Complex Numbers 04 | Argument of a Complex Number | Class 11 | JEE | Pace Series

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  • Опубліковано 20 вер 2024
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КОМЕНТАРІ • 1,6 тис.

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      @physcobot7984 3 роки тому +1

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    • @expertsondesk
      @expertsondesk 3 роки тому +1

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      @Aniket.0x0 3 роки тому +13

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      @behindthesean660 2 роки тому +2

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    @blackhawk6349 3 роки тому +42

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    • @akraghav7113
      @akraghav7113 2 роки тому +2

      Tameej se bola kar sir hain wo hamare

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      @blackhawk6349 2 роки тому

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      @parallellinesmeetatinfinity Рік тому +3

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      @akraghav7113 Рік тому

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    @rashmidevi4510 3 роки тому +501

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  • @pranjalyagyasaini690
    @pranjalyagyasaini690 3 роки тому +106

    Sir HW question bhannat tarike se solve ho gya.solution-
    1) 5π/12
    2)-3π/4

  • @rashmisatpathy5127
    @rashmisatpathy5127 3 роки тому +232

    Alakh sir & his team said --- Aap hain to hum hain 🙏
    We said --- No sir, Aap hain to hum hain 🙏, Kyonki aap sabhi humare teacher hain 🙏

  • @AsliTejas
    @AsliTejas 8 місяців тому +20

    TIMESTAMPS
    0:00 Intro
    1:49 Argument of a Complex No.
    5:35 Principle Argument
    15:04 Question 1
    21:21 Question 2
    27:07 Question 3
    30:13 Questions
    34:45 Highlights of Argument
    38:20 Properties of Argument
    50:18 Outro

  • @ranapratap9230
    @ranapratap9230 3 роки тому +24

    49:46
    arg(z1)=5pi/12
    solution: by solving question
    z1 comes _/3 -1 +i(1+_/3 )
    TanQ=1+_/3 divided by _/3 -1
    Rationalizing it I got 3.732
    Which is equal to 5pi/12
    Hence arg(z1) = 5pi/12

    • @Rani-yc3zy
      @Rani-yc3zy 4 місяці тому +1

      Could you please tell me how didi you convert 3.732 into 5pi/12

  • @abhi_2004
    @abhi_2004 3 роки тому +74

    Answer for the homework question:
    Arg(Z1)=5π/12
    Arg(z2)=-3π/4
    General arg(Z1)=5π/12+2kπ
    General arg(z2)=-3π/4+2kπ.

  • @devanshtrivedi3905
    @devanshtrivedi3905 3 роки тому +39

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  • @shivamarora2969
    @shivamarora2969 3 роки тому +26

    15:35
    Here also, Sabse Pehla Kaam : Sundar Diagram.

  • @AmanHouse
    @AmanHouse 3 роки тому +17

    The starting Line By Sir is 1000% true . Small small mistakes makes big Blunder. Same happens with me in class 10 maths exam. Silly mistakes causes my marks to be 85 although 100 marks was damn easy for me. But nothing to be regret, I learned from there and I will not do this again in my 12 and jee. I was too upset after giving my 10th exam but now I am thankful to God that cuz maybe this was been done by God to taught me a lesson that don't repeat again this calculation mistakes in jee.🙏🙏🙏

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    @deepu548 3 роки тому +34

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    @aryanpatel5273 3 роки тому +124

    please bring practice sessions for physics and chemistry also like maths so that we can get an idea of different types of questions

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      @iit-jeemainsadvanced3479 3 роки тому

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    • @physcobot7984
      @physcobot7984 3 роки тому

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    • @pratikgoswamiiitbombay8767
      @pratikgoswamiiitbombay8767 3 роки тому +1

      No

    • @expertsondesk
      @expertsondesk 3 роки тому

      new video for argument of Complex numbers
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  • @kaizokuori2456
    @kaizokuori2456 3 роки тому +9

    SIR HOMEWORK QUESTION SOLUTIONS
    1.) 5pi/4+2kpi
    2.)-3pi/4+2kpi

  • @guidingfriend5531
    @guidingfriend5531 3 роки тому +9

    First question answer=π/4+π/6 or 5π/12
    Second question answer =2kπ-9π/4 or -π/4

