Well done. There is a fifth concept using this idea that is worth mentioning... The box is fully submerged in the water, and floating mid-water without a string. Not only will both scales record the same weight, the box can also be determined that it has the same weight per volume as the water... in other words, the same density as the water.
would love to see more puzzle videos like this and also could you make videos for thermodynamics and KTG on khan academy! Previous sal videos are way too old on these concepts
Since the depth is the same, the water exerts the exact same amount of downward pressure on the beak. The only difference is whether another factor exerts a vertical force on the beak
The tricky part of these questions for me comes when the water level is not kept equal. For example when lowering the lead box on the string into the water, then water is displaced by the box so the water level rises. Ok so in that case I believe now it weighs more. The rectangle of higher density lead plus the two rectangles of water now on the sides of the beaker compared to the left side. Correct? Then there is the tricky question often posed, that if an ice cube is floating in the beaker, and the water level is kept constant then again the beaker on the right is lighter because it is like the example of that box that wanted to float up but is held down by the string. Lower density area is displaced but removed to keep the water level constant so weight goes down. But if the water with the ice in it is allowed to rise when we float an ice cube on top then the weight would be equal. Then to take it one step further, if the ice now melts the water volume it was displacing disappears as if we just pulled the ice cube out. Ignoring the ice melting into the water, if we wanted to keep the water level equal then the volume of displaced water the ice was taking up would have to be replaced with water. So we would have to add water. But if don’t ignore the ice melting into the beaker so it is no longer like we pulled it out. What happens to the level of water?
Sir in first question can we think that because the mass is floating its apparent weight os zero and therefore there wont be any weight of the block acting on the fluid
I have a doubt which has been stuck on mind for a long time, How does the depletion layer shrink in the forward bias thus causing the current to flow? I know that if we forward bias the junction Electrons which were in the N side tend to recombine with the holes in the P side passing through the depletion layer. But if they recombine with the holes in the P side then the entire trivalent atom becomes negatively charged causing the further expansion of the depletion (Also since the electron left it's pentavalent atom it has become positive now too). Now there will be a new junction potential created where the electrons get repelled by it. I have watched the mechanism of the forward bias which you have demonstrated in Khan Academy, but still I don't seem to get this, also can you explain this in terms of electrons motion and not the holes.
Good Morning sir In case 4, I was able to answer it correctly, but after watching the solution just got a little confused as to why the tensions don't cancel. Understood the string tends to make it lighter but then doesn't the box tend to make the system heavier? Sir, was just thinking now, is it because every time the box pulls down, an equal amount of water has to be removed to maintain the equal level condition given in the question? Thank you sir
The box would've made the system heavier if it was allowed to exert a force on it⬇️ Turns out , the string has taken half of its power💪 It can only exert 2 kg force on it The rest 3kg is balanced by the string↕️
The mass with less mass suffers more becuz due to its less mass while collision it comes to rest very fast The force acting in them will be same becuz Newton third law F=constant m>M Therefore F/m>F/M So small trick will suffer great damage
Easy lil bro. Box is halfway in the water so it’s half as dense. Now you can just compress the top half of the crate to the bottom one and get something that’s as dense as water with the same volume. Kindergarden
How did Kepler came into the conclusion that , "When the force is acting towards the centre planets will cover equal areas in equal time" In your previous video you told us directly that those 2 triangles will have equal areas! What's the reason behind that?
The last part was amazing😮
Well done. There is a fifth concept using this idea that is worth mentioning... The box is fully submerged in the water, and floating mid-water without a string. Not only will both scales record the same weight, the box can also be determined that it has the same weight per volume as the water... in other words, the same density as the water.
would love to see more puzzle videos like this and also could you make videos for thermodynamics and KTG on khan academy!
Previous sal videos are way too old on these concepts
Wow found new way to think for fuild mechanics❤️
AS ALWAYS, YOUR TEACHING IS AMAZING
Very Good Morning Mahesh Ji ,as usual the best and unique performance....
Can you teach Rotational Motion for IIT JEE please only one chapter
If you could it'll be very helpful!!
Since the depth is the same, the water exerts the exact same amount of downward pressure on the beak. The only difference is whether another factor exerts a vertical force on the beak
I love physics 😘😘😘😘🥰🥰🥰🥰
Epic video big fan of you. Patrick kilian sir also has so much in common with u... The way u explain things
I don’t know who that person is!
