Error Detection and Correction 1: Internet Checksum
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- Опубліковано 3 гру 2024
- Describes the calculation of the Internet Checksum, which uses repeated ones-complement addition. The checksum approach is a simply way of verifying that data is not corrupted during transmission. Much of this material is based on content from the book Data and Computer Communications by William Stallings.
Why are youtube videos so much clearer and more concise than my lectures. Thank you for this.
This helped a ton. My textbook just glossed over it briefly in words, which was a little confusing. Thanks for taking the time to make this!
The best Internet Checksum video I have seen so far, thanks!
Thank you for explaining the process first, then demonstrating it. Great video!
Great lesson. Very easy to understand.
Great explaination!!!!
Dude, you would make such a great teacher
excellent tutorial, thx !
Great Explaination!
Thanks for the explanation!
Thank you so much for your very helpful videos
My exam is in an hour lol, thanks for the vid
Really love your videos. Very well explained! I'm trying to understand a modulo-2 CRC that has a step in which it says "Form the two’s complement of the remainder." Could you briefly explain what exactly they mean there? Nevermind, I found what I was looking for in another video of yours.
It's now linked from the end card: ua-cam.com/video/6gbkoFciryA/v-deo.html&ab_channel=JacobSchrum
I have one question. When the receiver gets the message, what message he is going to send to the next layer?
For example: Receiver gets this message: D68A AF02 B6AE, he sends to the next layer: D68A AF02?
man you're a life saver!!!! thankk you definitely subscribe
thank you so much sir! easy to understand! was for great help!
thanks, you saved my day
After adding the checksum to thr sum I get 1 extra do this mean my message has error
Thank you!
great explanation
Kindky explain why we get 1C3C2 as the sum of C621 and FdA1?thank you.
it's wrong.
how did you get B6AE from from 1s compliment of 4951??????
Subtract B6AE from FFFF
Thanks for the video. I was confused near the end though, isn't 9A4E+AF02 = 13950, which becomes 3951 after the ones complement? I got this becaues 9+A=19, minus 16=3, carry the one. This leads to a hex sum of C6AE.
You forgot to Carry the one from A+F which become 20 not 19
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At the end, we get FFFF. As far as I know, we`ll have to take one`s complement of FFFF also. The receiver checks the checksum by taking the 1s complement of the sum of the received data (including the checksum) and checking whether the result is all 1 bits. If any of the bits are 0, an error is indicated.
my teacher also taught the same just like you
but how do u calculate to get 1C3C2 as the sum of C621 .your videos dosent show us tht u just show us the answer
Finally, I understood it. Thank you! F in the chat
Thank you
고마워요 형님
헐 한국인이다
thanks.. great help
Thanks a lot!
Ur a god
Thanks!
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did this guy just say F+F = 30
f is 15
Speak up almost completely inaudible