Euclid's Elements Book 1 - Proposition 35

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  • Опубліковано 15 лис 2024

КОМЕНТАРІ • 8

  • @zachospapazacharias1982
    @zachospapazacharias1982 Рік тому +1

    EXCELLENT!!! THANK YOU! HALO FROM GREECE

  • @bernandb7478
    @bernandb7478 7 років тому +4

    what a clever proof! nice!

  • @kylechurch6296
    @kylechurch6296 6 років тому

    My favourite Euclid video so far.

  • @rtytutut
    @rtytutut 3 місяці тому

    Hi! I enjoy your videos very much. But, I have a question that has been troubling for a while. Why do you say at this point, ie, proposition 35 of book I that the are of a rectangle with sides b and h is bxh? In what way does this formula for the area stems from Euclides axioms? Many thanks on any effort to make this clear. Greetings from Portugal

  • @JohnDanielBryant
    @JohnDanielBryant 5 років тому +1

    This is a pretty cool proof. A small quibble I have is labeling the extra side as delta, since Greek letters are conventionally reserved for angles.

  • @williampeters71
    @williampeters71 4 роки тому

    why cant the line be eb and cf be extended farther increasing the area of the bottom parallelogram
    cbdf keeping adbc constant would they not still have the same base but different area?

  • @CC-gu3ze
    @CC-gu3ze 5 років тому

    Thanks for the video - the translation I am reading is not clear on the definition of equality here (two parallelograms are equal - no mention of area) and if one assumes that equal parallelograms have equal sides and equal angles, this proof make no sense. If AREA is the equality sought, it makes perfect sense.

    • @SandyBultena
      @SandyBultena  5 років тому +1

      I am trying to stay true to Euclid's proofs, and he never ever mentions area. However, all of his proofs make sense when he says a triangle equals another triangle, or a square equals a rectangle, if we assume area.