Steel Design L6E| LSM| Beams | Design of beam for Shear only | Low Shear | Numerical Problem | Hindi

[@anand4236]

Beauty with brain very rare combination in civil engineering department 🤗🤗🤗

[@civilengg.withakriti2556]

Thank you

[@rajupoddar4386]

Maam your lecture it's so nice
After watching this i solve all beam design related problem
Everyone said that DSS is very tough subject in civil engineering but after watching your lecture vi think this is very easy for me and
Thank you so much ❤️❤️❤️❤️

[@civilengg.withakriti2556]

You're welcome 😊

[@SouvikCivil]

Ohh....thanks sir ...i was waiting for This topic only....

[@civilengg.withakriti2556]

🙏🏽

[@rajiitb]

love from IITB❤❤.....just a day before exam and getting concepts crystal clear...😊

[@civilengg.withakriti2556]

All the best

[@rishabhsoni3235]

Really helpfull and easy to understand, Thankyou Mam.

[@civilengg.withakriti2556]

Keep watching

[@vishalsinghdhamiak47]

Best teacher Happy Guru Purnima

[@civilengg.withakriti2556]

Thank you 😊

[@suyashsharnagat2912]

A huge thanks to you mam !!!

[@civilengg.withakriti2556]

🙏🏽

[@subrataghosh7026]

Thank you so much mam....very nice contribution for us 💕

[@civilengg.withakriti2556]

🙏🏽

[@gouravchouhan7504]

Thanku so much. You help me a lot

[@civilengg.withakriti2556]

You're welcome 😊

[@urendrarahangdale2003]

Thanks for sharing video

[@civilengg.withakriti2556]

My pleasure

[@Super-lj1rf]

crystal clear,thanks again!!

[@civilengg.withakriti2556]

You’re welcome

[@kamsanichandu4195]

Madam, why we are doing 1.5 for loads (are when we do ) we have do for any problem like this only while load is given ? { Plz answer this question

[@civilengg.withakriti2556]

1.5 is a factor used to obtain the design load from the service load. It helps us to design for a higher load so that in case the load increases during its lifetime the structure doesn't fail.

[@SanjeevKumar-mr7sj]

Really very helpful mam ☺️

[@civilengg.withakriti2556]

Thanks a lot

[@kamsanichandu4195]

Beautiful explaintion

[@civilengg.withakriti2556]

Thank you 😊

[@mazharkhan9229]

please continue classes , please

[@jeevanthagunna4390]

great mam thank you so much❤️

[@civilengg.withakriti2556]

🙏🏽

[@thehp33vlogger35]

Mam agr hme factored uniformly distributed load diya ho or unit usne kN/m ho to usse bhi 1.5 se multiply krege

[@saketsaurabh9776]

Nhi...agr fatored nhi diya ho to hi 1.5 se multiply krenge....

[@Gaurav428m]

Mam aap konsi book se pdate hai because hmari mam hume section ke self weight ko bhi include krti hai moment or shear force me

[@civilengg.withakriti2556]

S. K. Duggal and NPTEL Lectures

[@gauravchauhan3857]

Mam how to find moment of inertia Izz u have to directly write in question properties please reply

[@civilengg.withakriti2556]

You can obtain the value of Moment of inertia from the steel table for rolled sections

[@abidibadatali5367]

ISLB 550@846N/M
isme steel table me hum logo ku dikhta hai magar 846N/m kaise malum hota hai, 86.3 hai kg/m ka value. Plz reply

[@civilengg.withakriti2556]

846 N/m divided by 9.81 m/s² = 86.4 kg /m.

[@civilengg.withakriti2556]

Simply divide the value by Acceleration due to gravity

[@sonusoodh1094]

Mam ISLB 550 @846 lena ha ye samajh aagya mam lekin 846 kha se aaya

[@civilengg.withakriti2556]

Check the steel table for ISLB 550 there you will find the value 846

[@nematullahshaikh8048]

Gama m not ka value 1.1 kaise aaya mam

[@Allinone-fp7bb]

Thankyou mam.

[@civilengg.withakriti2556]

Welcome 😊

[@richooberhanu7914]

Good

[@civilengg.withakriti2556]

Thanks

[@intresting8355]

DETERMINE THE Design bENDING STRENGTH OF ISLB350@486 N/M considering the beam to be lateralLY UNSUPPORTED THE DESIGN SHEAR FORCE IS LESS THAN THE DESIGN OF SHEAR STRENGTH UNSUPPORETED LENGTH OF THE BEAM IS 3M ASSUME STEEL OF GRADE FE410 MAM CAN U POST THIS QUESTION MAM?

[@nillionaire.]

Watching in 2023🙃

[@civilengg.withakriti2556]

Great