sir.Your way of teaching Maths is very nice,easy to understand......
nswer of Homework questions
1)5pi/12
2)-3pi/4
Solved using properties.
48:01 sr sb bhannnat clr h bs negative wala confused ho gya 🥺
Edit: lekin maene har nhi mani bar bar dekha ab vo bhi bhannnat clr 👍
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