  • @darakhshayasmeen
    @darakhshayasmeen 3 роки тому +47

    At 33:40
    Sir wrote wrong
    Instead of writing pie by 2 he wrote pie by 6

  • @wqffeqf
    @wqffeqf 3 роки тому +103

    My friends who r giving jee exam then "All the best ". Bohot mehnat karo bhaiyo

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      @Miraculous_ladynoir499 3 роки тому

      Yes

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      @godson200 3 роки тому +4

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      @aryanpatel5273 3 роки тому +1

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      @JAVPindia0 3 роки тому +1

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      @wqffeqf 3 роки тому

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  • @Usha9392
    @Usha9392 3 роки тому +19

    33:39 par sir (Z6)=π/2 aaye ga .

    • @archiviste
      @archiviste 3 роки тому +3

      Han sir ne mistake se likh diya π/6..

  • @ganeshmishra3717
    @ganeshmishra3717 3 роки тому +35

    Aman sir jay ho!!!
    No argument
    😂😂😂😂

    • @physcobot7984
      @physcobot7984 3 роки тому

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    @sneha__7890 3 роки тому +15

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  • @shrutig4964
    @shrutig4964 3 роки тому +3

    Principal arg(z) =amp(z)
    -π < amp(z) < or = π
    Hw que:1=> amp(z1) = 5π/12 at k=0 .... { amp(z1) is invalid for +integers(ans>π) and -integers(ans amp(z2) = -3π/4 at k=0 ...
    ..{invalid for +Integers(ans >π) and for -Integers(ans

  • @shivamarora2969
    @shivamarora2969 3 роки тому +13

    Sir my answers to the homework questions are:
    A. 5π/12 radians
    B. -3π/4 radians
    Thoda late Ho Gaya, par please check kar lijiega.
    Please anybody tell if his/her answer matches.

  • @saiuttejr
    @saiuttejr 3 роки тому +51

    All basics of argument learned
    All concepts understood BHANATLY😉🤟

  • @padmasangale8194
    @padmasangale8194 Рік тому +18

    33:37 sir said π/2 but wrote π/6🙃. No problem insaan se hi galtiya hoti hai😃👍. Best sir in the whole Milky Way Galaxy 🌌✨❤️❤️

  • @blyezone4430
    @blyezone4430 3 роки тому +5

    h.w question done 1st answer= 5pi/12
    2nd question answer=-3pi/4

    • @Rani-yc3zy
      @Rani-yc3zy 4 місяці тому

      Can u tell me how didi u convert 3.732 into 5pi/12

  • @anshumansingh4725
    @anshumansingh4725 3 роки тому +27

    Answers of HW questions are
    Ans,1=5π/12
    Ans.2=-3π/4

    • @sharpdevilyt8691
      @sharpdevilyt8691 2 роки тому

      Kaise bhai batao

    • @helllegend1579
      @helllegend1579 Рік тому +1

      In first question, argument of ( 1+i ) is π/4 and of ( √3+i ) is π/6 . On adding π/4 + π/6 we get 5π/12
      In the 2nd example, arg(z2) = 3 x arg ( 1-i) . So we get the ans. as -3π/4

    • @ShubhamKumar-ss1tc
      @ShubhamKumar-ss1tc 4 місяці тому

      Bhai tu poora formula ka achhe se use kr ​@@helllegend1579

    • @ShubhamKumar-ss1tc
      @ShubhamKumar-ss1tc 4 місяці тому

      ​@@helllegend1579in first question you have left 2kπ

  • @biswajitsarkar9246
    @biswajitsarkar9246 3 роки тому +17

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      @Roshankumar-kd4uw 3 роки тому

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      @physcobot7984 3 роки тому

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    @SRVGAMING9 3 роки тому +13

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    @VineartCreation 3 роки тому +6

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    • @karantikoo9302
      @karantikoo9302 Рік тому +1

      same...err...1 day left for my last attempt..well..life goes on

  • @A.K_EDITS_007
    @A.K_EDITS_007 2 роки тому +2

    33:41
    Arg(z) = pie /2

  • @manoramabijarniya8674
    @manoramabijarniya8674 3 роки тому +4

    All basic & properties done bhannnatly...👏
    HW questions:
    (1)Sol:-5π/12+2kπ;k belongs to I
    (2)Sol:--3π/4+2kπ;k belongs to I

