Implementing an OAuth 2 authorization server with Spring Security - the new way! by Laurentiu Spilca

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  • Опубліковано 19 лис 2024

КОМЕНТАРІ • 54

  • @joshzoolian7821
    @joshzoolian7821 Рік тому +10

    In looking through dozens of sites advising on this topic, it was super handy hearing him mention deprecated methods and implementations

  • @HenrryWith2Rs
    @HenrryWith2Rs 2 роки тому +10

    I love this guys channel. He really knows his stuff.

  • @adrianstefan1814
    @adrianstefan1814 11 місяців тому

    Laur is a great teacher. I learned a lot from him!

  • @arulmurugansubramaniam8452
    @arulmurugansubramaniam8452 2 роки тому +3

    How are you generation code verifier?

  • @alxdm9760
    @alxdm9760 2 роки тому +3

    what about if i dont want jwt tokens? just like the old way which is using opaque token, is it possible? especially if the auth server and reaource server are in one project? hope you can have a demo

  • @donnerlucky
    @donnerlucky 2 роки тому +1

    Great Explanation of OAUTH .......

  • @nihmathaafiya9693
    @nihmathaafiya9693 Рік тому +3

    I'm a beginner, I'm not really sure as to how that code_challenge was generated, can someone explain it?

    • @jofrantoba
      @jofrantoba Рік тому

      public static void main(String[] args) throws NoSuchAlgorithmException {
      SpringApplication.run(Application.class, args);
      String codeVerifier=createCodeVerifier();
      log.info("code verifier:"+codeVerifier);
      log.info("code_challenge:"+createCodeChallenge(codeVerifier));
      }

      private static String createCodeChallenge(String value) throws NoSuchAlgorithmException {
      MessageDigest md = MessageDigest.getInstance("SHA-256");
      byte[] digest = md.digest(value.getBytes(StandardCharsets.US_ASCII));
      return Base64.getUrlEncoder().withoutPadding().encodeToString(digest);
      }

      private static String createCodeVerifier(){
      StringKeyGenerator secureKeyGenerator =
      new Base64StringKeyGenerator(Base64.getUrlEncoder().withoutPadding(), 96);
      return secureKeyGenerator.generateKey();
      }

  • @ridhopratama9639
    @ridhopratama9639 9 місяців тому

    Help. It is statefull, isn't it?? because no sessionCreationPolicy configuration written. like customizer.sessionCreationPolicy(SessionCreationPolicy.STATELESS)

  • @rahmonaliyoqubov
    @rahmonaliyoqubov 2 роки тому +2

    Hi. Can i use a jjwt implementation instead of nimbous jwt?

  • @mayankgupta2543
    @mayankgupta2543 11 місяців тому

    Can we have multiple authentication manager configured for different purpose if yes then how?

  • @ngocanha85
    @ngocanha85 Рік тому +1

    Rename ProviderSettings -> AuthorizationServerSettings

  • @陈俏锋
    @陈俏锋 6 місяців тому

    I love this presentation! How to get the code and file on your presentation?

  • @yuyeyang4973
    @yuyeyang4973 2 роки тому +2

    Does JWT need to be stored on the server?

  • @mohamedibrahim1836
    @mohamedibrahim1836 Рік тому

    how the resource server knows this token is from the authorization server? minute 7:36 the diagram misses this point .

  • @testingdave7629
    @testingdave7629 Рік тому +2

    If I am going to user Redis to store token data, how do I create a filter that will fetch the token first on Redis before proceeding with the checking of JWT? I am planning to use Redis as a cache and Postgresql as the DB

  • @csvxmlfan3853
    @csvxmlfan3853 2 роки тому +2

    at the post request i'll always get {"error":"invalid_client"}, stackoverflow and github show solutions but only for version 0.2.. has someone an idea?

    • @csvxmlfan3853
      @csvxmlfan3853 2 роки тому +1

      Ahh ok, so of course postman has the role in this example of a public client as such the clientAuthenticationMethod has to be ClientAuthenticationMethod.NONE according to registeredClient documentation... So either Mr. Spilca changed it and did no show it or he used some other trick..

