GCSE Required Practical: Rates of Reaction Part 1 - analysing graphs

[@med7756]

Thanks alot man.. You're really great. After I searched about 50 videos on UA-cam I couldn't understand. I only understood that from you because you're great thank you a lot

[@richardhiggins6471]

Glad you found it helpful.

[@med7756]

@@richardhiggins6471 You should be. But I'd like to ask you smth what if my triangle differs will the answer differ?

[@chemistrywithdrh6514]

@@med7756 .It doesn't matter how big a triangle you draw

[@chemistrywithdrh6514]

If you draw a triangle twice as big, the values of y and x will both be double, so the gradient will still be the same. It is difficult to draw a tangent that is exactly right, so the examiners always give you a margin of error of say 10% higher or lower.

[@mardinjordan8642]

this guy is a genius. its like he is a examiner thank you very much. better than freesicnelesson for sure

[@richardhiggins6471]

Thanks for your kind cmments. Good luck with the revision.

[@girl-wh8dv]

thank you soooo much i've been looking for an explanation!! :)

[@erhansukrucengiz5663]

Amazing lecture

[@allensamuel4630]

Thanks a lot dude u helped me understand it properly

[@gauravresearch8]

Amazingly well explained. Really great presentation. Explained very minute details. Thank you.

[@grandpaturtle5384]

how would you find a mean rate for the whole reaction

[@richardhiggins6471]

You would read the time from the graph when it has gone horizontal. This is when the reaction has finished. Then the average rate is the final volume of gas divided by this time. In the graph in this video the final volume of gas is 32 cm3 , and the reaction stops at 60 seconds, so the average rate is 32/60 = 0.533 cm3 per second.

[@KamFX]

good video, but ur mic is funny.

[@benvernon2800]

yes that's True!