Bjt Transconductance and small signal model explained visually

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References:
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[@fadi5228]

better than 2 hours lecture sir

[@erenjaeger5344]

As an EE student who had these topic last semester, this was actually the best explanation I have seen.

[@nomen_omen]

It's remarkable how you managed to explain a complex problem in such a simple way!

[@proteo-x4u]

I just discovered this video and I can only say one thing: EXCELLENT!

[@abhisheksamal1970]

This is the best explanation....completely refreshed my memories

[@phonix6494]

Finaly someone explaining this topic nicly, really enjoing your videos as an Amateruradio operateur

[@Adhithya2003]

Super good video cleared a lot of things

[@antonioe.2396]

Beautifully explained

[@elhainouni993]

Thank you sir for the high quality

[@willthecat3861]

Technically, non-period signals, cannot be done with Fourier analysis... at least, as the sum of sinusoids. That's limited to functions on a circle... where as the Fourier transform can deal with functions defined on R, (real numbers). For example, the Gaussian, an important non-periodic function in engineering, cannot be represented as the sum of sinusoids.

[@masatoedamura184]

omg I tried to learn this for so long time, but textbooks were too boring! this video is amazing!!! But I still have a hard time to learn transistors. because datasheets have so many graphs in them... Please continue working on this series!

[@arsalansyed4709]

Fantastic, thank you!

[@evaldas2490]

Simply amazing explanation.

[@mohamedriadasbai5176]

Fantastico bravo

[@alvaroaranibar8243]

Increible!

[@tanmoypandey]

It's really interesting the way you simply explain the operation. I have a question : why do we need a dc voltage source e.g Vcc with the collector of the BJT? Thank you and hoping for your reply

[@TheSiGuyEN]

to work as a voltage controlled current source, bjt must work in "the forward active region" . bjt work in the forward active region only if VCE is larger than VBE. so we have a dc voltage source on the collector to make VCE larger than VBE.

[@tanmoypandey]

Would you please make an intuitive video on BJT based switching operation for us?

[@subcom2793]

Is your current source sign not wrong? It should be a dependent source if I am not mistaken which needs a rectangle or diamond shape 🔷

[@TheSiGuyEN]

as long as you know that it is a dependent source, the symbol doesn't matter

[@bradreed2001]

Holy sh*t

[@like_cabezon3810]

the second part of the video is black screen

[@TheSiGuyEN]

yes, thank you for pointing out

[@TheSiGuyEN]

yes, thank you for pointing out

[@Wander4P]

Half the video is missing?

[@TheSiGuyEN]

here is the playlist
ua-cam.com/play/PLMP_edLR-0fYOfxxjBcDehovqL1nNqQna.html

[@TheSiGuyEN]

ok, thank you

[@mejoe444]

What is v_pi ?