at 10:24 , in denominator [s+(alpha + beta)][s+(alpha - beta)] thana mam varanum, because if we simply that we get s^2 +(R/L)s + 1/LC.....but in your's [s-(alpha + beta)][s-(alpha - beta)].....
in the case i'm taking alpha = R/2L instead of -R/2L, Can i take alpha = R/2L an proceed mam? is there will be any problem?? i will change all equations with '+' sign..... eg like this [s+(alpha + beta)][s+(alpha - beta)]....
8:56 1/2 square root ulla pona 1/4 agiduma..mam
Yes ma
Thank you so much mam ❤
Thanks mam....
Thank you mam
Thank you for your explanation mam .
Your are doing a great job mam,I will understand the concept about this topic
at 10:24 , in denominator [s+(alpha + beta)][s+(alpha - beta)] thana mam varanum, because if we simply that we get s^2 +(R/L)s + 1/LC.....but in your's [s-(alpha + beta)][s-(alpha - beta)].....
in the case i'm taking alpha = R/2L instead of -R/2L,
Can i take alpha = R/2L an proceed mam? is there will be any problem??
i will change all equations with '+' sign.....
eg like this [s+(alpha + beta)][s+(alpha - beta)]....
Awesome explanation mam. Thank you mam