Volume of Revolution about the x-axis between curves (2) : ExamSolutions Maths Revision
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- Опубліковано 23 сер 2024
- Revising the volume of revolution about the x axis between curves.
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Since it's an intersection, it'll be much simpler to do it together like π∫ (√x)² − (x²/8)² dx = π [ x²/2 − x⁵/320] definite integral from 0 to 4.
Exactly. But ig if one is a beginner than this video will be much comprehensive for them.
That's wrong, you would get a different answer. You can try it yourself. It works with 2D areas but not with volumes of solids of revolution, hence why he didn't do that
Imagine revolving a unit square that is touching the x-axis around the x-axis, as opposed to rotating a unit square located between y=10 and y=11 around the x-axis. Are you going to get the same shape? No. One is a small cylinder and the other is a large toroid
Cheers you absolute legend :)
how could you tell that volume of curve equals pi integral y squared?
Thank you so much
Thank u soo much sir for this awesome video...
No problem, thanks
can u make finding area under curve
Do you do private tutor
Why don't we find the area of the section enclosed by the two curves by subtracting and then find the volume?
Abdullah you can do, this is just one approach.
Salam, that wouldn't give you the same answer
thanks a lot dude
نو بروب
+سعود الجهني That's okay. Pleased it helped.
I love u 😍
Smash Meda
Hehe wassup Meda
how is 8-16=24???
Its not
If its about the answer here is what i think is happening: ( 8π )- (16π/5 ) We are subtracting a whole number by a fraction so we have to put them both under a common denominator, in this case 5. So it becomes: (40π/5 ) - (16π/5 ) which is why 40 - 16 =24
One person unfortunately has poor fine motor skills.