  • @sudhayarramaneni6257
    @sudhayarramaneni6257 Рік тому +5

    We have to salute to this man for his great and clear cut explanation

  • @deadpoollucky667
    @deadpoollucky667 3 роки тому +9

    In now India online teachers are famous as celebrity.🎉

  • @armaan4529
    @armaan4529 3 роки тому +15

    Sir , solved using the properties of arguments
    Arg(z1) = 5𝛑 / 12 +2𝛑K
    Arg(z2) = -3𝛑 / 4 + 2𝛑K
    Here is the solution link
    First : drive.google.com/file/d/18jVeeeJbhii9XT-ARHCAIO9MtkEabyhC/view?usp=drivesdk
    Second : drive.google.com/file/d/18Y4in2bwA37JqQUxvq6EYNCiaKfS_HFp/view?usp=drivesdk

  • @seemasinghal2976
    @seemasinghal2976 3 роки тому +4

    Answer of Homework questions
    1)5pi/12
    2)--3pi/4
    Solved using properties.

  • @TTT55668
    @TTT55668 3 роки тому +9

    Sir i m really impresed with your teaching really sir great teaching
    Concepts are crystal clear now.
    Thanks sir,🙏🙏

    • @expertsondesk
      @expertsondesk 3 роки тому

      new video for argument of Complex numbers
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    • @expertsondesk
      @expertsondesk 3 роки тому

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  • @Shreyasiiiii
    @Shreyasiiiii 3 роки тому +9

    Sir H.W question ka Answer: 5π/12 & -3π/4🙃
    Nd sir saari properties BHANNAT tarike se yaad hogyi hh 😆🙃

    • @expertsondesk
      @expertsondesk 3 роки тому

      new video for argument of Complex numbers
      ua-cam.com/video/nlmQ8uZQGdQ/v-deo.html

  • @AditiSarkar-vn3nn
    @AditiSarkar-vn3nn 4 місяці тому +1

    1. arg(z1)=5π/12
    General arg(z1)=5π/12+2Kπ(K belongs to set of all integers)
    2. arg(z2)= - 3π/4
    General arg(z2)= -3π/4 + 2Kπ (K belongs to set of all integers)

  • @khushimuley9644
    @khushimuley9644 3 роки тому +7

    Yeh bhannat maya,
    PCB student ko bhi pasand aaya.. 😆
    Thank you sir..🙏😁

  • @gigachad0716
    @gigachad0716 2 роки тому +5

    I understood everything what my teacher couldn't make me in a week😊
    Thanks a lot sir best maths sir I have seen in my life till now😊😊😊😊

  • @_aryan
    @_aryan 3 роки тому +21

    Bhannat Sir is the best maths teacher alive😁

  • @shivamarora2969
    @shivamarora2969 3 роки тому +5

    48:35
    All properties of Argument learnt.

  • @dipalipal3200
    @dipalipal3200 3 роки тому +5

    1 . arg(z1) = 5 pi/12
    2 . arg (z2) = -3pi/4

    • @sayantopics77
      @sayantopics77 Рік тому

      No

    • @shaikhking1365
      @shaikhking1365 Рік тому +1

      Hii I'm abdurrahman now I'm starting jee preparation and I'm attending his bhannat sir math class and his last two questions I solved and I checked my answer in comment box then I see your answers my answer is also same as your.

    • @dipalipal3200
      @dipalipal3200 Рік тому

      @@shaikhking1365 Bahat Badia Bro , Prepare well .All the Best

  • @SainyamThakur
    @SainyamThakur 2 місяці тому +2

    Short tips for students
    If Quadrant -I Re(z) >0 & Im(z)>0
    Theta = alpha
    If Quadrant -II Re(z) 0
    Theta =pi - alpha
    If Quadrant -III Re(z)

  • @sameermaurya4019
    @sameermaurya4019 3 роки тому +6

    All Basics of Complex Number is Done.
    All Properties Of Argument Is Learn.

