Thanks for incredibly teaching X-Ray Diffraction and impersonating Christopher Walken at the same time. =)))) That was very refreshing and you're are an incredible instructor. Way to go!
Ok this is a very clear explanation. I'm trying to understand how bragg's law is used to determine the spatial location of atoms in x-ray crystallography and I can't find any videos or guides which attempt to explain this.
There is much space between atoms, so light goes through. Qualitativley It works like slightly silvered mirrors, transparent for some light but also refelecting a part of it. Usually 10^3 to 10^5 layers can interact with the light. If your (nano)crystal is smaller there is less interference and peak broadening is observed as described by the scherrer equation (or williamson hall?) This is just braggs descreption and its liked cause it gives right results. More accurate description goes with the scattering density usually rho(r). The Laue condition (elastic scattering) (G=K=k1-k0) can then be get from the phaseangle between the outgoing light beams to a reference outgoing light beam, and because the scattering desenity is zero nowhere, one can calculate the relative intensity at the place of the observer by integrating |Int(rho(r) exp(-iKr) dr|^2 meaning vectors r and K giving the phaseangle. From Laue you can calculate Bragg. Its the intereferance between the outgoing beams which makes bragg come true. In Beachelor its probably not discussed that way. Lets simply say Bragg gives right results so lets work with it.
bana Ne how did you come up with all this information :) you know i've asked my doctor just about miller indices , he said it works that way don't ask me why!
I mainly used 2 books as i learned this "Ibach, Lüth - Festkörperphysik" and "Charles Kittel - Einführung in die Festkörperphysik" they are german, but there are probably english versions of this books aviable. Imo Kittel is condensed and needs some further reading, this is where i got the silvered mirrors from :) Ibach Lüth treats Interference more preciseley, our Prof. recommended this books. Further phenomenons like interatction with Phonons in inelastic scattering (Stokes, Rayleigh, Anti-Stokes) are also treated and much more. (Deby-Waller Factor, Plasmons,..) Really enjoyed learning this stuff back then.
But the incident and reflected rays are perpendicular to each other only in case that the incident angle is 45°, so what about all the other cases where you cannot use simple Pythagorean geometry?
The angle between the incident light and the bottom plane will also be theta, and from there you can find the angles in the triangle. If I'm not mistaken, that will work for any angle
Many videos just arrive at 2dsin(theta) and then set it equal to n*lambda with no proof. Here a good explanation of WHY this creates the constructive interference. Thanks!
Best explanation on UA-cam I've come across
Fantastic explaination, no ambiguity, Thank you Scott. Please do more stuff on youtube
Literally helped me so much. Just did an experiment analogous to this and you explained it much better than my lab TA. Thank you!
thank you very much sir...when this was taken in class i was just PLING!!!! now all clear...
Thank you so much Sir. You have taken your explanation abilities to a whole different level
Love from India🙏
The best explanation I have heard on UA-cam!!! Thank you so much!
I fully understand what you are saying. Great explanation.
You saved my butt with this. Really well explained in an understandable way. Thank you.
thank you bro. you are better in explanation than my teacher.. i understand it now very well.
cheers!!
crystal clear !
this was great! the best explanation i've found so far
wow the best explanation ive seen so far thank you
best explanation on youtube, thanks
Thank You : )
The explanation was to the point and crystal clear.
Thank you so much. I was trying to figure out Davisson Germer experiment, this has cleared it all up for me. Thank you :)
Well explained and I really understand Bragg's law equation. Thank you so much
An excellent and simple explanation... Thank you
Great video. Will remember it for a while. Thank you kind sire!
Thanks for incredibly teaching X-Ray Diffraction and impersonating Christopher Walken at the same time. =))))
That was very refreshing and you're are an incredible instructor. Way to go!
gr8 work.good explanation.looking forward to more videos
Such a clear and perfect explanation... (y) concept clear.. thankyou sir :)
The best explanation ever!!
Recommended this some of my course mates, great explanation!
thank you so much sir for this very clearly explaination about Bragg diffraction
Awesome way of breaking it down, thanks!
Ok this is a very clear explanation. I'm trying to understand how bragg's law is used to determine the spatial location of atoms in x-ray crystallography and I can't find any videos or guides which attempt to explain this.
Thanks!!
