Flexure Formula (Part 1) - Mechanics of Materials

Поділитися
Вставка
  • Опубліковано 19 гру 2024

КОМЕНТАРІ • 76

  • @ismaelmunoz152
    @ismaelmunoz152 7 років тому +5

    appreciate the fact that you sound like a homie rather than an old boring prof. makes me understand things better (:

  • @jazzbuckeye
    @jazzbuckeye 11 років тому +1

    I can't thank you enough for these videos. I usually stare at an awful lecturer or at my Hibbeler book for multiple hours and get nowhere, but this is making my life a lot easier.

  • @goodguyishagoodguy9798
    @goodguyishagoodguy9798 5 років тому +5

    I want to truly thank you, pulling an all nigther, covering weeks of work

  • @structurefree
    @structurefree  11 років тому +38

    I wish I were my prof too.

    • @kennethlian3585
      @kennethlian3585 3 роки тому

      a tip: watch series on Kaldrostream. I've been using them for watching lots of of movies recently.

    • @ralphkai9078
      @ralphkai9078 3 роки тому

      @Kenneth Lian Yea, I've been watching on kaldroStream for since december myself =)

  • @bigboateng2011
    @bigboateng2011 9 років тому +99

    that moment when a free 15mins video explains things better than a paid 1hr lecture

    • @structurefree
      @structurefree  9 років тому +56

      That moment of clarity when all things come together like that first bite of a peanut butter and jelly sandwich and a tall glass of cold milk....well soy milk because....you know. #youknow

    • @Rayquesto
      @Rayquesto 7 років тому +1

      structurefree Yuknows Beyancenulls.

  • @MassiniMonster
    @MassiniMonster 10 років тому +3

    Thank you so much for these videos! My professor is super hard to understand and goes so fast that i feel completely lost in class, but when I watch your videos everything makes sense the first time.

  • @wayupthep0unds
    @wayupthep0unds 9 років тому +1

    I was getting so stressed out because I couldn't get my head around this after my lecture, then I watch this and all my problems were ironed out! Thanks a bunch man!!

  • @rikschoonbeek
    @rikschoonbeek 8 років тому +2

    This is so much easier to digest than those dry textbooks. Much gratitute for putting your stuff online!

  • @jovanilijevski466
    @jovanilijevski466 9 років тому +3

    This is a great explanation of the flexure formula. Thanks man. Greetings from Macedonia. Keep up with the good work.

  • @kenikozo
    @kenikozo 12 років тому +1

    Dude, great videos. I love your attitude! Keep up the great work bro

  • @aahmedbhatti8344
    @aahmedbhatti8344 11 років тому

    You are a Beautiful person...My mechanics prof doesn't speak English so this is amazing

  • @arupkuet
    @arupkuet 7 років тому

    This video is really helpful. It includes figure that's why it seems very easy to understand...

  • @structurefree
    @structurefree  11 років тому

    Thanks for the support, but let's not get carried away here it's just a video on mechanics. Although I would not mind being able to convert water to wine on a regular basis....is there an app for that?

  • @ariefsyahrizal3645
    @ariefsyahrizal3645 5 років тому +1

    Thank U sir.. You explain it so Clearly.

  • @structurefree
    @structurefree  11 років тому +2

    thanks for the comments. It just takes time and Allen Iverson's favorite word.

  • @mxcollin95
    @mxcollin95 4 роки тому

    Awesome channel! So glad I stumbled onto your channel! Thanks for sharing.

  • @JusticeHunter
    @JusticeHunter 9 років тому +3

    thank you very much for the videos and all the effort you put into doing these amazing stuff

  • @structurefree
    @structurefree  11 років тому +3

    no, no, no, you're amazing.

  • @SWCoastBodyboarding
    @SWCoastBodyboarding 6 років тому +2

    To the point and very clear. Thanks!

  • @linsey5627
    @linsey5627 7 років тому +2

    Thank you for this video, it was very helpful!

  • @aprihi
    @aprihi 10 років тому +2

    Thanks a lot sir! This video really helps me! Keep up the good work :)

  • @TheTablamaniac
    @TheTablamaniac 9 років тому +1

    Excellent video. Thanks. I have doubt. If I have a highly elastic beam in pure bending (no shear), until what included angle will the formula for strain (i.e. -y/R) be valid?