    • @ayush6570
      @ayush6570 3 роки тому

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  • @raginibharti4087
    @raginibharti4087 3 роки тому +2

    Q.1=z1=(1+i). (√3+i)
    =arg(1+i) + arg(√3+i) + 2kπ
    =argπ/4 +argπ/6 +2kπ
    =5π/12 +2kπ
    Q. 2=z2=(1-i)
    =3(arg(1-i) +2kπ
    3 arg(π/4) +2kπ
    = 3π/4+2kπ

  • @aryansharma6265
    @aryansharma6265 3 роки тому +7

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  • @RavindraSingh-tc8fy
    @RavindraSingh-tc8fy 3 роки тому +5

    Hw questions:
    Arg(z1)=5π/12
    Arg(z2)=-π/4.
    ✌️✌️✌️

  • @aryaman1629
    @aryaman1629 3 роки тому +3

    Homework answer 1 =
    arg(Z1) = 5π/12+2kπ
    Homework answer 2 =
    arg(Z2) = -3π/4+2kπ

  • @sagarjain4128
    @sagarjain4128 2 роки тому +1

    Sir, at 47:47 you said that arg(z) = -arg (z)
    If is not on negative real axis.
    But I think that this thing is equally valid when z is on positive real axis.
    As if z=4 or we can say z= 4 + 0 I.
    It's conjugate (z bar) = 4 - 0 I.
    Hence, z= z bar .

  • @m____i.....8564
    @m____i.....8564 Рік тому +2

    First one is 5π÷12 and 2nd is -3π÷4

  • @theVISHeSH16
    @theVISHeSH16 3 роки тому +5

    33:38 he said π/2 and wrote π/6

  • @pratibhakushwah7445
    @pratibhakushwah7445 3 роки тому +1

    1 H.W question ka ans. 5π\12+2kπ,k belongs to integer .2 question ka answer -3π\4+2kπ,k belongs to integer by using 1 and 4 properties of argument respectively.🙂🙂🙂🙂🙂✅✅✅✅done bhannatly

  • @lllHustler
    @lllHustler 3 роки тому +6

    Best mathematics teacher....on utube

  • @juhisingh2613
    @juhisingh2613 3 роки тому +3

    Best maths teacher i have seen ever

  • @jayminpanchal6442
    @jayminpanchal6442 3 роки тому +11

    Sirrrrr argument ekdum clear ho gaya🔥🔥🔥🔥

  • @devashishramola2923
    @devashishramola2923 3 роки тому +1

    HW questions
    1) 5π/12
    2) -3π/4

  • @gauravendrachaudhary
    @gauravendrachaudhary 3 роки тому +5

    Homework Question Answers:-
    Q1. [(5π)/12]+2πk
    Q2. [(3π)/4]+2πk

  • @AmanSingh-yl3ly
    @AmanSingh-yl3ly 3 роки тому +1

    Answers of h.w questions
    Ans. 1= 5π/12 +2kπ ,k belongs to I
    Ans. 2= -3π/4 +2kπ ,k belongs to I
    😉😉

  • @dadrar1800
    @dadrar1800 3 роки тому +2

    Correct kr lena Bhailog 34:39 pr arg(z6)=π/2 aur v thodi choti choti mistakes hui h plz ignore them and enjoy the lecture!!

  • @harsh_15002
    @harsh_15002 3 роки тому +4

    🔥Home work Question Answer is :-
    🔴Q1) arg(z1)= 5π/12
    🔴Q2)arg(z2)= -3π/4 #Bhannatgang

    • @visheshgupta640
      @visheshgupta640 3 роки тому

      bhai pls solution bta do

    • @whysopuzzled6474
      @whysopuzzled6474 3 роки тому

      @@visheshgupta640 bhai properties dekhna arg(Z1.Z2) or arg(Z^n) wali ho jaiga bohot easy h

  • @ranvir2647
    @ranvir2647 3 роки тому +1

    Ans: a_=5pi/12
    b_=-3pi/4
    Because in _a_,tan(15)=√3+1/√3-1
    tan75=5pi/12..............
    In _b_,we find z=-2-2i
    tanΦ=1then Φ=45 i.e.,pi/4
    Due to 3rd quad. Φ=-(pi-pi/4)=-3pi/4........................

