At 5:38 , There is one small mistake made by me, There should be only S + (-1)**i / (2*i+1) but what I wrote is 1/ (-1)**i / (2*i+1) while writing code and I am sorry for that but we still get same answer right? Why? Because 1/(-1)^i and (-1)^i have same effect on plus and minus sign. So it's just don't matter whether you write 1/(-1)^i or (-1)^i both will be positive for even values of i and negative for odd values of i. 00:09 Intro 00:30 Leibniz's Pie Formula 00:56 3b1b's Animation 1:48 Algorithm 4:12 Algorithm in work 5:27 coding part Don't forget to read description ! Thanks for watching ✌️
At 5:38 , There is one small mistake made by me, There should be only S + (-1)**i / (2*i+1) but what I wrote is 1/ (-1)**i / (2*i+1) while writing code and I am sorry for that but we still get same answer right? Why?
Because 1/(-1)^i and (-1)^i have same effect on plus and minus sign. So it's just don't matter whether you write 1/(-1)^i or (-1)^i both will be positive for even values of i and negative for odd values of i.
00:09 Intro
00:30 Leibniz's Pie Formula
00:56 3b1b's Animation
1:48 Algorithm
4:12 Algorithm in work
5:27 coding part
Don't forget to read description !
Thanks for watching ✌️
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