  • @shubhamshah6499
    @shubhamshah6499 8 років тому +4

    really sir you are great

  • @53BigNasty
    @53BigNasty 8 років тому +9

    The dude is like a wizard.

  • @reymarkquisel5939
    @reymarkquisel5939 9 років тому +2

    tnx for uploading this video I hope this
    will help me..
    for addition on my knowledge

  • @liamodonnell9091
    @liamodonnell9091 10 років тому +1

    you're such a DON! your videos are targeted towards viewers actually understanding! Thanks so much for these! I hope they stay on youtube for a long time to come!

  • @MisterBinx
    @MisterBinx 8 років тому +4

    This is cool because it's mathematical proof that the top is compressing and the botton side is in tension. In statics it wasn't as obvious to me.

  • @raveenekanayake9494
    @raveenekanayake9494 8 років тому +11

    seriously you should lecture us in the uni!

  • @easyengineering483
    @easyengineering483 7 років тому

    I love your channel

  • @alimorgan3737
    @alimorgan3737 4 роки тому

    Could you tell me any real-life applications of Deformation of a thin plate and/or Linear Elasticity, i already have a condenser microphone and thermoplastic thermoforming
    Thanks

  • @reymarkquisel5939
    @reymarkquisel5939 9 років тому +1

    tnx for uploading this video I hope this will me little bit

  • @tomray4702
    @tomray4702 5 років тому

    for your delta s and delta s', are those values some arbitrary line above the neutral axis or do they represent the section above that line?

  • @zuby555
    @zuby555 12 років тому +1

    Thank you, these videos are really clearing up a few misconception I have had!
    What programs and equipment do you use to produce these videos?

  • @1Motoko
    @1Motoko 11 років тому

    Id rather pay my tuition money to youtube than to my reputable 4 year university...
    Thank you Structurefree.

  • @tara-jodeagle4755
    @tara-jodeagle4755 7 років тому

    My suggestion is that you step away from the book derivation and attempt to derive it by yourself using your own notation; it will involve failing, but that will show you what assumptions they made and what simplifications they stepped into (which you could mention here for completion). That also helped me better explain the buckling formula. Also, you could include an analysis from a meshed FEM software like Abaqus, to show that the assumptions about the 'NA' are incorrect and limit the beam formula in the longitudinal direction (for completion). The limitations of the beam formula should be known to the designer, especially in more complex cross sections (even if prismatic). Local buckling, longitudinally asymmetric elongation, etc. are products of the simplifying assumptions. These concepts give the user a balanced idea of what the beam formula can and cannot do.
    Also, the DelX = p*DelTheta is a geometric property of arc length, not triangles. See: "The angle around a circle can go from 0 to 2 pi radians. The arc segment length is always radius x angle. When the radius is 1, as in a unit circle, then the arc length is equal to the radius."-www.geogebra.org/m/mbzAXPmu
    That property is valid beyond small angles.

  • @rajuthapamagar1438
    @rajuthapamagar1438 8 років тому +4

    The neutral axis you are showing is wrong..its called neutral plane. The neutral axis is along the z axis at each cross section, isn't it???

    • @TheSunshineRequiem
      @TheSunshineRequiem 7 років тому

      that's what i thought, z lying in the plane of the cross section is the neutral axis, x-axis is the longitudinal axis, this is straight from the text book.

  • @yoshitasahishnaa
    @yoshitasahishnaa 9 років тому +2

    in the beginning of the video ... when you mentioned neutral axis.. you actually meant longitudinal axis of the beam. Neutral axis comes only in the cross section right?

    • @structurefree
      @structurefree  9 років тому

      yoshita sahishna technically it's a plane.

  • @فرجبنعمران-ص9س
    @فرجبنعمران-ص9س 6 років тому

    can we say that y/raw is the ratio of change in length and multiply it by the x

  • @andreduplessis8384
    @andreduplessis8384 9 років тому

    Thanks this helps a lot.