  • @meenakshigupta3221
    @meenakshigupta3221 3 роки тому +5

    O:45 reminded me of carryminati , kaise hai aap log...😂

    • @sushreesaundarya5331
      @sushreesaundarya5331 3 роки тому

      Exatly...🤣🤣

    • @uditgupta5825
      @uditgupta5825 3 роки тому

      I was watching this an suddenly I came here to see that is anyone have commented on the kase ho aap log

  • @aaryan2379
    @aaryan2379 3 роки тому +4

    Homework
    1) 5π/12
    2) -3π/4
    Aaryan

  • @ankitvashist1925
    @ankitvashist1925 3 роки тому +3

    HOMEWORK (QUES 2)::👇👇👇👇👇
    drive.google.com/file/d/1FhHzY8VAj2LUxKvc79C5UPmqkLde05jq/view?usp=drivesdk

    • @pratibhakushwah7445
      @pratibhakushwah7445 3 роки тому +1

      Your solutions are same as my solutions . But tumko Na thoda aur explanation dalna hoga sol. Me ki konsi property use kri h bcz school me no. Cut ho jate h agr Shi se explain nhi kiya or next year board h to abhi se hi habit me daal lo👍......allover is best 👍🙂🙃

    • @ankitvashist1925
      @ankitvashist1925 3 роки тому +1

      @@pratibhakushwah7445 thanks

    • @pratibhakushwah7445
      @pratibhakushwah7445 3 роки тому +1

      @@ankitvashist1925 welcome 🙂😊🙂

  • @RoorkeeyGaming
    @RoorkeeyGaming 2 місяці тому +1

    Arg(z1):5pi/12
    Arg(z2): -3pi/4

  • @harsh_15002
    @harsh_15002 3 роки тому +6

    33:37 You said right but wrote wrong it should be π/2

    • @ayush6570
      @ayush6570 3 роки тому

      If you are preparing JEE/NEET you must watch this video🔥🔥🔥🔥
      👇👇👇👇👇
      ua-cam.com/video/HebDGCMWPPI/v-deo.html

  • @chlhatt3452
    @chlhatt3452 3 роки тому +2

    All properties learn
    Ans of hw by using properties
    1-) 5π/12 +2kπ
    2-) -3π/4 +2Kπ

  • @SRVGAMING9
    @SRVGAMING9 3 роки тому +5

    Sir's today's starting is absolutely very creative as well this new getup......🙂

  • @chupretu1602
    @chupretu1602 3 роки тому +6

    Kyu chod gaye sir...itna accha padate hoo😭😭😭

  • @TanmayPareekOfficial
    @TanmayPareekOfficial 3 роки тому +13

    Alakh sir ki umaar kitni ho....❤️
    👇
    👇

    • @physcobot7984
      @physcobot7984 3 роки тому +1

      Alakh sir ki video hai
      Dekh Lo
      Thanks me later ☺☺
      ua-cam.com/video/7RGi6X-FcN8/v-deo.html
      ua-cam.com/video/7RGi6X-FcN8/v-deo.html
      ua-cam.com/video/7RGi6X-FcN8/v-deo.html

    • @TanmayPareekOfficial
      @TanmayPareekOfficial 3 роки тому

      @keval buch Bhai log like he nhi karte😭😭

  • @krishnamohapatra2432
    @krishnamohapatra2432 3 роки тому +1

    Answer of homework questions
    Question 1=arg(Z1)=5π/12 and answer of question 2
    =-3π/4,properties ke maddat se solve kiya aaur solve ho jaya.

  • @aleejfry
    @aleejfry 3 роки тому +8

    Kar bhala to ho bhala!
    3rd law of motion in
    Alakh sir's language.
    Love you Alakh sir and team.

  • @himanshurajpoot7060
    @himanshurajpoot7060 3 роки тому +3

    Answer of homework questions
    1. arg(Z1) = 5pi/12
    2. arg(Z2) = -3pi/4

  • @divyanshdhiman7028
    @divyanshdhiman7028 2 роки тому +3

    Are all of your maths videos enough for jee mains 2022 ...sir ? ....... you are a best teacher sir .....thank you so much for teach us by online 😇

  • @AshutoshKumar-dn5kq
    @AshutoshKumar-dn5kq 3 роки тому +1

    arg(z1), =5π/12
    arg(z2) =-3π/4

  • @legendaryofficer6960
    @legendaryofficer6960 2 роки тому +5

    Sir I heartly like this lecture and a lot of thanks to you and your team

  • @ultimatetry675
    @ultimatetry675 3 роки тому +2

    homework questions : 1] arg [5pi/16] 2] arg[3pi/4] . plz reply sir if my answers are correct

  • @vanshvadhwa2525
    @vanshvadhwa2525 3 роки тому +4

    Sir there is so much of clearity after attending this lecture
    Thank You Sir

  • @pratikgoswamiiitbombay8767
    @pratikgoswamiiitbombay8767 3 роки тому +2

    Sir please make a video on strategy and books important for self study for jee main and advanced and for neet. Please sir 🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻

  • @aksarkar7794
    @aksarkar7794 Рік тому +3

    Answers is 5pi/12 & -3pi/4 respectively . is my ans. is correct sir ?

