I'm BACK! Implicit Differentiation Tings! | Tricky A-Level Maths Question #36
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- Опубліковано 7 вер 2024
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beautiful question i beg we get something like this
sir can you please do more hard intergration questions?
Hi sir I think you might have done the first step wrong. I got " 8y(dy/dx)+3 = (dy/dx)6e^(-2x) - 12e^-(2x) --------> simplifying by bringing the 6e^-2x to the left side and the 3 to the right side we end up getting --------- > -(12e^(-2x) - 3)/8y - 6e^(-2x)
They are equivalent. If you times all the terms in the numerator and in the denominator of your expression by negative 1 you will arrive at the expression I had.
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Why does y not equal zero if it crosses axis at 0 because say y was 4 and x was 0 surely it wouldnt then cross y axis at origin?
Sir you are amazing thank you so much! I was curious for differential equations is there sort of a list of equations that we are suppose to know such as volume or surface areas of weird shapes or is it basically GCSE shapes that we are supposed to know? Thank you!!!
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Yesss been waiting for a video
Hi, during part a) I factorised out 6 on the RHS, then divided both sides by 6 before following similar steps to you. If I multiply my answer by (-6) top and bottom I get the exact same final answer.
Would they accept my answer? It does have a fraction on the denominator (4/3y) and the numerator (-1/2), so should I always aim to simplify if this happens?
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can this come up in year 1 maths?
No, this is learnt in year 2
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Ignore what i said lol i just realised, thanks