Came for (path and phase difference)!!
Now understood!!😇
So vivid explanation sir
great explanation scotty!!
You explained it super differently clear
Amazing ,Simple and easy
Badass explanation, loved it, thanks....
Perfectly explained!
very nice explanation, thank you sir!
awesome...i feel so good now that i understood that. thank you
Thank you very much sir! That's one great explanation!
This video was great! Thanks.
Excellent work. Thanks
you're a life savior
very good explanation thank you so much
Great lecture. Thanks a lot!
Understood better thanks to this
Thank you very much! Helped me a lot!
Really good explanation, Thanks! :)
could you tell me what is the program that you use in this video :)
thankyou for such great explanation
excellent explanation . thank you very much.
Why does the light travel trough that first layer atom? Should it reflect right away when it hits something?
There is much space between atoms, so light goes through. Qualitativley It works like slightly silvered mirrors, transparent for some light but also refelecting a part of it. Usually 10^3 to 10^5 layers can interact with the light. If your (nano)crystal is smaller there is less interference and peak broadening is observed as described by the scherrer equation (or williamson hall?)
This is just braggs descreption and its liked cause it gives right results. More accurate description goes with the scattering density usually rho(r). The Laue condition (elastic scattering) (G=K=k1-k0) can then be get from the phaseangle between the outgoing light beams to a reference outgoing light beam, and because the scattering desenity is zero nowhere, one can calculate the relative intensity at the place of the observer by integrating |Int(rho(r) exp(-iKr) dr|^2 meaning vectors r and K giving the phaseangle. From Laue you can calculate Bragg. Its the intereferance between the outgoing beams which makes bragg come true. In Beachelor its probably not discussed that way.
Lets simply say Bragg gives right results so lets work with it.
bana Ne how did you come up with all this information :) you know i've asked my doctor just about miller indices , he said it works that way don't ask me why!
I mainly used 2 books as i learned this "Ibach, Lüth - Festkörperphysik" and
"Charles Kittel - Einführung in die Festkörperphysik" they are german, but
there are probably english versions of this books aviable. Imo Kittel is condensed and needs some further reading, this is where i got the silvered mirrors from :)
Ibach Lüth treats Interference more preciseley, our Prof. recommended this books.
Further phenomenons like interatction with Phonons in inelastic scattering (Stokes, Rayleigh, Anti-Stokes) are also treated and much more. (Deby-Waller Factor, Plasmons,..)
Really enjoyed learning this stuff back then.
kerguule simply put, if there ain't nothin' there, it ain't gonna reflect!
Great explanation!
But the incident and reflected rays are perpendicular to each other only in case that the incident angle is 45°, so what about all the other cases where you cannot use simple Pythagorean geometry?
The angle between the incident light and the bottom plane will also be theta, and from there you can find the angles in the triangle. If I'm not mistaken, that will work for any angle
you are right! I was stupid! thank you!
The explanation is awesome! I was looking at 2 pages of text and got nothing.
Many videos just arrive at 2dsin(theta) and then set it equal to n*lambda with no proof. Here a good explanation of WHY this creates the constructive interference. Thanks!
Thanks, Scott!
wow this video is popular! Prof. Ramsay you can totally consider becoming khan-academy-type-youtube-famous XD
why does non constructive not produce a peak? is it because out of phase x rays do not excite the material?
+Indi Sunner Thanks!
It was great! thank you very much:)
Is that diffraction or reflection? diffraction happens when X-ray goes through a slit ?
You’re right that it is diffraction, but we can model it like simple reflection.
very helpful ,thank you very much
Very helpful, thanks!!
you're a star thank you so much
excellent but plz work on atomic scattering factor
Nice explanation
VEry GOOD EXPLANATION!!!!!!!!!!!!!!
Thank you,sir.
Awesome! thank you very much (viewed in 1.25x)
I am not sure that it is correct that you superposition two parallel lines that they never cross each other.
so helpful!
Thank you so so so much!
excellent - thank you
You’re very welcome!
Thanks so much!
thank you so much!!
thank you so much
Thank you
your lambdas look like arrows XD
thank you!
that's very fine
tq
👌
Awesome
Super !
please dont put this on final i beg
Great explanation. Thanks a lot.
Very helpful, thanks!!
Thank you so much!!!
Thank u so much