  • @diasy77714
    @diasy77714 7 років тому

    Is there anyway you can post your notes from the videos?

  • @vatsaakhil
    @vatsaakhil 7 років тому +2

    If you ever do a MOOC, I'm in.

  • @geezerlb4066
    @geezerlb4066 6 років тому

    amazing content:))

  • @xtcKrauspe
    @xtcKrauspe 11 років тому

    What program are you using to write these tutorials out for us? Looks nice

  • @antreaschatzitofi1614
    @antreaschatzitofi1614 6 років тому

    if the question says compressive stress=45 MPa in my calculations do I have to use positive or negative sign?

  • @dustinbrennan5271
    @dustinbrennan5271 10 років тому +1

    Hey! Great video! I have a question. This derivation shows that strain varies linearly along the cross section. (saying (epsilon)=-y/(rho).) Is this only valid for linear elastic bending or will the section strain graph change from linear to some other shape when it yields? like if for instance a steel beam yielded, would the strain still be linear along the section? Thank you!

    • @structurefree
      @structurefree  9 років тому +1

      Dustin Brennan even if the materials yield, a beam's strain profile still remains linear assuming everything stays connected. The stress profile however would no longer be linear.

    • @structurefree
      @structurefree  9 років тому

      Dustin Brennan Great question!

  • @shaikhshaan8507
    @shaikhshaan8507 8 років тому

    thanks !!!! you easily described it sir :)

  • @johnyjoe2k
    @johnyjoe2k 6 років тому

    But how do you find the radius of curvature???

  • @FelixyzTv
    @FelixyzTv 11 років тому

    you're amazing

  • @willtolife9323
    @willtolife9323 6 років тому

    I still don't understand what it means by linearly

  • @anjleenatufail
    @anjleenatufail 5 років тому

    What is (ro).∆theta ....? Can someone tell me plzzz

    • @structurefree
      @structurefree  5 років тому

      It is the arc length when the angle, deltatheta, is very very small.

    • @anjleenatufail
      @anjleenatufail 5 років тому +1

      @@structurefree thanku 😊

  • @wardiegal8612
    @wardiegal8612 8 років тому +1

    Thank you.

  • @teejar12
    @teejar12 11 років тому

    geez you love dat straight edge XD

  • @PurpleNurpple
    @PurpleNurpple 8 років тому +2

    If you were near me I would kiss your beautiful head in thanks because I'm so happy. Been stuck on this problem for hours because my lecturer never bothered to explain ANY OF THIS!

  • @structurefree
    @structurefree  11 років тому

    fo sho.

  • @RohKage
    @RohKage 8 років тому

    I didn't get the ∆x=(rho).∆(theta)

    • @Aman78628
      @Aman78628 8 років тому +1

      its a formula for finding out the arc length of a circle
      if theta is angle and r is radius then length of curvature\ arc length lets call it S, is given by
      s = r x theta
      if you want proof\ derivation of formula think of it like this
      circumference of whole circle = 2pi x R
      now here 2pi is not just a constant number but it is angle in radians
      so the formula for arc length is S = R x angle(in radians)

    • @SaiKrishna-vz1up
      @SaiKrishna-vz1up 8 років тому +1

      Roh Nain bro it's simple...l=r*thetha is the formula where l is length of arc r is radius and thetha is the angle enclosed by the arc

  • @structurefree
    @structurefree  11 років тому

    word.

  • @cykia3102
    @cykia3102 11 років тому

    wish you were my prof -__-

  • @reymarkquisel5939
    @reymarkquisel5939 9 років тому +1

    upload more videos

  • @amirhossainraju676
    @amirhossainraju676 8 років тому

    Hey dude you sound like Salman khan from khan academy..

  • @aseelremawi481
    @aseelremawi481 10 років тому

    I need lectures in Arabic if I allowed the student of Civil Engineering

  • @danielminch4448
    @danielminch4448 3 роки тому

    You drew left handed axes OOF

  • @danahaddi1358
    @danahaddi1358 8 років тому

    thx dude but please stop using the word " BAMM "

  • @zhilinzhuo7201
    @zhilinzhuo7201 6 років тому

    my prof sucks...