  • @SachinKumar-hf7rf
    @SachinKumar-hf7rf 3 роки тому +1

    #Homework_Answer
    1. 5π/12 (by first property)
    2. -3π/4 (by fourth property)

  • @shivamarora2969
    @shivamarora2969 3 роки тому +4

    48:31
    All Basics Done bhannatli.

  • @diyaagrawal5048
    @diyaagrawal5048 3 роки тому +1

    Answer of Homework question
    Arg(z1)= 10pie/24
    Arg(z2)= -3pie/4

  • @manviyadav623
    @manviyadav623 3 роки тому +10

    0:49 I got heart attack.
    But I am still watching this lecture in heaven

  • @10mechalokrawani.48
    @10mechalokrawani.48 3 роки тому +2

    Sir waise to aapne shi kha tha but likhne me mistake ho gya 33:37 min me π/2 hoga.....,. Nice teaching skill sir ji 👍😊❤️

  • @RAJKUMAR-ln9jj
    @RAJKUMAR-ln9jj 3 роки тому +5

    Sir Basic And Formulae Done 👍🏻

  • @lalitasaibe9188
    @lalitasaibe9188 6 місяців тому

    Solution to HW Question-
    1st HW-- Ans=5pi/12
    2nd HW-- Ans=3pi/4
    Sir thank you for such an amazing session

  • @milan7130
    @milan7130 3 роки тому +1

    HW
    IN Q1 USE THE PROPERTY ARG(Z1.Z2) = ARG(Z1) + ARG(Z2) + 2Kπ
    IN Q2 USE THE PROPERTY ARG (Z^n) = n.ARG(Z)
    👍

  • @kunal9450
    @kunal9450 3 роки тому +4

    Sir arg(z1) = 5π/12 + 2Kπ (K € I)
    & arg(z2) = -3π/4 + 2Kπ (K € I)
    That's all today's Homework

  • @RavindraSingh-tc8fy
    @RavindraSingh-tc8fy 3 роки тому +2

    Sir basics ,properties of mod ,arg,conj
    Yad ho gya ek dm BHAAANAAAAATTT tarike ss✌️✌️🙏

  • @rajiblochanpanda3583
    @rajiblochanpanda3583 3 роки тому +5

    15:53
    " Ssamjhau bhi ga " 😂😂😂

  • @manabsaha2733
    @manabsaha2733 3 роки тому +2

    46:56 if z lies on positive x real axis then also arg z will be equal to arg z conjugate......cause both are 0

  • @captaingamer1685
    @captaingamer1685 3 роки тому +3

    Best teacher i have ever come acrossed.

  • @EasyMathematics01
    @EasyMathematics01 2 роки тому +1

    very clear concept sir, watching from Nepal.

  • @ShivamKumar_077
    @ShivamKumar_077 3 роки тому +5

    All basics are done bhhanatly... Thank you so much sir for this quality education.❤️❤️❤️

  • @gayatripriya4838
    @gayatripriya4838 3 роки тому +1

    Arguments clear hai sir....dhanyavad sir

  • @pratiksarkar9785
    @pratiksarkar9785 2 роки тому +4

    A huge respect to you sir.Your way of teaching Maths is very nice,easy to understand......

  • @crazyreshit4667
    @crazyreshit4667 7 місяців тому

    nswer of Homework questions
    1)5pi/12
    2)-3pi/4
    Solved using properties.

  • @A4vinish
    @A4vinish 3 роки тому +4

    48:01 sr sb bhannnat clr h bs negative wala confused ho gya 🥺
    Edit: lekin maene har nhi mani bar bar dekha ab vo bhi bhannnat clr 👍