Local and Absolute Maximum Minimum Differences
Вставка
- Опубліковано 5 бер 2015
- Absolute Maximum and Absolute minimum value for any function continuous in closed interval [a, b] will always exist at the critical numbers or at the end points.
Check the value of the function at the critical numbers and at the end-points to find the result.
Increasing Decreasing Interval Details: • Test Series Increasing...
Steps to find increasing and decreasing interval of any function, f(x), are:
find the first derivative, f'(x)
find critical numbers, f'(x) = 0 or does not exist (DNE)
INTERVAL TABLE TEST:
These critical numbers divide the domain in intervals. Test each interval with a test point.
RESULT:
If f'(x) is greater than 0 then f(x) is increasing.
If f'(x) is less than 0 then f(x) is decreasing.
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That is just a little I can do. Thanks a lot for your appreciation!
Very nice explanation Sir. Thanks 🙏
Its really helpful ...thanks sir..
Thank you very much
I was half my age when this video was uploaded😢
You're so good sir. You're explain like a smart uncle...
Thanku sir
Sir we need to take interval points a and b while finding only local extreme values?
Excellent
THANK YOU
4:43
sir you say "local maxima and manima could also be a absolute maxima and manima " which is wrong .
correctness ..
absolute max and min can also be a local max and min.
I think the sin function has many absolute max and min not only one, do you agree, Thanks
Sine function will have a value of maximum/minimum, however it could be repeated as per the period. Thanks
Sir application of derivatives maxima ,minima and inverse trignometry,continuity as of now
Thanks for undersanding
thank u
Does an absolute maximum have to be a local maximum?
🏆
Lof u
nice
Thanks
Sir can you upload xii cbse videos. Your explanation is great
There are many for xii cbse students. You can search with Anil Kumar Topic Name Playlist to see some related playlist. Also let me know the topics you are interested in; I will provide the list of video. Thanks
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