Lecture 10/65: Equivalence of Regular Expressions and Regular Languages

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  • Опубліковано 7 січ 2025

КОМЕНТАРІ • 18

  • @rj-nj3uk
    @rj-nj3uk 5 років тому +5

    People like you needs to live long.

  • @perjespersen4746
    @perjespersen4746 5 років тому +2

    He is really good. Perfect mix of formalism and examples

  • @esraasaad1281
    @esraasaad1281 6 років тому +1

    By far the best professor i have seen that explained theory of computation! Thank you for your great efforts you helped me ace the material for my test !

  • @356379783
    @356379783 9 років тому +10

    love the way you use small steps to build up the whole thing

  • @josemunguia5660
    @josemunguia5660 6 років тому +1

    Prof. Harry, you're awesome. Thanks for sharing your knowledge!

  • @vladmihaila4654
    @vladmihaila4654 10 місяців тому

    I believe there is a mistake at 33:34. The c state is missing a transition for the letter 2, so the machine is a NFA rather than a DFA.

  • @JeremyFBlack
    @JeremyFBlack 3 роки тому

    This is a work of art!

  • @marcuskielman1272
    @marcuskielman1272 5 років тому +1

    Sir, you have taken a course that I’ve started to absolutely despise with a passion, and make it interesting

    • @hhp3
      @hhp3  5 років тому +1

      Thank you so much!

  • @qwertyuiop-ke7fs
    @qwertyuiop-ke7fs 8 років тому +5

    This one was long but everything was clear. It did not seem like 40 minutes at all. Thanks.

  • @pratikwaikar2538
    @pratikwaikar2538 8 років тому +1

    You are a Saviour !!

  • @suyziljackson8202
    @suyziljackson8202 2 місяці тому

    Can a DFA have multiple symbols over a single transition??? 20:59

  • @jordanlayton6540
    @jordanlayton6540 7 років тому

    i love this man

  • @melekhine
    @melekhine 5 років тому +3

    Of all the Theory of Computation videos on youtube, this series is the best. But in this video in particular, there is a serious error.
    The diagram he points to at 29min 13sec is very misleading. The previous diagram had self transitions on these states. Where did they go? The diagram also misrepresents the situation when i = j when it would look very different.
    The statements he makes at 28min 46sec and 30min 3sec are incorrect. Not only the red edges matter. Strictly speaking, the transition from i to j is replaced by the transition from i to i then i to j then j to j. Leaving this subtlety out just saves writing and later simplifying except for the case when i = j when it will result in an incorrect regular expression.
    Like he correctly states, all edges must be modified. At 30min 58sec he reiterates this by mentioning literally every edge in the graph that must be modified but leaves out the self transition edges! This method will not in general produce the correct regular expression unless the self transitions are modified.
    The path i to i can also be made i to i (R5), i to rip (R1), rip to rip (R2), rip to i (R6), i to i (R5). So R5 must be replaced by (R5)*(R1)(R2)*(R6)(R5)*.

    • @jeff_kola
      @jeff_kola 4 роки тому

      Thanks for this explanation, can you point to any examples when i=j. I was under the illusion that each state would be distinct.

  • @debayondharchowdhury3001
    @debayondharchowdhury3001 4 роки тому

    Prof. Harry Potter

  • @romansmirnov3351
    @romansmirnov3351 8 років тому +2

    Professor Harry Potter