Answer is 5 .. As 91 is not prime but it's factors are prime 13 and 7 . So if individually divide 555555.. by 13 and 7 using the same trick as mentioned by sir .we can find the remainder as 5 only
In simple terms, 115 can be written in aaaaaa format as 6×19 = 114, so only one 5 is remaining out of 115 times divided by 91. hence it's the reminder.
Thank you sir
Grateful for this series
Answer b) 5 ..... Tysm sir
Thank you sleep classes for providing CSAT series.....🙏🙏
Thankyou very much sir for this amazing session
Answer -5 ,nice lecture , very thankyou, sir.
Big thank you sir please continue this series :')
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Thank you sir 😊
B is the right answer sir
Ans is B (5)
Option B
Opption C
Plz mention the right answer
Thanku sir
I need more formula tricks to understand sir
I am not getting exact answers.
Keep watching..
15 and thanku so much sir
How u got 15 answer?
@@shrutiishar1280its 5 .. 55/25 = 5 remainder
5
🅱️ is answer
B
Option B will be correct answer
Sir nahi Samajh m aaya
Answer is 5 ..
As 91 is not prime but it's factors are prime 13 and 7 .
So if individually divide 555555.. by 13 and 7 using the same trick as mentioned by sir .we can find the remainder as 5 only
Can you please show me the solution.....
How remainder 5 left if we divide individually. Both no's are dividing completely so no remainder is remaining.
In simple terms, 115 can be written in aaaaaa format as 6×19 = 114, so only one 5 is remaining out of 115 times divided by 91. hence it's the reminder.
@@yerrashivani6731 ok thank you finally cleared 👍
I think 15
555555/91= 0
55555.....114 times divisible
Left only 5 answer b
How u get ur answer 5. Will u explain because I m finding the remainder 0.
5