tech geek Hi! Kindly open the subtitles option in video as we have already mentioned a correction i.e. In step 2 we add three alphabets a3=alpha2 * 0, a4= alpha2 * 1, a6'=alpha2 * 2. As alpha2=0, therefore a3=00, a4=01 and a6'=02.
Kindly open the subtitles option in video as we have already mentioned a correction i.e. In step 2 we add three alphabets a3=alpha2 * 0, a4= alpha2 * 1, a6'=alpha2 * 2. As alpha2=0, therefore a3=00, a4=01 and a6'=02.
mam please make a pdf file of all these hand written notes of data compression and provide us download link through google drive. Btw thank you for this awesome content.
Ashish Jha Hi! Just watch the video from starting that there is a condition in non binary Huffman code that m' represent how many symbols are added in first iteration.After that we add according to question.Thanks
Mam please check values of a3, a4
mam if value of α2 is 0 thn how value of a3=20 and a4 =21
in my calculation a3=00 and a4=01
mam plz corrct me if im wrong
tech geek Hi! Kindly open the subtitles option in video as we have already mentioned a correction i.e. In step 2 we add three alphabets a3=alpha2 * 0, a4= alpha2 * 1, a6'=alpha2 * 2. As alpha2=0, therefore a3=00, a4=01 and a6'=02.
Mam, your videos are very helpful in study.. U make every point clear.
Please do make videos on pattern recognition subject also.
Mam, there should be P(a3') = 0.55 instead of 0.45 and C(a3) = 00 instead of 20 . If i am wrong then please correct me.
Bansee Mendapara Hi! We already make correction in video.kindly on the subtitle option,so that u can see the correction.Thanks
Thank you mam
All the videos of your channel it's very helpful
Mam I'm not understand at point :::
P(a'3)= 0.45 or 0.55
&
C (a3)= 20 or 00
C (a4)= 21 or 01
Hello....here I'm getting confused abt two methods arithmetic coding.....which method is to be used when!!
Hi! Actually if you want tag value (decimal value)then you use first method & if u want binary tag value then use scaling method.
Thanks
itechnica Thanks alot and yeah all the videos are very helpful....
please tell me the general procedure for decoding golomb code
harsha dawda Hi! Follow the link- www.chegg.com/homework-help/write-general-procedure-decoding-golomb-code-gm-n-chapter-8-problem-12p-solution-9780131687288-exc
Why Video is not visible clearly.
mam, can this non binary huffman created using tree? can you show to us?
Hi! We can do with the help of tree. Send me ur email I'd ,so that we can provide the solution.
Mam 2 iteration ke baad aapne alpha2 ki value 0 ki jgha 2 q rkha
mam you are tooo good..please upload more videos ..videos are very helpful for us..Doing great job mam..thank-you soo much
shashank shekhar Hi !! Thanks for appreciation !!!
Mam, step 2 me , c(a3)= alpha * 0 =00 and c(a4) = alpha * 1 = 01 nhi aayega??🤔
Siddharth Bhatt Hi! Codeword of a3 & a4 is correct.
But mam there is alpha2=0 so there is maybe alpha2 * 0 = 00 and alpha2 * 1 =01. Mam is it correct???I'm confused about it.🤔🤔
Kindly open the subtitles option in video as we have already mentioned a correction i.e. In step 2 we add three alphabets a3=alpha2 * 0, a4= alpha2 * 1, a6'=alpha2 * 2. As alpha2=0, therefore a3=00, a4=01 and a6'=02.
Ohk mam ,now i got it......thank you mam
mam please make a pdf file of all these hand written notes of data compression and provide us download link through google drive.
Btw thank you for this awesome content.
Instead of 0.45 there will be 0.55
Sahi bole bhai
Ese sikhne ke liye full English ana chahiye ?
Mam, why don't we use ternary code from 1st iterations itself? Thanks for these awesome videos :)
Ashish Jha Hi! Just watch the video from starting that there is a condition in non binary Huffman code that m' represent how many symbols are added in first iteration.After that we add according to question.Thanks
thanks mam its very helpful for exam
Thank you ma'am for this video and some error in this video but I am correction 😊 those point
Guys, ma'am ne confusion Clear krdiya he subtitles me a3 and a4 wala
Too much minutes in this video.. in sum, assign the codes at last😰
confused in the last iteration
Where?