    • @victormartin6264
      @victormartin6264 2 роки тому +3

      @@csvxmlfan3853 the trick is the hidden Authorization tab in postman. Try adding --header 'Authorization: Basic Y2xpZW50OnNlY3JldA=='

    • @arsenmemetov5794
      @arsenmemetov5794 2 роки тому +6

      @CSVXML FAN, Víctor Martín is right, you have to pass client_id and client_secret using Authorization Header: In Postman's Authorization tab select 'Basic Auth' in 'Type' dropdown menu and then type client_id/client_secret in appeared Username/Password fields.

  • @fredzouza
    @fredzouza 2 роки тому +2

    Please can someone help me with the "code_challenge" i need to generate a SHA256 from any string like "anything" and in "code_verifier" i send "anything" ?

    • @jafajarvis324
      @jafajarvis324 Рік тому

      same question i have... if you find any solution please let me know

    • @jofrantoba
      @jofrantoba Рік тому

      public static void main(String[] args) throws NoSuchAlgorithmException {
      SpringApplication.run(Application.class, args);
      String codeVerifier=createCodeVerifier();
      log.info("code verifier:"+codeVerifier);
      log.info("code_challenge:"+createCodeChallenge(codeVerifier));
      }

      private static String createCodeChallenge(String value) throws NoSuchAlgorithmException {
      MessageDigest md = MessageDigest.getInstance("SHA-256");
      byte[] digest = md.digest(value.getBytes(StandardCharsets.US_ASCII));
      return Base64.getUrlEncoder().withoutPadding().encodeToString(digest);
      }

      private static String createCodeVerifier(){
      StringKeyGenerator secureKeyGenerator =
      new Base64StringKeyGenerator(Base64.getUrlEncoder().withoutPadding(), 96);
      return secureKeyGenerator.generateKey();
      }

  • @rakeshnukapeyyi5528
    @rakeshnukapeyyi5528 Рік тому

    Where is the code challenge being maintained in the spring backend to validate against the code verifier? If it is in memory, it will cause an issue every time the server is restarted. The authenticated public client might use the non-existent code verifier.

    • @jofrantoba
      @jofrantoba Рік тому

      public static void main(String[] args) throws NoSuchAlgorithmException {
      SpringApplication.run(Application.class, args);
      String codeVerifier=createCodeVerifier();
      log.info("code verifier:"+codeVerifier);
      log.info("code_challenge:"+createCodeChallenge(codeVerifier));
      }

      private static String createCodeChallenge(String value) throws NoSuchAlgorithmException {
      MessageDigest md = MessageDigest.getInstance("SHA-256");
      byte[] digest = md.digest(value.getBytes(StandardCharsets.US_ASCII));
      return Base64.getUrlEncoder().withoutPadding().encodeToString(digest);
      }

      private static String createCodeVerifier(){
      StringKeyGenerator secureKeyGenerator =
      new Base64StringKeyGenerator(Base64.getUrlEncoder().withoutPadding(), 96);
      return secureKeyGenerator.generateKey();
      }

  • @sergeybayramov1466
    @sergeybayramov1466 2 роки тому

    Is it possible and supported in current version to change formLogin to httpBasic?

  • @AnkitKumar-ow6fg
    @AnkitKumar-ow6fg Рік тому

    I loved the part where he mentioned about Log4J XD

  • @sadiulhakim7814
    @sadiulhakim7814 9 місяців тому

    I am getting error while using BCryptPasswordEncoder instead of NoOpPasswordEncoder. It says Encoded password does not look like BCrypt.

    • @xxxHipHopRap
      @xxxHipHopRap 8 місяців тому

      Did u fix it? I have the same problem but I want to use BCryptPasswordEncoder

    • @sadiulhakim7814
      @sadiulhakim7814 8 місяців тому

      @@xxxHipHopRap no

    • @xxxHipHopRap
      @xxxHipHopRap 8 місяців тому

      @@sadiulhakim7814 I fixed it doing this if u still need it:
      @Bean
      public RegisteredClientRepository registeredClientRepository() {
      BCryptPasswordEncoder passwordEncoder = new BCryptPasswordEncoder();
      RegisteredClient r1 = RegisteredClient.withId(UUID.randomUUID().toString())
      .clientId("myclient")
      .clientSecret(passwordEncoder.encode("secret"))........

