Hi, Im a PPE student at the university of Nottingham and having not done A level Maths, I was really baffled by all the Maths in Quantitative Economics. I have never commented on a UA-cam video before but I would like to take this opportunity to thank you from the bottom of my heart for all the work you have put it for not only helping A level students but also us university dummies :P. You are a great man. You make the hardest things really really simple. Please keep up the great work! We need more teachers like you. I have started to take interest in Maths after such a long time. You are the best. Gratitude Sultan F. Iqbal
its just amazing that i pay so much money for college and i dont get shit from it while 7 minute tutorial taught me everything i need to know in that 2 hour classroom. Thanks
Thank you for all the hard work you put in for these videos. I missed a lot of math classes due to some genuine reasons but had noone at school to help. Bless you and your site, as it is saving my life.
I recall from one of your C2 videos that when doing something like dt/dx you do dx/dt then do the inverse im not 100% sure If you understand what I mean will you please shed some light to it please
+Christian Davies I solved it and I'm almost 80% sure of my answer, I took it as y=1(x^2+19x-4)^1/2 and I considered that (x^2+19x-4) as t and solved it normally using the chain rule, that is.. dy/dx= [1/2(x^2+19x-4)^-1/2]* (2x+19) so you get the answer as dy/dx=[(2x+19)/2]*(x^2+19x-4).
Wow Damn !!!!!!! I can finally understand the chain rule using your chain rule method. It has real helped me understand this concept, as calculus is very important in university and understanding the basics are very important before you build. thanks for saving my life as my exam is in 3 days time and I'm much more confident
Hi, Im a PPE student at the university of Nottingham and having not done A level Maths, I was really baffled by all the Maths in Quantitative Economics. I have never commented on a UA-cam video before but I would like to take this opportunity to thank you from the bottom of my heart for all the work you have put it for not only helping A level students but also us university dummies :P. You are a great man. You make the hardest things really really simple. Please keep up the great work! We need more teachers like you. I have started to take interest in Maths after such a long time. You are the best.
Gratitude
Sultan F. Iqbal
+Sultan Iqbal Thank you for your comments. May you go from strength to strength now. Take care.
wallah wa7sh!
its just amazing that i pay so much money for college and i dont get shit from it while 7 minute tutorial taught me everything i need to know in that 2 hour classroom. Thanks
You make one of the hardest things in the world seem easy, awesome teacher!!
You’re a legend
Thank you.
Thank you for all the hard work you put in for these videos. I missed a lot of math classes due to some genuine reasons but had noone at school to help. Bless you and your site, as it is saving my life.
I love this.. nice nice.. thanks a lot..
thank you for this, very helpful for remembering past knowledge!
Yes dy/dx = 1 / [dx/dy] I can't really say much more but learn this method.
am really starting to like maths, but that doesn't mean that i have stopped hating on whoever invented it. you are an awesome teacher
gerald jack Thank you and good luck on your journey.
Cheers
I wanted the simplified term.
This is really good ... the way I do it is differentiate the inside bit first then the outside and it gives the same answer ^^
Thank u
I already had a good understanding of the chain rule but this helps. Thanks!
That's good. Best wishes.
Wierd flex but ok
Best explaination ever loved it
I recall from one of your C2 videos that when doing something like dt/dx you do dx/dt then do the inverse im not 100% sure
If you understand what I mean will you please shed some light to it please
How come you didn't expand answer to the fiest question? Can I leave my answers like that?
Hi could you help me out please, having some trouble with a question.
y=(x^2+19x-4)^1/2
finding it difficult to clean it up towards the end.
Christian Davies Try posting on here facebook.com/groups/mathsrevision.examsolutions/ for an answer
Thank you
+Christian Davies I solved it and I'm almost 80% sure of my answer, I took it as y=1(x^2+19x-4)^1/2 and I considered that (x^2+19x-4) as t and solved it normally using the chain rule, that is.. dy/dx= [1/2(x^2+19x-4)^-1/2]* (2x+19) so you get the answer as dy/dx=[(2x+19)/2]*(x^2+19x-4).
still searching youtube for maths help? are the videos from 2006 really helping?
I hope so.
@@ExamSolutions_Maths It is useful cheers mate
Can't we use the product rule?
Wow Damn !!!!!!! I can finally understand the chain rule using your chain rule method. It has real helped me understand this concept, as calculus is very important in university and understanding the basics are very important before you build. thanks for saving my life as my exam is in 3 days time and I'm much more confident
Thnx yaar
I love this. thank you so much
yh where is it
Big thumbs up...you are really great :)
Thank you very much, very helpful :)
That's okay, thanks for watching. Best wishes.
Thank you
Thank you
You are more than welcome. Best wishes.
thanks!!!
Thanks dude!! You help me alot :) 100000000 Likes and Subscribe for you!!