Continuity over an interval | Limits and continuity | AP Calculus AB | Khan Academy
Вставка
- Опубліковано 28 чер 2017
- Courses on Khan Academy are always 100% free. Start practicing-and saving your progress-now: www.khanacademy.org/math/ap-c...
A function Ä is continuous over the open interval (a,b) iff it's continuous on every point in (a,b). Ä is continuous over the closed interval [a,b] iff it's continuous on (a,b), the right-sided limit of Ä at x=a is Ä(a) and the left-sided limit of Ä at x=b is Ä(b).
Watch the next lesson: www.khanacademy.org/math/ap-c...
Missed the previous lesson? www.khanacademy.org/math/ap-c...
AP Calculus AB on Khan Academy: Bill Scott uses Khan Academy to teach AP Calculus at Phillips Academy in Andover, Massachusetts, and heÕs part of the teaching team that helped develop Khan AcademyÕs AP lessons. Phillips Academy was one of the first schools to teach AP nearly 60 years ago.
About Khan Academy: Khan Academy is a nonprofit with a mission to provide a free, world-class education for anyone, anywhere. We believe learners of all ages should have unlimited access to free educational content they can master at their own pace. We use intelligent software, deep data analytics and intuitive user interfaces to help students and teachers around the world. Our resources cover preschool through early college education, including math, biology, chemistry, physics, economics, finance, history, grammar and more. We offer free personalized SAT test prep in partnership with the test developer, the College Board. Khan Academy has been translated into dozens of languages, and 100 million people use our platform worldwide every year. For more information, visit www.khanacademy.org, join us on Facebook or follow us on Twitter at @khanacademy. And remember, you can learn anything.
For free. For everyone. Forever. #YouCanLearnAnything
Subscribe to Khan AcademyÕs AP Calculus AB channel: / channel
Subscribe to Khan Academy: ua-cam.com/users/subscription_...
How would you figure this out algebraically?
Thanks Sir...
Now I'm very clear....... thanks!!!!
Susmita Banerjee nhhhhubvf
Susmita Banerjee Juanmi
Thank you so much
I agree
good explanation
Thanks that really helped
Very cool
Your mom is very cool
Can anyone help me if
(negative infinity, 2] is continuous or not?
I need help in one question. There is an exercise that asks to prove this. Suppose f satisfies the conclusion of the middle value theorem (that in an interval [a,b] f takes every value between f(a) and f(b))and f takes on each value only once (suppose it means a 1-1 function) prove that the function is continuous at [a,b]. Ok it had an ε,δ contradiction proof which made no sense at all. Because it used the middle value theorem WITHOUT knowing that the function is continuous.Circular. Fact is the exercise looks totally wrong, because I can find any function of this kind which is NOT continuous and qualifies. You only have to find a function with no limit at certain x es. (Different - and + limit a x1,x2 etc). And it STILL is 1-1 and takes ALL VALUES between f(a) and f(b).It is a very interesting calculus book that I am studying but either I am missing something or there is a huge mistake. Any help?
google john
Google John
ask in khan academy website
Why last one is not continues?
Becaude the limit of f(x) as x approaches -2 from the right needs to equal the value of f(x) when x is -2, in this case the limit from the right is -3 and the value of the function at x equals -2 is equal to 0 and since they arent equal, It is NOT continues over that closed interval (hope you understand)
Clear and To the point!
Would (3,4) be continuous?
Yes... i think
@sxzm isn't an infinite discontinuity considered discontinuous?
@sxzm wait my answer in my exer just change bc everyone is like telling me that it's still continuous bc of the open interval. since it's not really going to 4 just the points between 3 and 4.
@sxzm the answer sheets is still not released. i'll update if it's already released and anyone is still interested with this conversation
@@uwish5356 what is the answer?
What graph is this
What function did you use
ask in khan academy website
indi tkon ka intindi angud😤
HAHAHAHAH parehas ta dai 😭
1st
You should have solved some problems.
First!
Second
Third
Fifth
Second