  • @sabbirtanvir177
    @sabbirtanvir177 Рік тому

    why I am getting this error ?
    Error creating bean with name 'securityFilterChainAs' defined in class path resource

    • @sabbirtanvir177
      @sabbirtanvir177 Рік тому

      it is actually the Noclassdef error for OAuth2AuthorizationServerConfiguration , anyone to help?

    • @sabbirtanvir177
      @sabbirtanvir177 Рік тому

      ok, spring changes the version, oauth2-server 0.3.0 will not work with spring 3.0.0, I needed to change ti to 1.0.1 version. I don't know what will spring do tomorrow. :)
      Now i follow all steps, but found a response invalid_request. Huuh, i don't know about this error at all.

  • @mukendiemmanuel5640
    @mukendiemmanuel5640 2 роки тому +1

    i do the same configuration but when i try to get access token on /oauth2/token it return 404 not found exception

    • @kiranjawale8822
      @kiranjawale8822 2 роки тому

      Your issue resolved ?

    • @mukendiemmanuel5640
      @mukendiemmanuel5640 2 роки тому

      @@kiranjawale8822 yes the problem was in query params and the Authorization header

  • @dawidd6356
    @dawidd6356 2 роки тому +3

    Dude speaks like a MACHINE (nvm i had it on 1.25x)

  • @nico-s29
    @nico-s29 2 роки тому

    Helped me a lot thank you

  • @felipebedoyacastano8434
    @felipebedoyacastano8434 2 роки тому

    Thanks!

  • @farjallahhaythem5675
    @farjallahhaythem5675 2 роки тому

    the best

  • @arturolucas776
    @arturolucas776 2 роки тому

    amazing

  • @yuyeyang4973
    @yuyeyang4973 2 роки тому

    Is this the norm in actual development?

  • @jafajarvis324
    @jafajarvis324 Рік тому +1

    can anyone tell me how can i generate my own code chanllenge

    • @jafajarvis324
      @jafajarvis324 Рік тому

      I got answer. Its totally pkce. We can get it from online and generate our own pkce code

    • @nihmathaafiya9693
      @nihmathaafiya9693 Рік тому

      @@jafajarvis324 Hey, could you clarify how? It'll be really helpful, thanks

    • @jofrantoba
      @jofrantoba Рік тому

      public static void main(String[] args) throws NoSuchAlgorithmException {
      SpringApplication.run(Application.class, args);
      String codeVerifier=createCodeVerifier();
      log.info("code verifier:"+codeVerifier);
      log.info("code_challenge:"+createCodeChallenge(codeVerifier));
      }

      private static String createCodeChallenge(String value) throws NoSuchAlgorithmException {
      MessageDigest md = MessageDigest.getInstance("SHA-256");
      byte[] digest = md.digest(value.getBytes(StandardCharsets.US_ASCII));
      return Base64.getUrlEncoder().withoutPadding().encodeToString(digest);
      }

      private static String createCodeVerifier(){
      StringKeyGenerator secureKeyGenerator =
      new Base64StringKeyGenerator(Base64.getUrlEncoder().withoutPadding(), 96);
      return secureKeyGenerator.generateKey();
      }

  • @yuyeyang4973
    @yuyeyang4973 2 роки тому

    Can this example be used in actual development? A friend of mine said that this example has drawbacks. After the server restarts, everyone will be disconnected. Is that true?

    • @nick_bezverkhyi
      @nick_bezverkhyi 2 роки тому +2

      It can't be used, for the actual development you would probably want to use db instead of in-memory solution

    • @nick_bezverkhyi
      @nick_bezverkhyi 2 роки тому +1

      @Rendell Jay Eyas no, but should be pretty easy, just read the documentation

    • @khajalieubarrie5088
      @khajalieubarrie5088 Рік тому

      @Rendell Jay Eyas Check the speakers channel. Has an ongoing playlist on the subject

  • @gopal2598
    @gopal2598 Рік тому

    In 0.3.0 version is it supporting password grant ?