@@Mahesh_Shenoy sir Petschge is a plasma physicist who spends a load of time helping others in the physics server
@@Mahesh_Shenoy yes petschge has so much in common with u sir...can u do a podcast with him lol
The tricky part of these questions for me comes when the water level is not kept equal. For example when lowering the lead box on the string into the water, then water is displaced by the box so the water level rises. Ok so in that case I believe now it weighs more. The rectangle of higher density lead plus the two rectangles of water now on the sides of the beaker compared to the left side. Correct? Then there is the tricky question often posed, that if an ice cube is floating in the beaker, and the water level is kept constant then again the beaker on the right is lighter because it is like the example of that box that wanted to float up but is held down by the string. Lower density area is displaced but removed to keep the water level constant so weight goes down. But if the water with the ice in it is allowed to rise when we float an ice cube on top then the weight would be equal.
Then to take it one step further, if the ice now melts the water volume it was displacing disappears as if we just pulled the ice cube out. Ignoring the ice melting into the water, if we wanted to keep the water level equal then the volume of displaced water the ice was taking up would have to be replaced with water. So we would have to add water. But if don’t ignore the ice melting into the beaker so it is no longer like we pulled it out. What happens to the level of water?
Good video. I got a question for you though. Would you know the equation of archimedes principle before newton came up with gravity?
Can you make more videos on Intuitions i like them a lot.
Would you make us a new video on magnetic inductance specialy how the inductors store energy ,please!
Check out khan academy video! I have it there :)
Woww thank u so much. What is the name for the website that u used to get these questions?
if the box were full of uranium then the right side weighs more otherwise you can't tell for the most part (if the box is sunk)
Sir in first question can we think that because the mass is floating its apparent weight os zero and therefore there wont be any weight of the block acting on the fluid
Hi, please 11th physics videos on khan academy
I have a doubt which has been stuck on mind for a long time,
How does the depletion layer shrink in the forward bias thus causing the current to flow?
I know that if we forward bias the junction
Electrons which were in the N side tend to recombine with the holes in the P side passing through the depletion layer. But if they recombine with the holes in the P side then the entire trivalent atom becomes negatively charged causing the further expansion of the depletion (Also since the electron left it's pentavalent atom it has become positive now too). Now there will be a new junction potential created where the electrons get repelled by it.
I have watched the mechanism of the forward bias which you have demonstrated in Khan Academy, but still I don't seem to get this, also can you explain this in terms of electrons motion and not the holes.
Good Morning sir
In case 4, I was able to answer it correctly, but after watching the solution just got a little confused as to why the tensions don't cancel. Understood the string tends to make it lighter but then doesn't the box tend to make the system heavier?
Sir, was just thinking now, is it because every time the box pulls down, an equal amount of water has to be removed to maintain the equal level condition given in the question?
Thank you sir
The box would've made the system heavier if it was allowed to exert a force on it⬇️
Turns out , the string has taken half of its power💪
It can only exert 2 kg force on it
The rest 3kg is balanced by the string↕️
se
How was the "1 coulomb" determined?🤔 Plz 🙏🏻 reply sir
1 Coulomb was defined as 1 amp second
Off-topic.
Sir, I have a question on momentum and kinetic enegry.
A truck of mass 4000 kg and having a velocity 20 m/s collides with another truck of mass 13000 kg. which truck will be damaged more?? How do I show mathematically (It's very impotant)??
© level class -10 (from Bangladesh)
The mass with less mass suffers more becuz due to its less mass while collision it comes to rest very fast
The force acting in them will be same becuz Newton third law
F=constant
m>M
Therefore F/m>F/M
So small trick will suffer great damage
Easy lil bro. Box is halfway in the water so it’s half as dense. Now you can just compress the top half of the crate to the bottom one and get something that’s as dense as water with the same volume. Kindergarden
How did Kepler came into the conclusion that ,
"When the force is acting towards the centre planets will cover equal areas in equal time"
In your previous video you told us directly that those 2 triangles will have equal areas!
What's the reason behind that?
I have shown how in that video, no
It's NOT 2 kg. It's 2 kg force!!! Get your units right!
I don’t agree with the last one😭. Shouldn’t it be lighter😭