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I’d have taken the square root of the square to get back to the original “effective” absolute value.
that has the same problem as the regular absolute value which Eddie mentioned, it is not differentiable at 0
yippee!! you just discovered standard deviation
Which MacBook do you have?
I’d have taken the square root of the square to get back to the original “effective” absolute value.
that has the same problem as the regular absolute value which Eddie mentioned, it is not differentiable at 0
yippee!! you just discovered standard deviation
Which MacBook do you have?