Sampling distribution of sample proportion part 1 | AP Statistics | Khan Academy
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- Опубліковано 7 вер 2024
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Formulas for the mean and standard deviation of a sampling distribution of sample proportions.
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shouldn't the last calculation of sigma-phat being sigmaX divided by the sqrt of n?
Mu (x) = n1*p - where n1 is the number of objects in the trial (10 in this case)
if no. of trials in X = n2
Mu(p^) should be = n2* (n1 * p) / n2
very hard to follow... continuous pattern
you're supposed to divide it by n
Thank you so much!
Why is no one capable of explaining this topic in a simpler way and then adding all this complex bull shit’s meaning at the end. Just the concept, seriously??
Have u found someone that explains this in a normal way bc. I’m struggling sm with stats
awesome video! thank you!
Only me feelling the explanation is confusing? I prefer the way Patrick teaches.
The whole subject is a bit confusing and explaining it might be tricky.
Can I ask?
Does the sampling distribution of proportions normally distributed?
If np(1-p) greater than or equal 10 than sample distribution of propotion normally distributed
Thank you.
I'm concerned how I'm seeing orange gumballs.
the last part of finding the mean and standard deviation for the sampling distribution of sampling proportion isn't explained well. That's why it is a dislike from me
Sorry what about this ( a random sample of 10,000 is taken from a population that is known to be 10% defective. Find the probability that less than 1,000 are found defective.
This video is an L for Khan academy
fr
Thanks
THIS TOLD ME NOTHING
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hi
Khan maths is too hard shoot a video to make it easier XD
i didn't like it
why can't you just solve the problem without explaining it and then doing an explanation