Partial Fractions - Denominator with quadratic factors | SHS 1 ELECTIVE MATH

[@Voy2k23]

After watching 5 unhelpful videos , this one really helped me. ThANK YOU MAN.

[@SkanCityAcademy_SirJohn]

You are most welcome

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[@SkanCityAcademy_SirJohn]

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[@SkanCityAcademy_SirJohn]

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[@SkanCityAcademy_SirJohn]

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[@SkanCityAcademy_SirJohn]

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[@SkanCityAcademy_SirJohn]

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[@SkanCityAcademy_SirJohn]

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[@SkanCityAcademy_SirJohn]

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[@thertzejun1178]

Thankyouuuuu I had been hopeless the entire day becuz of partial fraction and this vid literally saved my life

[@SkanCityAcademy_SirJohn]

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[@thertzejun1178]

@@SkanCityAcademy_SirJohn I found you when I searched partial fractions with quadratic factors

[@SkanCityAcademy_SirJohn]

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[@SkanCityAcademy_SirJohn]

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[@mayarmohamed1103]

Amazing🎉

[@VijaySingh-kp9dg]

How to calculate B and C if we don't have quadratic equations on the RHS

[@efeoghene1622]

Hello. I have a similar problem regarding this partial fraction with a quadratic denominator. Can i send you the question so you could help out ?

[@OLIVIAKabo-od6wn]

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[@SkanCityAcademy_SirJohn]

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[@MARVELOUSAWOBAJO-vy1cm]

Thank u so much for this video it was really helpful

[@SkanCityAcademy_SirJohn]

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[@SkanCityAcademy_SirJohn]

Thanks

[@resiniabeysekera3961]

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[@SkanCityAcademy_SirJohn]

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[@kamalisathish7347]

Amazing

[@SkanCityAcademy_SirJohn]

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[@cappmasters7253]

You video is useful thank you sir

[@SkanCityAcademy_SirJohn]

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[@SkanCityAcademy_SirJohn]

You are most welcome. Thanks for watching as well

[@comfortessandor9646]

Wow. thanks so much sir

[@SkanCityAcademy_SirJohn]

You are most welcome. All the best in your academics

[@EkuaAmponsah-wj2dg]

Love your method Nice

[@SkanCityAcademy_SirJohn]

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[@SkanCityAcademy_SirJohn]

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Watching it in August 😂

[@SkanCityAcademy_SirJohn]

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[@IllustriousProfessional]

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[@SkanCityAcademy_SirJohn]

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[@SkanCityAcademy_SirJohn]

Most welcome.
Thanks for watching

[@gyanendrakumal2997]

Is this method always correct?

[@SkanCityAcademy_SirJohn]

Yes, except that the question type is different

[@abdullah4759]

What if numerator is only a single number with no x^2? Then how do you compare

[@SkanCityAcademy_SirJohn]

You will still use the same approach, just that this time the LHS will be equal to 1, and you try to eliminate two constants in each step to find the other constant

[@abdullah4759]

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[@SkanCityAcademy_SirJohn]

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[@SkanCityAcademy_SirJohn]

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[@SkanCityAcademy_SirJohn]

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[@SkanCityAcademy_SirJohn]

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[@Oreki758]

Great explanation buddy anyways where are you from? Are you from Nigeria ?

[@SkanCityAcademy_SirJohn]

Thanks so much. I'm from Ghana

[@Tastygarden1]

I have a question. Why we put the denominator linear factor equal to zero. Even when we let the denominator equal to 0 the whole expression will become undefined. And why not we put the quadratic factor equal to zero. Please reply me as soon as possible. Thanks.

[@SkanCityAcademy_SirJohn]

Hello, the idea is always to eliminate two constants and have only one constant remaining at a time.
Can you come again with your question. I don't really get you.

[@Tastygarden1]

the question is that when we let the denominator factor =0. What is the logic how could we let it =0. please answer me. it is very urgent.@@SkanCityAcademy_SirJohn

[@SkanCityAcademy_SirJohn]

Is it a general question, or a question from my video, if it's a question from my video, please state the time in the video.

[@janeshnair9452]

Thank you so muchhh

[@SkanCityAcademy_SirJohn]

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[@freshkidotv8550]

So great

[@SkanCityAcademy_SirJohn]

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[@Yeurtt_x1]

Sir please I want to make similar vidoes but I don't know how to start

[@SkanCityAcademy_SirJohn]

Just prepare and start

[@user-il9wn7rl3j]

7:01 can somebody explain why it's -2 instead of 2? Bcs earlier he puts x equal to 2???

[@SkanCityAcademy_SirJohn]

In finding the value of c, we want to compare coefficient of x, we have expressions with x attached as ' Cx - 2Bx' = -3x.
From the LHS, coeefifcent of x is -2B, that's where the negative comes from.

[@PortiaAuntie-rt2dd]

Please what if the numerator is not a quadratic equation

[@SkanCityAcademy_SirJohn]

Kindly explain further, do you mean if you have an improper fraction?

[@chibuchinwachukwu2342]

Thanks u sir

[@SkanCityAcademy_SirJohn]

Most welcome

[@fairuzmalihamaya9976]

thanks, sir

[@SkanCityAcademy_SirJohn]

You are welcome

[@LORDSHREERAM108]

4:21 Bro 5(2)² - 3(2) - 4 = 10 not 18

[@SkanCityAcademy_SirJohn]

It's +4 not -4.

[@LORDSHREERAM108]

Thankyou to correct my mistake and your quick reaponse

[@avatarthanos-u5r]

thank you

[@SkanCityAcademy_SirJohn]

You are welcome

[@osasuruth1207]

Sir what about this question 2x^2+3x+10/(x+1)(x+2)

[@SkanCityAcademy_SirJohn]

For this question, you will use the improper fraction method.
After the long division you will get
2 + (-3x + 6)/(x+1)(x+2)
Hence you work of the term on the right hand side
A /( x+ 1) + B / (x + 2).
You will get A = 9 and B = -12.
Finally you have the decomposition to be
2 + 9/(x+1) - 12/(x+2)
Sorry for the late reply

[@osasuruth1207]

Thank you and there's no problem sir

[@SkanCityAcademy_SirJohn]

@osasuruth1207 you are welcome, which school do you attend?

[@ZainArtz]

final answer is covered by end title

[@SkanCityAcademy_SirJohn]

okayy

[@clifendyemilien6527]

😎😎

[@nolanminev2064]

How do you even get 5x^2-3x+4 it seems so out of nowhere like he just wrote it down and I couldn’t follow

[@SkanCityAcademy_SirJohn]

Can you explain further ?

[@samisamby8044]

it's the numerator of the original function that he chose for the example.

[@RachealDestiny]

Aweh things are complicated

[@aadik07]

Why are you making it harder and explaining it ??? We can take X= 0 and find C ? LOL

[@SkanCityAcademy_SirJohn]

Thanks for your contribution.

[@atlanticschool1367]

So that i can understand it in detail

[@amnanaqvi7073]

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[@SkanCityAcademy_SirJohn]

Okay. Thank you

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[@SkanCityAcademy_SirJohn]

Great